ÌâÄ¿ÄÚÈÝ

£¨2010?±¾Ïª£©ÈçͼËùʾ£¬ÊÇijʵÑéС×é²âÁ¿ÑÎË®ÃܶȵÄʵÑé¹ý³Ì£º

£¨1£©Çë½áºÏ¸ÃС×éµÄʵÑéÉè¼Æ£¬ÌîдÏÂÃæµÄʵÑé¼Ç¼±í¸ñ£®
ÎïÀíÁ¿ ÉÕ±­ºÍÑÎË®µÄ×ÜÖÊÁ¿/g ÉÕ±­ºÍÊ£ÓàÑÎË®µÄÖÊÁ¿/g
µ¹ÈëÁ¿Í²ÖÐÑÎË®µÄÖÊÁ¿/g
µ¹ÈëÁ¿Í²ÖÐÑÎË®µÄÖÊÁ¿/g
µ¹ÈëÁ¿Í²ÖÐÑÎË®µÄÌå»ý/cm3 ÑÎË®µÄÃܶÈ/£¨g?cm-3£©
ʵÑéÊý¾Ý
63.2
63.2
17
17
46.2
42
42
1.1
1.1
£¨2£©Ð¡Ç¿»Øµ½¼ÒÖУ¬¿´µ½ÂèÂèÂòµÄһСƿÉÙÁ¿µÄ¡°éÏé­ÓÍ¡±£¬ËûÏë²âһϡ°éÏé­ÓÍ¡±µÄÃܶȣ¬¼ÒÖÐÖ»ÓÐÒÔÏÂÎïÆ·£º×ãÁ¿µÄË®£¬Ô²ÐÎË®Å裬¿Ì¶È³ß£¬Ò»¸öÄÜÔÚË®ÖÐÊúֱƯ¸¡µÄ¡¢Ô²ÖùÐα¡±Úƽµ×ÖÊÁ¿²»¼ÆµÄ²£Á§Æ¿£¬ÇëÄã°ïÖúËûÉè¼ÆÒ»ÖÖʵÑé·½·¨£¬²â³ö¡°éÏé­ÓÍ¡±µÄÃܶȣ¬Ð´³öÖ÷ҪʵÑé²½ÖèºÍéÏé­ÓÍÃܶȱí´ïʽ£º
¢ÙʵÑé²½Ö裺
a£®ÔÚ²£Á§Æ¿ÖÐÊ¢ÈëÊÊÁ¿µÄéÏé­ÓÍ£¬Óÿ̶ȳ߲â³öéÏé­Ó͵ĸ߶Èh1£®
b£®ÔÚË®ÅèÖÐÊ¢ÈëÊÊÁ¿µÄË®£¬½«Ê¢ÓÐéÏé­Ó͵IJ£Á§Æ¿·ÅÈëË®ÖУ¬Ê¹ÆäÊúֱƯ¸¡ÔÚË®ÃæÉÏ£¬Óÿ̶ȳ߲â³ö²£Á§Æ¿½þÈëË®ÖеÄÉî¶Èh2£®
c£®¼ÆËãéÏé­Ó͵ÄÃܶȣ®
a£®ÔÚ²£Á§Æ¿ÖÐÊ¢ÈëÊÊÁ¿µÄéÏé­ÓÍ£¬Óÿ̶ȳ߲â³öéÏé­Ó͵ĸ߶Èh1£®
b£®ÔÚË®ÅèÖÐÊ¢ÈëÊÊÁ¿µÄË®£¬½«Ê¢ÓÐéÏé­Ó͵IJ£Á§Æ¿·ÅÈëË®ÖУ¬Ê¹ÆäÊúֱƯ¸¡ÔÚË®ÃæÉÏ£¬Óÿ̶ȳ߲â³ö²£Á§Æ¿½þÈëË®ÖеÄÉî¶Èh2£®
c£®¼ÆËãéÏé­Ó͵ÄÃܶȣ®
£®
¢ÚÃܶȵıí´ïʽ¦ÑéÏé­ÓÍ=
¦ÑË®h2
h1
¦ÑË®h2
h1
   £¨ÓÃÎïÀíÁ¿µÄ·ûºÅ±íʾ£©£®
·ÖÎö£º£¨1£©ÓÃÒºÌåºÍÉÕ±­µÄ×ÜÖÊÁ¿¼õÈ¥ÉÕ±­ºÍÊ£ÓàÒºÌåµÄÖÊÁ¿¼´µÃÁ¿Í²ÖÐÒºÌåµÄÖÊÁ¿£®¸ù¾ÝÁ¿Í²µÄʾÊý¿É¶Á³öÒºÌåµÄÌå»ý£¬È»ºóÀûÓÃÃܶȹ«Ê½¦Ñ=
m
V
¿ÉÇó³öÒºÌåµÄÃܶȣ®
×¢ÒâÌìƽµÄ¶ÁÊý£ºÌìƽƽºâʱÎïÌåµÄÖÊÁ¿µÈÓÚÓÒÅÌÖÐíÀÂëµÄÖÊÁ¿¼ÓÓÎÂëÔÚ±ê³ßÉÏËù¶ÔµÄ¿Ì¶ÈÖµ£®Òª¿´Çå±ê³ßµÄ·Ö¶ÈÖµ£®
ÔÚ½øÐÐÁ¿Í²µÄ¶ÁÊýʱ£¬ÊÓÏßÒªÓëÒºÃæµÄ°¼µ×Ïàƽ£¬×¢ÒâÁ¿Í²µÄ·Ö¶ÈÖµ£®
£¨2£©¸ù¾ÝÌâÄ¿Öиø³öµÄÆ÷²ÄÌáʾ£¬´ËÌâÐ轫СƿƯ¸¡ÔÚË®ÖУ¬¸ù¾Ý¸¡Á¦ÓëÖØÁ¦ÏàµÈµÄ֪ʶÇó³öéÏé­Ó͵ÄÃܶȣ®
½â´ð£º½â£º£¨1£©ÓÉͼ֪£¬
±ê³ßµÄ·Ö¶ÈÖµÊÇ0.2g£¬ËùÒÔÉÕ±­ºÍÑÎË®µÄ×ÜÖÊÁ¿Îª50g+10g+3.2g=63.2g£»ÉÕ±­ºÍÊ£ÓàÑÎË®µÄÖÊÁ¿Îª10g+5g+2g=17g£»
Á¿Í²µÄ·Ö¶ÈֵΪ2ml£¬ËùÒÔµ¹ÈëÁ¿Í²ÖÐÑÎË®µÄÌå»ýΪ42ml£®
ÒªÇó³öÑÎË®µÄÃܶȻ¹ÐèµÃÖªµ¹ÈëÁ¿Í²ÖÐÑÎË®µÄÖÊÁ¿£¬¸ù¾Ý¦Ñ=
m
V
=
46.2g
42cm3
¡Ö1.1g/cm3
£¨2£©ÔÚ²£Á§Æ¿ÖÐÊ¢ÈëÊÊÁ¿µÄéÏé­ÓÍ£¬Óÿ̶ȳ߲â³öéÏé­Ó͵ĸ߶Èh1£¬ÔÚË®ÅèÖÐÊ¢ÈëÊÊÁ¿µÄË®£¬½«Ê¢ÓÐéÏé­Ó͵IJ£Á§Æ¿·ÅÈëË®ÖУ¬Ê¹ÆäÊúֱƯ¸¡ÔÚË®ÃæÉÏ£¬Óÿ̶ȳ߲â³ö²£Á§Æ¿½þÈëË®ÖеÄÉî¶Èh2£¬¸ù¾ÝÎïÌåÊܵ½µÄ¸¡Á¦ÓëÖØÁ¦ÏàµÈµÃ£¬ÎïÌåµÄÖÊÁ¿µÈÓÚÅÅ¿ªË®µÄÖÊÁ¿£®
ÉèÆ¿µÄµ×Ãæ»ýΪS£¬ÔòmÓÍ=mË®=¦ÑË®VË®=¦ÑË®Sh2
ËùÒÔ¦ÑÓÍ=
mÓÍ
VÓÍ
=
¦ÑË®Sh2
Sh1
=
¦ÑË®h2
h1

¹Ê´ð°¸Îª£º£¨1£©
ÎïÀíÁ¿ ÉÕ±­ºÍÑÎË®µÄ×ÜÖÊÁ¿/g ÉÕ±­ºÍÊ£ÓàÑÎË®µÄÖÊÁ¿/g µ¹ÈëÁ¿Í²ÖÐÑÎË®µÄÖÊÁ¿/g µ¹ÈëÁ¿Í²ÖÐÑÎË®µÄÌå»ý/cm3 ÑÎË®µÄÃܶÈ/£¨g?cm-3£©
ʵÑéÊý¾Ý 63.2 17 46.2 42 1.1
£¨2£©¢Ùa£®ÔÚ²£Á§Æ¿ÖÐÊ¢ÈëÊÊÁ¿µÄéÏé­ÓÍ£¬Óÿ̶ȳ߲â³öéÏé­Ó͵ĸ߶Èh1£®
b£®ÔÚË®ÅèÖÐÊ¢ÈëÊÊÁ¿µÄË®£¬½«Ê¢ÓÐéÏé­Ó͵IJ£Á§Æ¿·ÅÈëË®ÖУ¬Ê¹ÆäÊúֱƯ¸¡ÔÚË®ÃæÉÏ£¬Óÿ̶ȳ߲â³ö²£Á§Æ¿½þÈëË®ÖеÄÉî¶Èh2£®
c£®¼ÆËãéÏé­Ó͵ÄÃܶÈ
¢Ú
¦ÑË®h2
h1
µãÆÀ£º´ËÌ⿼²éÁËѧÉú²âÁ¿ÒºÌåÃܶȵķ½·¨£¬Í¬Ê±¿¼²éÁËÓйØÌìƽºÍÁ¿Í²µÄ¶ÁÊýÎÊÌ⣬ÔÚ½øÐжÁÊýʱһ¶¨×¢Òâ·Ö¶ÈÖµ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2010?±¾Ïª£©ÈçͼËùʾ£¬ÊÇÎÒ¹ú±ùºøÑ¡ÊÖÔÚ2010Ä궬°Â»áÅ®×Ó±ùºø±ÈÈüÖеÄÒ»¸ö³¡¾°£®Ð¡ÀöÔÚ¹Û¿´±ÈÈüʱ·¢ÏÖ£ºÁ½ÃûÔ˶¯Ô±ÔÚ±ùºøµÄÇ°Ãæ¡°Ë¢±ù¡±Ê±£¬±ùºøµÄÔ˶¯×´Ì¬·¢ÉúÁ˸ı䣮СÀöÁªÏëµ½½Ì²ÄÖеÄ̽¾¿ÊµÑ飬ËýÏ룺
£¨1£©Èô½«±ùºø»»³É±ù¿é£¬ÓÃͬÑùµÄ·½·¨ÔÚ±ùÃæÉϾͿÉÒÔ̽¾¿¡°×èÁ¦¶ÔÎïÌåÔ˶¯µÄÓ°Ï족£®
¢ÙСºì¶ÔСÀöµÄ¹ÛµãÌá³öÁËÖÊÒÉ£¬Ð¡ºìµÄÒìÒéÊÇ´ËʵÑéÉè¼Æ²»Ò׿ØÖƱù¿éµÄ³õʼËٶȣ¬¼ÙÈç¿ÉÒÔÀûÓÃľ°å´î³ÉбÃ棬ΪÁ˱£Ö¤±ù¿é»¬µ½±ùÃæʱµÄËÙ¶ÈÏàͬ£¬Ó¦½øÐеIJÙ×÷ÊÇ
Èñù¿é´ÓбÃæµÄͬһ¸ß¶ÈÓɾ²Ö¹»¬ÏÂ
Èñù¿é´ÓбÃæµÄͬһ¸ß¶ÈÓɾ²Ö¹»¬ÏÂ
£®
¢Ú¼ÙÈçÔÚ¡°Ë¢±ù¡±µÄ¹ý³ÌÖУ¬±ùÃæûÓÐÈÛ»¯£¬¡°Ë¢±ù¡±µÄÄ¿µÄÊÇΪÁ˸ıä±ùÃæµÄ
´Ö²Ú³Ì¶È
´Ö²Ú³Ì¶È
£¬´Ó¶ø¸Ä±ä×èÁ¦´óС£®
¢Ûͨ¹ý±È½Ï±ù¿éÔÚ²»Í¬±ùÃæÉÏÇ°½øµÄ
¾àÀë
¾àÀë
£¬¾Í¿ÉÒÔ̽¾¿¡°×èÁ¦¶ÔÎïÌåÔ˶¯µÄÓ°Ï족£®¼ÙÈç±ùÃæÉÏûÓÐ×èÁ¦£¬Ô˶¯µÄ±ù¿é½«
×öÔÈËÙÖ±ÏßÔ˶¯
×öÔÈËÙÖ±ÏßÔ˶¯
£®
£¨2£©ÈôÑ¡ÓôóС²»Í¬µÄ±ù¿é£¬ÔÙÔö¼ÓÒ»¸öľ¿é£¬ÓôËʵÑé×°Öû¹¿ÉÒÔ̽¾¿¶¯ÄÜ´óСÓë
ËÙ¶È
ËÙ¶È
ºÍ
ÖÊÁ¿
ÖÊÁ¿
µÄ¹Øϵ£®
£¨2010?±¾Ïª£©Èçͼ¼×Ëùʾ£¬ÊÇСºìÉè¼ÆµÄ²âÁ¿¶î¶¨µçѹΪ¡°3.8V¡±Ð¡µÆÅݵç×èµÄ²¿·ÖʵÑéµç·£¬ÈôµçÔ´µçѹΪ6V£¬Ð¡µÆÅݵĵç×è´óÔ¼ÊÇ10¦¸£¬Ð¡ºìÔÚÁ¬½ÓʵÑéµç·µÄ¹ý³ÌÖз¢ÏÖµçѹ±í0--15VÁ¿³ÌË𻵣¬Ö»ÓÐ0¡«3VµÄÁ¿³Ì¿ÉÒÔʹÓãº

£¨1£©ÈôСºìÏë²âСµÆÅÝÕý³£·¢¹âʱµÄµç×裬ÇëÓñʻ­Ïß´úÌæµ¼Ï߰ѵç·Á¬½ÓÍêÕû£®
£¨2£©ÊµÑéÖÐÓÐÁ½¸ö¿É¹©Ñ¡ÔñµÄ»¬¶¯±ä×èÆ÷·Ö±ðΪ¡°5¦¸  1A¡±¡°10¦¸  1A¡±£¬ÎªÁË˳ÀûÍê³ÉʵÑ飬СºìӦѡÔñ
¡°10¦¸ 1A¡±
¡°10¦¸ 1A¡±
µÄ±ä×èÆ÷×îΪºÏÊÊ£®
£¨3£©dxºìÔÚʵÑéµÄ¹ý³ÌÖУ®µ÷½Ú»¬¶¯±ä×èÆ÷ʹСµÆÅÝÕý³£·¢¹â£¬µçÁ÷±íµÄʾÊýÈçͼÒÒËùʾ£¬µçÁ÷±íµÄ¶ÁÊýΪ
0.3
0.3
A£¬Ð¡µÆÅÝÕý³£·¢¹âʱµÄµç×èΪ
12.7
12.7
¦¸£®¸ù¾ÝËù²âÊý¾ÝСºì»æÖÆÁËÈçͼ±ûËùʾµÄU-IͼÏó£¬Ôò
ÒÒ
ÒÒ
£¨Ìî¡°¼×¡±»ò¡°ÒÒ¡±£©ÊÇСµÆÅݵÄU-IͼÏó£¬Ô­ÒòÊÇ
µÆË¿µç×èËæζȵÄÉý¸ß¶øÔö´ó
µÆË¿µç×èËæζȵÄÉý¸ß¶øÔö´ó
£®
£¨4£©Ð¡ºì»¹Ïë̽¾¿¡°µ¼ÌåÖеĵçÁ÷Óëµ¼Ìåµç×衱µÄ¹Øϵ£¬ËýÉè¼ÆµÄµç·ͼÈçͼ¶¡Ëùʾ£º
¢ÙÈôСºì±ÕºÏ¿ª¹Øºó£¬·¢ÏÖµçÁ÷±íÎÞʾÊý£¬Óõçѹ±í·Ö±ð²âR1¡¢R2£¨R1¡ÙR2£©Á½¶ËµÄµçѹ£¬µçѹ±í²¢ÁªÔÚR1Á½¶ËʱÓÐʾÊý£¬²¢ÁªÔÚR2Á½¶ËʱÎÞʾÊý£¬Ôò´Ëµç··¢Éú¹ÊÕϵÄÔ­ÒòÊÇ
R1¶Ï·
R1¶Ï·
£®
¢ÚÅųý¹ÊÕϺó£¬Ð¡ºì·Ö±ðÓõçѹ±í²â³öÁËR1¡¢R2Á½¶ËµÄµçѹ£¬ÇëÄã²ÂÏ룺ͨ¹ýÒÔÉϲÙ×÷£¬ËýÄÜ̽¾¿³ö¡°µ¼ÌåÖеĵçÁ÷Óëµ¼Ìåµç×衱µÄ¹ØϵÂð£¿
²»ÄÜ
²»ÄÜ
£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©£¬Äã²ÂÏëµÄÒÀ¾ÝÊÇ
ÎÞ·¨¿ØÖÆR1¡¢R2Á½¶ËµÄµçѹÏàͬÇÒÎÞ·¨¸Ä±äµçÁ÷´óС
ÎÞ·¨¿ØÖÆR1¡¢R2Á½¶ËµÄµçѹÏàͬÇÒÎÞ·¨¸Ä±äµçÁ÷´óС
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø