ÌâÄ¿ÄÚÈÝ

£¨6·Ö£©£¨1£©¡¢½«CO¡¢O2ÖÖÆøÌå·Ö±ðÊ¢·ÅÔÚ2¸öÈÝÆ÷ÖУ¬²¢±£³Ö2¸öÈÝÆ÷ÄÚÆøÌåµÄζȺÍÃܶȾùÏàµÈ£¬Õâ2ÖÖÆøÌå¶ÔÈÝÆ÷±ÚËùʩѹǿµÄ´óС¹ØϵÊÇ               ¡£
£¨2£©¡¢Í¬Î¡¢Í¬Ñ¹ÏÂijƿ³äÂúO2ʱÖØ116¿Ë£¬³äÂúCO2ÖØ122¿Ë£¬³äÂúijÆøÌåʱÖØ114¿Ë¡£ÔòijÆøÌåµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª                       ¡£
£¨3£©¡¢AÎïÖÊ°´ÏÂʽ·Ö½â£º2A=B¡ü+2C¡ü+2D¡ü£¬²âµÃÉú³ÉµÄ»ìºÏÆøÌåÔÚÏàͬÌõ¼þϵÄÃܶÈÊÇH2ÃܶȵÄm±¶£¬ÔòAµÄĦ¶ûÖÊÁ¿Îª                       ¡£
£¨1£©CO>O2  (2)  28  (3)  5 m  g/mol  (¸÷2·Ö)
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø