题目内容

【题目】电阻R1=15Ω,R2=10Ω,R3=5Ω,下列连接电阻最小的是(
A.只能用R3
B.R1与R3并联
C.R2与R3并联
D.R1、R2与R3并联

【答案】D
【解析】解:因并联电路中总电阻的倒数等于各分电阻倒数之和,
所以,R1与R3并联时有 = + = + = ,解得R13=3.75Ω,
R2与R3并联时有 = + = + = ,解得R23≈3.33Ω,
R1、R2与R3并联时有 = + + = + + = ,解得R123≈2.73Ω,
综上可知,D选项的电阻最小.
故选D.
根据电阻的并联求出R1与R3并联、R2与R3并联、R1、R2与R3并联后的总电阻,然后与R3的阻值比较得出答案.

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