ÌâÄ¿ÄÚÈÝ

ijÓлúÎïAÊÇÌþµÄº¬ÑõÑÜÉúÎΪ²â¶¨Æä×é³ÉÓÐÈçÏÂʵÑé½á¹û£º
¢ÙÔÚÒ»¶¨Î¶ȺÍѹǿϽ«AÆû»¯£¬ÆäÖÊÁ¿ÊÇͬΡ¢Í¬Ñ¹ÏÂÇâÆøÖÊÁ¿µÄ76±¶£»
¢Ú³ÆÈ¡7.6gÓлúÎïA£¬ÔÚ¹ýÁ¿ÑõÆøÖÐÍêȫȼÉÕ£®½«·´Ó¦ºóµÄ»ìºÏÆøÌåͨ¹ý×ãÁ¿Å¨H2SO4ºóÌå»ý±äΪ10.64L£¬Å¨ÁòËáÔöÖØ3.6g£®ÔÙ½«ÓàϵÄÆøÌåͨ¹ýÊ¢ÓÐ×ãÁ¿¼îʯ»ÒµÄ¸ÉÔï¹Ü£¬ÆøÌåÌå»ý¼õÉÙÖÁ1.68L£¨ÆøÌåÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©£®
£¨1£©È·¶¨AµÄ·Ö×Óʽ£®
£¨2£©ÈôAÎïÖÊÓöFeCl3ÈÜÒºÎÞÏÔÉ«·´Ó¦£®ÊÔÈ·¶¨AµÄ½á¹¹¼òʽ£¨Ð´Ò»ÖÖ¼´¿É£©£®
·ÖÎö£ºÔÚÒ»¶¨Î¶ȺÍѹǿϽ«AÆû»¯£¬ÆäÖÊÁ¿ÊÇͬΡ¢Í¬Ñ¹ÏÂÇâÆøÖÊÁ¿µÄ76±¶£¬ÔòAµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ152£¬7.6gÓлúÎïAµÄÎïÖʵÄÁ¿ÊÇ0.05mol£®Å¨ÁòËáÔöÖØ3.6g£¬Ôò·´Ó¦ÖÐÉú³ÉµÄË®µÄÖÊÁ¿ÊÇ3.6g£¬ÎïÖʵÄÁ¿µÄÊÇ0.2mol£®ÔÙ½«ÓàϵÄÆøÌåͨ¹ýÊ¢ÓÐ×ãÁ¿¼îʯ»ÒµÄ¸ÉÔï¹Ü£¬ÆøÌåÌå»ý¼õÉÙÖÁ1.68L£¨ÆøÌåÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©£®ËùÒÔ·´Ó¦ÖÐÉú³ÉµÄCO2ÊÇ10.64L-1.68L=8.96L£¬ÎïÖʵÄÁ¿ÊÇ8.96L¡Â22.4L/mol=0.04mol£¬Ôò¸ù¾ÝÔ­×ÓÊغã¿ÉÖª£¬AÖÐ̼ÇâÔ­×ӵĸöÊý·Ö±ðÊÇ8¡¢8£¬ËùÒÔÑõÔ­×ӵĸöÊýÊÇ
152-96-8
16
=3£¬Òò´Ë»¯Ñ§Ê½ÊÇC8H8O3£¬
ÈôAÎïÖÊÓöFeCl3ÈÜÒºÎÞÏÔÉ«·´Ó¦£¬ËµÃ÷·Ö×ÓÖÐÎï·ÓôÇ»ù£¬1molAÖ»ÄÜÓë1molNaOH·´Ó¦£¬1molAÓë×ãÁ¿½ðÊôÄÆ·´Ó¦¿ÉÉú³É1molH2£¬ËµÃ÷·Ö×ÓÖк¬´¼ôÇ»ùºÍôÈ»ù£¬ÒԴ˽â´ð¸ÃÌ⣮
½â´ð£º½â£º£¨1£©Mr£¨A£©=76¡ÁMr£¨H2£©=76¡Á2=152£¬
ŨÁòËáÔöÖØ3.6g£¬Ôò·´Ó¦ÖÐÉú³ÉµÄË®µÄÖÊÁ¿ÊÇ3.6g£¬
n£¨H£©=
3.6g¡Á2
18g/mol
=0.4mol£¬
ÔÙ½«ÓàϵÄÆøÌåͨ¹ýÊ¢ÓÐ×ãÁ¿¼îʯ»ÒµÄ¸ÉÔï¹Ü£¬ÆøÌåÌå»ý¼õÉÙÖÁ1.68L£¨ÆøÌåÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©£®ËùÒÔ·´Ó¦ÖÐÉú³ÉµÄCO2ÊÇ10.64L-1.68L=8.96L£¬
n£¨C£©=
10.64L-1.68L
22.4L/mol
=0.4mol£¬
Ôò¸ù¾ÝÔ­×ÓÊغã¿ÉÖª£¬
n£¨O£©=
7.6g-0.4mol¡Á1g/mol-0.4mol¡Á12g/mol
16g/mol
=0.15mol£¬
n£¨C£©£ºn£¨H£©£ºn£¨O£©=0.4mol£º0.4mol£º0.15mol=8£º8£º3£¬
AµÄʵÑéʽÊÇC8H8O3£¬Ê½Á¿Îª152£¬¼´ÊµÑéʽ¾ÍÊÇ·Ö×Óʽ£¬¼´·Ö×ÓʽΪC8H8O3£¬
´ð£ºAµÄ·Ö×ÓʽΪC8H8O3£»
£¨2£©ÈôAÎïÖÊÓöFeCl3ÈÜÒºÎÞÏÔÉ«·´Ó¦£¬ËµÃ÷·Ö×ÓÖÐÎï·ÓôÇ»ù£¬1molAÖ»ÄÜÓë1molNaOH·´Ó¦£¬1molAÓë×ãÁ¿½ðÊôÄÆ·´Ó¦¿ÉÉú³É1molH2£¬ËµÃ÷·Ö×ÓÖк¬´¼ôÇ»ùºÍôÈ»ù£¬¿ÉÄܵĽṹÓУ¨ÁÚ¡¢¼ä¡¢¶Ô¾ù¿É£©£¬
´ð£ºAµÄ½á¹¹¼òʽΪµÈ£®
µãÆÀ£º±¾Ì⿼²éÓлúÎïµÄÍƶϣ¬²àÖØÓÚ»¯Ñ§Ê½¡¢½á¹¹¼òʽȷ¶¨µÄÓйؼÆËãºÍÅжϣ¬¸ß¿¼Öеij£¼ûÌâÐÍ£¬ÊôÓÚÖеÈÄѶȵÄÊÔÌ⣮ÊÔÌâ×ÛºÏÐÔÇ¿£¬Ìù½ü¸ß¿¼£®ÔÚ×¢ÖضÔѧÉú»ù´¡ÖªÊ¶¹®¹ÌºÍѵÁ·µÄͬʱ£¬²àÖضÔѧÉúÄÜÁ¦µÄÅàÑø£®Ö¼ÔÚÅàÑøѧÉú·ÖÎö¡¢¹éÄÉ¡¢×ܽáÎÊÌâµÄÄÜÁ¦£®ÓÐÀûÓÚÅàÑøѧÉúµÄÂß¼­ÍÆÀíÄÜÁ¦ºÍ´´ÐÂ˼άÄÜÁ¦£®¸ÃÌâµÄ¹Ø¼üÊÇÀûÓúÃÊغ㷨£®¼´ÖÊÁ¿ÊغãºÍÔ­×ÓÊغãµÈ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨¢ñ£©Ä³ÌþAµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª84¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÏÂÁÐÎïÖÊÓëAÒÔÈÎÒâ±ÈÀý»ìºÏ£¬Èô×ÜÎïÖʵÄÁ¿Ò»¶¨£¬³ä·ÖȼÉÕÏûºÄÑõÆøµÄÁ¿²»ÏàµÈµÄÊÇ(ÌîÐòºÅ)________¡£
a£®C7H12O2   b£®C6H14      c£®C6H14O   d£®C7H14O3
£¨2£©ÈôÌþAΪÁ´Ìþ£¬·Ö×ÓÖÐËùÓеÄ̼ԭ×ÓÔÚͬһƽÃæÉÏ£¬¸Ã·Ö×ÓµÄÒ»ÂÈÈ¡´úÎïÖ»ÓÐÒ»ÖÖ¡£AµÄ½á¹¹¼òʽΪ________________£»
£¨3£©ÈôA²»ÄÜʹäåË®ÍÊÉ«£¬ÇÒÆäÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ£¬ÔòAµÄ½á¹¹¼òʽΪ______________¡£
£¨¢ò£©1mol·Ö×ÓʽΪCmHnµÄÓлúÎïÔÚÑõÆøÖÐÍêȫȼÉÕ£¬Éú³ÉCO2ºÍH2OµÄÎïÖʵÄÁ¿ÏàµÈ£¬²¢ÏûºÄ168LÑõÆø(±ê¿öÏÂ)¡£¸ÃÓлú»¯ºÏÎïµÄ·Ö×Óʽ____   _____£»
£¨¢ó£©Ä³ÓлúÎïAÊÇÌþµÄº¬ÑõÑÜÉúÎΪ²â¶¨Æä×é³ÉÓÐÈçÏÂʵÑé½á¹û£º
¢ÙÔÚÒ»¶¨Î¶ȺÍѹǿϽ«AÆû»¯£¬ÆäÖÊÁ¿ÊÇͬΡ¢Í¬Ñ¹ÏÂÇâÆøÖÊÁ¿µÄ76±¶£»
¢Ú³ÆÈ¡7.6gÓлúÎïA£¬ÔÚ¹ýÁ¿ÑõÆøÖÐÍêȫȼÉÕ¡£½«·´Ó¦ºóµÄ»ìºÏÆøÌåͨ¹ý×ãÁ¿Å¨H2SO4ºóÌå»ý±äΪ10.64L£¬Å¨ÁòËáÔöÖØ3.6g¡£ÔÙ½«ÓàϵÄÆøÌåͨ¹ýÊ¢ÓÐ×ãÁ¿¼îʯ»ÒµÄ¸ÉÔï¹Ü£¬ÆøÌåÌå»ý¼õÉÙÖÁ1.68L£¨ÆøÌåÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©¡£ È·¶¨AµÄ·Ö×Óʽ            ¡£

£¨¢ñ£©Ä³ÌþAµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª84¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÏÂÁÐÎïÖÊÓëAÒÔÈÎÒâ±ÈÀý»ìºÏ£¬Èô×ÜÎïÖʵÄÁ¿Ò»¶¨£¬³ä·ÖȼÉÕÏûºÄÑõÆøµÄÁ¿²»ÏàµÈµÄÊÇ(ÌîÐòºÅ)________¡£

a£®C7H12O2   b£®C6H14      c£®C6H14O   d£®C7H14O3

£¨2£©ÈôÌþAΪÁ´Ìþ£¬·Ö×ÓÖÐËùÓеÄ̼ԭ×ÓÔÚͬһƽÃæÉÏ£¬¸Ã·Ö×ÓµÄÒ»ÂÈÈ¡´úÎïÖ»ÓÐÒ»ÖÖ¡£AµÄ½á¹¹¼òʽΪ________________£»

£¨3£©ÈôA²»ÄÜʹäåË®ÍÊÉ«£¬ÇÒÆäÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ£¬ÔòAµÄ½á¹¹¼òʽΪ______________¡£

£¨¢ò£©1mol·Ö×ÓʽΪCmHnµÄÓлúÎïÔÚÑõÆøÖÐÍêȫȼÉÕ£¬Éú³ÉCO2ºÍH2OµÄÎïÖʵÄÁ¿ÏàµÈ£¬²¢ÏûºÄ168LÑõÆø(±ê¿öÏÂ)¡£¸ÃÓлú»¯ºÏÎïµÄ·Ö×Óʽ____   _____£»

£¨¢ó£©Ä³ÓлúÎïAÊÇÌþµÄº¬ÑõÑÜÉúÎΪ²â¶¨Æä×é³ÉÓÐÈçÏÂʵÑé½á¹û£º

¢ÙÔÚÒ»¶¨Î¶ȺÍѹǿϽ«AÆû»¯£¬ÆäÖÊÁ¿ÊÇͬΡ¢Í¬Ñ¹ÏÂÇâÆøÖÊÁ¿µÄ76±¶£»

¢Ú³ÆÈ¡7.6gÓлúÎïA£¬ÔÚ¹ýÁ¿ÑõÆøÖÐÍêȫȼÉÕ¡£½«·´Ó¦ºóµÄ»ìºÏÆøÌåͨ¹ý×ãÁ¿Å¨H2SO4ºóÌå»ý±äΪ10.64L£¬Å¨ÁòËáÔöÖØ3.6g¡£ÔÙ½«ÓàϵÄÆøÌåͨ¹ýÊ¢ÓÐ×ãÁ¿¼îʯ»ÒµÄ¸ÉÔï¹Ü£¬ÆøÌåÌå»ý¼õÉÙÖÁ1.68L£¨ÆøÌåÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©¡£ È·¶¨AµÄ·Ö×Óʽ            ¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø