ÌâÄ¿ÄÚÈÝ

¹ã¶«ÊÇÖйú·çÁ¦·¢µç×îÔçµÄµØÇøÖ®Ò»£¬¸ÃÊ¡·çÄÜ×ÊÔ´´¢Á¿Òì³£·á¸»£¬·çËÙ¿ÉæÇÃÀÈ«Çò×î´ó·çµç¹úµÂ¹ú£¬·¢Õ¹·çµç²»½ö¿ÉΪ¹ã¶«¸ßËٵľ­¼Ã·¢Õ¹ÌṩÄÜÔ´£¬»¹½«¼õÉÙÎÂÊÒÆøÌåµÄÅÅ·Å£®¾Ý´Ë»Ø´ðÎÊÌâ¡£


1.¹ã¶«¡¢µÂ¹ú·Ö¾ÓÑÇÅ·´ó½¶«Î÷Á½²à£¬Á½ÕßÏà±È


  1. A.
    ·çËÙÏ൱£¬µ«Ê¢ÐзçÏò²»Í¬
  2. B.
    ·çËÙÏ൱£¬µ«·çÄܵÄÀûÓÃÂÊÓÐÒì
  3. C.
    Ê¢ÐзçÏòÏàͬ£¬µ«·çËÙ²î±ðºÜ´ó
  4. D.
    ·çÄܵÄÀûÓÃÂÊÏàͬ£¬µ«Ê¢ÐзçÏò²îÒìºÜ´ó

2.³ý·çÄÜÍ⣬¹ã¶«ÆľßDZÁ¦µÄÐÂÄÜÔ´»¹ÓÐ


  1. A.
    ³±Ï«ÄÜ
  2. B.
    Ë®ÄÜ
  3. C.
    ºËÄÜ
  4. D.
    Ì«ÑôÄÜ

3.´Ó»·¾³½Ç¶È·ÖÎö£¬·¢Õ¹·çµç


  1. A.
    ¿ÉÒÔ»º½âÎÂÊÒЧӦ
  2. B.
    ¿ÉÒÔ»ñµÃ½Ï´óµÄͶ×ʻر¨
  3. C.
    Äܹ»¼õÇá´óÆøÎÛȾ
  4. D.
    Äܹ»ÊµÏÖÄÜÔ´µÄ¶àÑù»¯
1. AB
2. AC
3. AC
±¾Ì⿼²éÐÂÄÜÔ´¡£
1.¹ã¶«Ê¡Î»ÓÚÑÇÅ·´ó½¶«°¶£¬¹Ê·çÁ¦½Ï´ó£¬µ«Ïļ¾Ê¢Ðж«ÄϷ磬¶¬¼¾Ê¢ÐÐÎ÷±±·ç£»µ«·çÄܵÄÀûÓÃÂʵͣ»µÂ¹úÖÕÄêÊÜÊ¢ÐÐÎ÷·çÓ°Ï죬¹Ê·çÁ¦´ó£¬ÇÒ·çÄÜÀûÓÃÂʸߡ£¹ÊÑ¡AB¡£
2.Ë®Äܲ»ÊôÓÚÐÂÄÜÔ´£»¹ã¶«µØ´¦ÄÏ·½£¬¹ÊÓê¼¾½Ï³¤£¬¹ÊÌ«ÑôÄÜ×ÊԴDZÁ¦²»´ó£»¹ÊÑ¡AC
3.´Ó»·¾³µÄ½Ç¶È¶øÑÔ£¬·¢Õ¹·çµçÖ÷ÒªÊǸÄÉÆÄÜÔ´Ïû·Ñ½á¹¹£¬¼õÉÙ¿óÎïȼÁϵÄȼÉÕ£¬¼õÇá¶þÑõ»¯Ì¼µÄÅŷźʹóÆøÎÛȾµÄÅÅ·Å£¬¹ÊÑ¡AC¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø