题目内容
某物理兴趣小组为了测量人到高墙的距离,他们站在高墙前对着高墙大喊一声,用秒表测出自发声后1.6s听到回声,求人到高墙的距离
解:声音从人传到高墙的时间:
t=
×1.6s=0.8s
∵v=![](http://thumb.1010pic.com/pic1/upload/papers/c04/20120819/20120819121228493492.png)
∴此人与高墙之间的距离:s=vt=340m/s×0.8s=272m
答:人离高墙的距离是272m
t=
![](http://thumb.1010pic.com/pic1/upload/papers/c04/20120819/20120819121228375571.png)
∵v=
![](http://thumb.1010pic.com/pic1/upload/papers/c04/20120819/20120819121228493492.png)
∴此人与高墙之间的距离:s=vt=340m/s×0.8s=272m
答:人离高墙的距离是272m
![](http://thumb2018.1010pic.com/images/loading.gif)
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