ÌâÄ¿ÄÚÈÝ

³ÂÃ÷ͬѧÔÚÊúÖ±Ðü¹ÒµÄµ¯»Éϼӹ³Â룬×ö¡°Ì½¾¿µ¯»ÉÉ쳤Á¿Ó뵯Á¦µÄ¹ØÏµ¡±ÊµÑ飮ϱíÊdzÂÃ÷ͬѧÊÕ¼¯µÄʵÑéÊý¾Ý£º
£¨1£©ÇëÄã°ïÖú³ÂÃ÷ͬѧÍê³É±í¸ñµÄ¿Õ°×´¦£»
µ¯Á¦/N00.51.01.52.02.5
µ¯»É×ܳ¤¶È/cm6.07.28.49.610.812.0
µ¯»ÉÉ쳤Á¿/cm01.22.43.6
£¨2£©¸ù¾Ý±íÖÐÊý¾ÝÃèµã£¬ÔÚͼÖеÄ×ø±êϵ»­³öµ¯»ÉÉ쳤Á¿Ó뵯Á¦µÄ¹ØÏµÍ¼£»

£¨3£©·ÖÎöʵÑéÊý¾Ý»ò´Óµ¯»ÉÉ쳤Á¿Ó뵯Á¦µÄ¹ØÏµÍ¼£¬Äã¿ÉµÃµ½µÄ½áÂÛ£º________£»
£¨4£©´ËʵÑé½áÂÛÓ¦ÓÃÔÚÎÒÃÇËùѧ¹ýµÄÄÄÒ»¸ö²âÁ¿¹¤¾ßÖУº________£»
£¨5£©µ¯»É²âÁ¦¼ÆÉϿ̶ÈÊÇ·ñ¾ùÔÈ£¿ÎªÊ²Ã´£¿

½â£º£¨1£©Í¨¹ý¹Û²ì±í¸ñÖÐǰËÄ×éÊý¾Ý¿ÉÖª£ºµ¯Á¦Ã¿Ôö¼Ó0.5N£¬µ¯»ÉµÄÉ쳤Á¿¾ÍÔö¼Ó1.2cm£¬¹Êµ±µ¯Á¦Îª2.0Nʱ£¬µ¯»ÉµÄÉ쳤Á¿Îª1.2cm¡Á=4.8cm£»µ±µ¯Á¦Îª2.5Nʱ£¬µ¯»ÉµÄÉ쳤Á¿Îª1.2cm¡Á=6.0cm£»
£¨2£©¸ù¾Ý±íÖÐÊý¾ÝÃèµã£¬ÔÚͼÖеÄ×ø±êϵ»­³öµ¯»ÉÉ쳤Á¿Ó뵯Á¦µÄ¹ØÏµÍ¼ÈçÏÂͼËùʾ£º

£¨3£©·ÖÎöʵÑéÊý¾Ý»ò´Óµ¯»ÉÉ쳤Á¿Ó뵯Á¦µÄ¹ØÏµÍ¼£¬¿ÉµÃµ½µ¯»ÉµÄ²âÁ¦·¶Î§ÄÚµ¯»ÉµÄÉ쳤Á¿Ó뵯Á¦³ÉÕý±ÈÕâÒ»½áÂÛ£»
£¨4£©´ËʵÑé½áÂÛÓ¦ÓÃÔÚÎÒÃÇËùѧ¹ýµÄµ¯»É²âÁ¦¼ÆÕâÒ»²âÁ¿¹¤¾ßÖУ»
£¨5£©µ¯»É²âÁ¦¼ÆÉϿ̶ÈÊǾùÔȵģ¬ÒòΪÔÚµ¯»ÉµÄ²âÁ¦·¶Î§ÄÚµ¯»ÉµÄÉ쳤Á¿Ó뵯Á¦³ÉÕý±ÈÀý¹ØÏµ£®
¹Ê´ð°¸Îª£º£¨1£©Á½¸öÊý¾Ý´Ó×óµ½ÓÒÒÀ´ÎΪ4.8 6.0£»
£¨2£©µ¯»ÉÉ쳤Á¿Ó뵯Á¦µÄ¹ØÏµÍ¼ÈçÉÏͼËùʾ£»
£¨3£©µ¯Á¦Ôö´óÒ»±¶£¬µ¯»ÉµÄÉ쳤Á¿Ôö¼ÓÒ»±¶»òµ¯»ÉµÄÉ쳤Á¿Ó뵯Á¦³ÉÕý±È£»
£¨4£©µ¯»É²âÁ¦¼Æ£»
£¨5£©¾ùÔÈ£»ÒòΪÔÚµ¯»ÉµÄ²âÁ¦·¶Î§ÄÚµ¯»ÉµÄÉ쳤Á¿Ó뵯Á¦³ÉÕý±ÈÀý¹ØÏµ£®
·ÖÎö£º±¾ÌâÖ÷Òª¿¼²éÁËÓйص¯»É²âÁ¦¼ÆÔ­ÀíµÄÏà¹ØÖªÊ¶£¬Ö÷ÒªÓУº
£¨1£©ÔÚµ¯»ÉµÄ²âÁ¿·¶Î§ÄÚ£¬µ¯»ÉµÄÉ쳤Á¿Ó뵯Á¦³ÉÕý±È£»
£¨2£©ÄÜÔÚ×ø±êϵÖл­³öµ¯»ÉÉ쳤Á¿Ó뵯Á¦µÄ¹ØÏµÍ¼£»
£¨3£©ÖªµÀµ¯»É²âÁ¦¼ÆµÄÔ­Àí¼°Æä¿Ì¶ÈµÄ¾ùÔÈÐÔµÄÔ­Òò£®
µãÆÀ£º±¾ÊµÑé̽¾¿Á˵¯»ÉÉ쳤Á¿Ó뵯Á¦µÄ¹ØÏµ²¢Í¨¹ý·ÖÎöÊÕ¼¯µÄʵÑéÊý¾Ý£¬µÃ³öÁËÔÚµ¯»ÉµÄ²âÁ¦·¶Î§ÄÚµ¯»ÉµÄÉ쳤Á¿Ó뵯Á¦³ÉÕý±ÈÀý¹ØÏµÕâÒ»½áÂÛ£¬ÒÔ´Ë·´À¡µ½Ê鱾֪ʶ£¬Ë¼Â·ÐÂÓ±£¬¶ÔѧÉúÁé»îÕÆÎÕ֪ʶµÄÄÜÁ¦ÓÐÁ˸ü¸ßµÄÒªÇó£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø