ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ä³Í¬Ñ§×ö¡°²âÁ¿Ð¡µÆÅݵ繦ÂÊ¡±ÊµÑéÖУ¬ËùÓõçÔ´µçѹºãΪ4V£¬Ð¡µÆÅݵÄÂÝÐýÌ×ÉϱêÓС°2.5V¡±×ÖÑù
£¨1£©ÔÚ¼ì²éÒÇÆ÷ʱ£¬·¢ÏÖµçÁ÷±íµÄÖ¸ÕëÈçͼ1Ëùʾ£¬ÔòËû½ÓÏÂÀ´µÄ²Ù×÷ÊÇ £®
£¨2£©ÇëÄã¸ù¾Ýͼ2µç·ͼÓñʻÏß´úÌæµ¼Ïߣ¬½«Í¼3ÖÐδÍê³ÉµÄµç·Á¬½ÓºÃ£®ÒªÇ󣺻¬¶¯±ä×èÆ÷µÄ»¬Æ¬ÏòÓÒÒƶ¯Ê±£¬Á¬Èëµç·µÄ×èÖµ±äС£¬µ¼Ïß²»Äܽ»²æ£®
£¨3£©¼ì²éÒÇÆ÷ºÍµç·ÎÞÎóºó£¬±ÕºÏ¿ª¹Ø£¬µ÷½Úµ÷¶¯±ä×èÆ÷Ƭµ½Ä³Ò»Î»ÖÃʱ£¬µçѹ±íʾÊýÈçͼ4Ëùʾ£¬ÏÖÒª²â¶¨Ð¡µÆÅݵĶ¹¦ÂÊ£¬Ó¦½«»¬Æ¬Êʵ±µØÏò £¨Ñ¡Ìî¡°×ó¡±»ò¡°ÓÒ¡±£©Òƶ¯£¬Í¬Ê±ÑÛ¾¦Ó¦¹Û²ì £®
£¨4£©¸Ä±ä»¬¶¯±ä×èÆ÷µÄ×èÖµ£¬¶à´Î²âÁ¿Í¨¹ýСµÆÅݵĵçÁ÷ºÍËüÁ½¶ËµÄµçѹ£¬¸ù¾Ý¼Ç¼µÄÊý¾Ý»³öÁËÈçͼ5ËùʾµÄСµÆÅݵĵçÁ÷Ëæµçѹ±ä»¯µÄ¹ØϵͼÏó£®ÓÉ´Ë¿ÉÖª£¬Ð¡µÆÅݵĶ¹¦ÂÊΪ W£¬Ð¡µÆÅݵÆÏßÐεç×èËæµçѹµÄÔö´ó¶ø £¨Ñ¡Ìî¡°Ôö´ó¡±¡¢¡°²»±ä¡±»ò¡°¼õС¡±£©£®
£¨5£©Íê³ÉÁËÉÏÊöʵÑéºó£¬Ð¡Ã÷½øÒ»²½Ì½¾¿Í¨µçÖ±µ¼ÏßÖÜΧµÄ´Å³¡·Ö²¼Çé¿ö£¬ÕÒÀ´Ð¡´ÅÕë¡¢Ìúм¡¢Ó²Ö½°åµÈ£¬×öÁËÈçͼ6ËùʾµÄʵÑ飬·¢ÏÖÁËÖ±µ¼ÏßÖÜΧµÄ´Å³¡ÊÇÒÔµ¼ÏßΪԲÐĵÄͬÐÄԲȦ£¬²¢ÕÒµ½ÁËÅжÏÖ±µ¼ÏßÖÜΧ´Å³¡µÄ·½·¨£º¡°ÓÃÓÒÊÖÎÕסֱµ¼Ïߣ®ÈôóÄ´Ö¸Ö¸ÏòÖ±µ¼ÏßÖеçÁ÷µÄ·½Ïò£¬ÔòÍäÇúµÄËÄÖ¸ËùÖ¸·½ÏòΪ´Å³¡·½Ïò£®¡±ÇëÄãÓÃСÃ÷µÄ·½·¨ÅжÏÈçͼ7ÖÐС´ÅÕë±±¼«×ªÏò £®Í¼8ÖÐС´ÅÕë±±¼«×ªÏò £¨Á½¿Õ¾ùÑ¡Ìî¡°Ö½ÄÚ¡±»ò¡°Ö½Í⡱£©£®
¡¾´ð°¸¡¿£¨1£©µ÷Á㣻£¨2£©ÈçÏÂͼ
£¨3£©×ó¡¢µçѹ±íʾÊý£»£¨4£©Ê¹µçѹ±íʾÊýΪ2.5V¡¢0.625¡¢Ôö´ó£»£¨5£©Ö½Í⣻ֽÄÚ
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©Ê¹Óõç±íÇ°£¬×Ðϸ¹Û²ìÖ¸ÕëÊÇ·ñÖ¸ÔÚÁã¿ÌÏߣ¬Èç²»ÊÇ£¬ÐèÒªµ÷Á㣻
£¨2£©¸ù¾ÝÌâÄ¿ÒªÇ󣬻¬¶¯±ä×èÆ÷µÄ»¬Æ¬ÏòÓÒÒƶ¯Ê±£¬Á¬Èëµç·µÄ×èÖµ±äС£¬ÓÉͼ¿ÉÖª»¬¶¯±ä×èÆ÷µÄϽÓÏßÖùÓ¦½ÓÓҲ࣬Á¬Èëµç·µÄ×èÖµ±ä´ó£¬ÓÉͼ¿ÉÖª»¬¶¯±ä×èÆ÷µÄϽÓÏßÖùÓ¦½Ó×ó²à£»
£¨3£©Óɵçѹ±íµÄʾÊý¿ÉÖª£¬µçѹΪ2.7V´óÓڶµçѹ£¬ÏÖÒª²â¶¨Ð¡µÆÅݵĶ¹¦ÂÊ£¬¾ÍÒªÇóСµÆÅÝÁ½¶ËµçѹΪ2.5V£¬¸ù¾Ý´®Áª·ÖѹÌص㣬»¬¶¯±ä×èÆ÷µÄ»¬Æ¬Ó¦Ïò×óÒÆ£»Í¬Ê±¹Û²ìµçѹ±íÖ±µ½2.5V£»
£¨4£©ÓÉͼ5¿ÉÖª£¬Ð¡µÆÅÝ2.5VʱµÄµçÁ÷£¬ÓÉP=UI¿ÉÇó¶î¶¨¹¦ÂÊ£¬Ð¡µÆÅݵç×èÊÜζÈÓ°Ïì½Ï´ó£¬ËæµçѹÔö´ó¶øÔö´ó£»
£¨5£©¸ù¾ÝÓÃÓÒÊÖÎÕסֱµ¼Ïߣ®ÈôóÄ´Ö¸Ö¸ÏòÖ±µ¼ÏßÖеçÁ÷µÄ·½Ïò£¬ÔòÍäÇúµÄËÄÖ¸ËùÖ¸·½ÏòΪ´Å³¡·½Ïò£¬Ïȸù¾Ý°²ÅඨÔòÅжϳöͨµçµ¼ÌåÏ·½´Å³¡µÄ·½Ïò£¬È»ºó¸ù¾ÝС´ÅÕ뾲ֹʱ£¬±±¼«µÄÖ¸ÏòΪ´Å³¡·½Ïò¿É֪С´ÅÕëN¼«µÄÖ¸Ïò£®
½â£º£¨1£©µç±íµÄʹÓÃ×¢Òâµ÷Á㣬¹Û²ìÁ¿³Ì¡¢·Ö¶ÈÖµ£»ÓÉͼ1¿ÉÖªÐèÒªµ÷Á㣻
£¨2£©»¬¶¯±ä×èÆ÷µÄ»¬Æ¬ÏòÓÒÒƶ¯Ê±£¬Á¬Èëµç·µÄ×èÖµ±äС£¬ÓÉͼ¿ÉÖª»¬¶¯±ä×èÆ÷µÄϽÓÏßÖùÓ¦½ÓÓҲࣻ
£¨3£©Óɵçѹ±íµÄʾÊý¿ÉÖª£¬µçѹΪ2.7V£¾2.5V£¬¸ù¾Ý´®Áª·ÖѹÌص㣬»¬¶¯±ä×èÆ÷µÄ»¬Æ¬Ó¦Ïò×óÒÆ£¬Ôö´ó»¬¶¯±ä×èÆ÷×èÖµ·ÖÈ¥¶àÓàµÄ0.2Vµçѹ£»Í¬Ê±¹Û²ìµçѹ±íµ½Ê¾ÊýΪ2.5VΪֹ£»
£¨4£©£©ÓÉͼ5¿ÉÖª£¬Ð¡µÆÅÝ2.5VʱµÄµçÁ÷£¬I=0.25A£¬P=UI=2.5V¡Á0.25A=0.625w£¬
СµÆÅݵç×èÊÜζÈÓ°Ïì½Ï´ó£¬¹ÊËæµçѹÔö´ó¶øÔö´ó£»
£¨5£©Éì³öÓÒÊÖ£¬´óÄ´Ö¸Ö¸ÏòµçÁ÷µÄ·½Ïò£¬ËÄÖ¸µÄ·½ÏòΪ´Å³¡µÄ·½Ïò£¬¹Êͼ7µ¼ÌåÕýÏ·½´Å³¡·½ÏòÏòÍ⣬¼´Ð¡´ÅÕ뾲ֹʱN¼«µÄÖ¸ÏòΪֽÍ⣻ͼ8Öдų¡·½Ïò´¹Ö±Ö½ÃæÏòÄÚ£®
¹Ê´ð°¸Îª£º£¨1£©µ÷Á㣻£¨2£©ÈçÏÂͼ
£¨3£©×ó¡¢µçѹ±íʾÊý£»£¨4£©Ê¹µçѹ±íʾÊýΪ2.5V¡¢0.625¡¢Ôö´ó£»£¨5£©Ö½Í⣻ֽÄÚ£®