ÌâÄ¿ÄÚÈÝ

£¨12·Ö£©
£¨1£©±ê×¼×´¿öÏ£¬Ìå»ýԼΪ11.2 LµÄNH3ÖÐÔ¼º¬ÓР    ¸ö·Ö×Ó¡¢º¬ÓР   ¸öÖÊ×Ó¡£
£¨2£©Í¬ÎÂͬѹÏ£¬Í¬ÖÊÁ¿µÄ°±ÆøºÍÁò»¯ÇâÆøÌ壨H2S£©µÄÌå»ý±ÈΪ           ¡£Í¬ÎÂͬѹÏ£¬Èô¶þÕßÇâÔ­×ÓÊýÏàµÈ£¬ËüÃǵÄÌå»ý±ÈΪ            ¡£
£¨3£©ÔÚijζÈʱ£¬Ò»¶¨Á¿µÄÔªËØAµÄÇ⻯ÎïAH3ÔÚÒ»¶¨Ìå»ýÃܱÕÈÝÆ÷ÖпÉÍêÈ«·Ö½â³ÉÁ½ÖÖÆø̬µ¥ÖÊ£¬´ËʱÃܱÕÈÝÆ÷ÖÐÆøÌå·Ö×Ó×ܵÄÎïÖʵÄÁ¿Ôö¼ÓÁË75%¡£ÔòAµ¥ÖʵÄÒ»¸ö·Ö×ÓÖÐÓÐ_____¸öAÔ­×Ó£¬AH3·Ö½â·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___________________¡£
£¨1£©3.01¡Á1023£¨2·Ö£© 3.01¡Á1024£¨2·Ö£©
£¨2£©2©U1£¨2·Ö£© 2©U3£¨2·Ö£©
£¨3£©4£¨2·Ö£© 4AH3 = A4+6H2£¨2·Ö£©
¿¼²éÎïÖʵÄÁ¿µÄÓйؼÆËã¡£
£¨1£©¸ù¾Ý±ê×¼×´¿öϵÄÆøÌåĦ¶ûÌå»ý¿ÉÖª£¬11.2L°±ÆøµÄÎïÖʵÄÁ¿ÊÇ11.2L¡Â22.4L/mol£½0.5mol¡£Òò´Ëº¬ÓеķÖ×ÓÊýÊÇ10¡Á0.5mol¡Á6.02¡Á1023/mol£½3.01¡Á1023¡£°±Æø·Ö×ÓÖк¬ÓÐ10¸öÖÊ×Ó£¬ËùÒÔº¬ÓеÄÖÊ×ÓÊýÊÇ0.5mol¡Á6.02¡Á1023/mol£½3.01¡Á1024¡£
£¨2£©Í¬ÖÊÁ¿µÄ°±ÆøºÍÁò»¯ÇâÆøÌ壨H2S£©µÄÎïÖʵÄÁ¿Ö®±ÈÊÇ34©U17£½2©U1£¬ËùÒÔ¸ù¾Ý°¢·ü¼ÓµÂÂÞ¶¨ÂÉ¿ÉÖª£¬¶þÕßµÄÌå»ýÖ®±ÈÊÇ2©U1£»¸ù¾Ý¶þÕߵĻ¯Ñ§Ê½¿ÉÖª£¬Í¬ÎÂͬѹÏ£¬Èô¶þÕßÇâÔ­×ÓÊýÏàµÈ£¬ËüÃǵÄÌå»ý±ÈΪ1/3©U1/2£½2©U3¡£
£¨3£©¸ÃÇ⻯Îï·Ö½âµÄ·½³ÌʽÊÇ2xAH3 ="2" Ax+3xH2£¬ÓÉÓÚÃܱÕÈÝÆ÷ÖÐÆøÌå·Ö×Ó×ܵÄÎïÖʵÄÁ¿Ôö¼ÓÁË75%¡££¬ÔòÓУ¬½âµÃx£½4£¬¼´Aµ¥ÖʵÄÒ»¸ö·Ö×ÓÖÐÓÐ4¸öÔ­×Ó£¬·´Ó¦µÄ·½³ÌʽÊÇ4AH3 = A4+6H2¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø