ÌâÄ¿ÄÚÈÝ
£¨1£©(8·Ö) ijÎÞɫ͸Ã÷ÈÜÒº¿ÉÄÜ´æÔÚNa£«¡¢Fe3£«¡¢Ba2£«¡¢NO3£¡¢CO32£¡¢HCO3£¡¢SO42£Öеļ¸ÖÖÀë×Ó£¬ÏÖÓÐÈçϲÙ×÷£º
¢ñ¡¢È¡ÊÊÁ¿¸ÃÈÜÒº¼ÓÈëCaCl2ÈÜÒºÎÞ³Áµí£¬¼ÌÐøµÎ¼ÓÑÎËá²úÉúÎÞÉ«ÎÞζµÄÆøÌå¡£
¢ò¡¢ÁíÈ¡¸ÃÈÜÒºµÎ¼ÓÒ»¶¨Á¿µÄNaOHÈÜÒºÓа×É«³ÁµíÉú³É¡£
ÊԻشðÏÂÁÐÎÊÌ⣺
¢Ù ¸ÃÈÜÒºÖÐÒ»¶¨´æÔÚµÄÀë×ÓÓÐ__________£¬Ò»¶¨²»´æÔÚµÄÀë×Ó__________¡£
¢Ú ÓÃÒ»¸öÀë×Ó·½³Ìʽ±íʾ²Ù×÷¢ÚµÄʵÑéÏÖÏó£º
______________________________________________________¡£
£¨2£©£¨4·Ö£©ÏÂÁи÷ÏîÖеÄÁ½ÖÖÎïÖÊÔÚÈÜÒºÖеķ´Ó¦£¬¿ÉÓÃͬһÀë×Ó·½³Ìʽ±íʾµÄÊÇ£¨ £©£¬Çëд³ö¸ÃÀë×Ó·´Ó¦·½³Ìʽ£º_____________________________________________¡£
¢ñ¡¢È¡ÊÊÁ¿¸ÃÈÜÒº¼ÓÈëCaCl2ÈÜÒºÎÞ³Áµí£¬¼ÌÐøµÎ¼ÓÑÎËá²úÉúÎÞÉ«ÎÞζµÄÆøÌå¡£
¢ò¡¢ÁíÈ¡¸ÃÈÜÒºµÎ¼ÓÒ»¶¨Á¿µÄNaOHÈÜÒºÓа×É«³ÁµíÉú³É¡£
ÊԻشðÏÂÁÐÎÊÌ⣺
¢Ù ¸ÃÈÜÒºÖÐÒ»¶¨´æÔÚµÄÀë×ÓÓÐ__________£¬Ò»¶¨²»´æÔÚµÄÀë×Ó__________¡£
¢Ú ÓÃÒ»¸öÀë×Ó·½³Ìʽ±íʾ²Ù×÷¢ÚµÄʵÑéÏÖÏó£º
______________________________________________________¡£
£¨2£©£¨4·Ö£©ÏÂÁи÷ÏîÖеÄÁ½ÖÖÎïÖÊÔÚÈÜÒºÖеķ´Ó¦£¬¿ÉÓÃͬһÀë×Ó·½³Ìʽ±íʾµÄÊÇ£¨ £©£¬Çëд³ö¸ÃÀë×Ó·´Ó¦·½³Ìʽ£º_____________________________________________¡£
A£®ÑÎËáºÍÉÕ¼îÈÜÒº¡¢ÁòËáºÍÇâÑõ»¯±µÈÜÒº |
B£®´¿¼îÈÜÒººÍÑÎËᡢʯ»ÒʯºÍÁòËá |
C£®ÂÈ»¯±µÈÜÒººÍÁòËáÄÆÈÜÒº¡¢ÏõËá±µÈÜÒººÍÁòËá |
D£®Ì¼Ëáï§ÈÜÒººÍÇâÑõ»¯ÄÆÈÜÒº¡¢Ì¼Ëáï§ÈÜÒººÍÇâÑõ»¯¸ÆÈÜÒº |
(10·Ö) £¨2·Ö/¿Õ£©
(1)¡¢¢Ù Ba2£«¡¢HCO3£¡¡¡¡¡¡Fe3£«¡¢CO32£¡¢SO42£
¢Ú Ba2£«+ HCO3£+ OH£= BaCO3¡ý+ H2O£»
»òBa2£«+ 2HCO3£+ 2OH£= BaCO3¡ý+ CO32£+ 2H2O
£¨2£©¡¢C Ba2£«+ SO42£= BaSO4¡ý
(1)¡¢¢Ù Ba2£«¡¢HCO3£¡¡¡¡¡¡Fe3£«¡¢CO32£¡¢SO42£
¢Ú Ba2£«+ HCO3£+ OH£= BaCO3¡ý+ H2O£»
»òBa2£«+ 2HCO3£+ 2OH£= BaCO3¡ý+ CO32£+ 2H2O
£¨2£©¡¢C Ba2£«+ SO42£= BaSO4¡ý
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿