ÌâÄ¿ÄÚÈÝ

£¨5·Ö£©ÏÖÓÐһƿŨ¶ÈΪ0.2 mol/LµÄijËáÈÜÒº£¬¿ÉÄÜΪ´×Ëá¡¢ÑÎËá¡¢ÁòËáÖеÄÒ»ÖÖ¡£ÎªÁËÈ·¶¨¸ÃËáÈÜÒºµÄ×é³É½øÐÐʵÑ飺ȡ25.00 mL0.1 mol/LµÄÇâÑõ»¯ÄÆÈÜÒº£¬ÖðµÎ¼ÓÈë¸ÃËáÈÜÒº£¬Ç¡ºÃ·´Ó¦ÍêȫʱËùÐè¸ÃËáÈÜÒºÌå»ýΪ12.50 mL¡£Çë»Ø´ð£º
£¨1£©¸ÃËá²»¿ÉÄÜÊÇ               £»
£¨2£©ÓÃpHÊÔÖ½²âµÃ·´Ó¦ºóËùµÃÈÜÒº³Ê¼îÐÔ£¬¸ù¾Ý´ËÏÖÏó˵Ã÷¸ÃËáÈÜҺΪ       £¬ÓÃÀë×Ó·½³Ìʽ˵Ã÷ÈÜÒº³Ê¼îÐÔµÄÔ­Òò                                  £»
£¨3£©ÊµÑéÖеζ¨ÇúÏßÈçÓÒͼ£¬ÔÚBµã£¬a        12.5£¨Ìî´óÓÚ¡¢Ð¡ÓÚ»òµÈÓÚ£©ÔÚCµã¸÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡ÅÅÐò                                      ¡£
£¨1£©ÁòËᣨ1·Ö£©
£¨2£©´×ËᣬCH3COO_  + H2O  CH3COOH + OH£¨¸÷1·Ö£©
£¨3£©´óÓÚ  £¬ c£¨CH3COO£­£© > c£¨Na +£© > c£¨H+£© > c£¨OH£­£©£¨2·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨13·Ö£©ÏÂͼËùʾÊÇ·ÖÀë»ìºÏÎïʱ³£ÓõÄÒÇÆ÷£¬»Ø´ðÏÂÁÐÎÊÌâ:

£¨1£©Ð´³öÒÇÆ÷C¡¢EµÄÃû³Æ                 ¡¢                
£¨2£©·ÖÀëÒÔÏ»ìºÏÎïÓ¦¸ÃÖ÷ҪѡÓÃʹÓÃʲôÒÇÆ÷£¿£¨Ìî×Öĸ·ûºÅ£©
´ÖÑκÍÄàɳ£º        Ê³ÓÃÓͺ;ƾ«£º         »¨ÉúÓͺÍË®£º      
£¨3£©ÏÂÁйØÓÚÒÇÆ÷µÄʹÓÃ˵·¨ÕýÈ·µÄÊÇ      
A£®AÒÇÆ÷¿ÉÒÔÓþƾ«µÆÖ±½Ó¼ÓÈÈ
B£®BÒÇÆ÷¿ÉÒÔÓÃÓÚÏò¾Æ¾«µÆÖÐÌí¼Ó¾Æ¾«
C£®CÒÇÆ÷ÔڷųöÒºÌåʱӦ´ò¿ªÉϱߵÄÆ¿Èû
D£®ÔÚʵÑéÊÒÓ¦ÓÃDÒÇÆ÷½øÐÐʵÑéʱҪ²»¶ÏÓò£Á§°ô½Á°è
E£®EÒÇÆ÷ÖÐË®µÄÁ÷ÏòÊÇÉϽøϳö
£¨4£©ÈôÏòC×°ÖÃÖмÓÈëµâË®ºÍÉÙÁ¿CCl4£¬Õðµ´ºó¾²Ö㬻á¹Û²ìµ½Ê²Ã´ÏÖÏó£¿
                                                                                
£¨5£©Èô´ÖÑÎÈÜÒºÖнöº¬ÓÐÉÙÁ¿µÄCaCl2£¬Ä³Ñ§ÉúÓÃNa2CO3ʹCa2+Àë×Óת»¯ÎªÌ¼Ëá¸Æ³Áµí£¬È·ÈÏCa2+ÒѳÁµíÍêÈ«µÄʵÑé·½·¨ÊÇ                                   £»ÈôÒªµÃµ½´¿¾»µÄ³ÁµíÎÐèÒª¶ÔÆäÏ´µÓ£¬Ð´³öÏ´µÓ³ÁµíµÄ·½·¨                                            ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø