ÌâÄ¿ÄÚÈÝ
ÈçͼËùʾÊÇ·çÁ¦²âÁ¿Òǵĵç·ʾÒâͼ¡£ÆäµçÔ´µçѹU ="3" V£¬µç·±£»¤µç×èR1=10¦¸£¬¾ùÔȵç×èË¿µÄ×èֵΪR2=10¦¸£¬½ðÊôË¿£¨µç×èºöÂÔ²»¼Æ£©µÄÉ϶˹̶¨ÔÚOµã£¬Ï¶ËϵÓÐÒ»¿éËÜÁÏƬA£¬µ±·ç´ÓÓÒÏò×󴵶¯ËÜÁÏƬʱ£¬½ðÊôË¿Ïò×ó°Ú¶¯²¢Óëµç×èË¿±£³ÖÁ¼ºÃµÄ½Ó´¥£¬·çÁ¦±íÓɵçѹ±í¸Ä×°¶ø³É¡£
£¨l£©ÎÞ·çʱ£¬ËÜÁÏƬÊúֱϴ¹£¬µçѹ±íʾÊýÊǶàÉÙ£¿µç·ÖеĵçÁ÷ÊǶàÉÙ£¿
£¨2£©·çÁ¦×îǿʱ£¬½ðÊôË¿»¬ÖÁµç×èË¿µÄ×î×ó¶Ë£¬µçѹ±íµÄʾÊýÊǶàÉÙ£¿
£¨3£©ÎªÊ²Ã´²»ÔÚµç·Öд®ÁªµçÁ÷±í£¬°ÑµçÁ÷±í¸Ä×°³É·çÁ¦±í£¿
£¨l£©ÎÞ·çʱ£¬ËÜÁÏƬÊúֱϴ¹£¬µçѹ±íʾÊýÊǶàÉÙ£¿µç·ÖеĵçÁ÷ÊǶàÉÙ£¿
£¨2£©·çÁ¦×îǿʱ£¬½ðÊôË¿»¬ÖÁµç×èË¿µÄ×î×ó¶Ë£¬µçѹ±íµÄʾÊýÊǶàÉÙ£¿
£¨3£©ÎªÊ²Ã´²»ÔÚµç·Öд®ÁªµçÁ÷±í£¬°ÑµçÁ÷±í¸Ä×°³É·çÁ¦±í£¿
£¨1£©0V£» 0.15A£®£¨2£©1.5V£®£¨3£©ÒòΪÎÞÂÛ·çÁ¦´óС£¬½ÓÈëµç·ÖеÄ×ܵç×趼ûÓз¢Éú£¬µçÔ´µçѹһ¶¨£¬µç·ÖеĵçÁ÷Ò²¾Í²»»á·¢Éú¸Ä±ä£¬Òò´Ë½ÓÈëµçÁ÷±í²»¿ÉÐÐ
Óɵç·ͼ¿ÉÖª£¬R1ÓëR2´®Áª£¬µçѹ±í²âR2ÓҶ˽ÓÈëµç·µç×èµÄ×èÖµ£»ÎÞ·çʱ£¬µçѹ±í±»¶Ì·£¬¹ÊµçѹΪ0£»µç×èË¿Óë±£»¤µç×è´®Áª£¬ÓÉÅ·Ä·¶¨ÂÉ¿ÉÇóµÃµçÁ÷£»·çÁ¦×îǿʱ£¬½ðÊôË¿»¬µ½×î×ó¶Ëʱ£¬µçѹ±í²âR2Éϵĵçѹ£¬ÔòÓÉÅ·Ä·¶¨ÂÉ¿ÉÇóµçѹ±íµÄʾÊý£»Óɵç·ͼ¿ÉÖª£¬µç·Öеĵç×è²»±ä£¬¸ù¾ÝÅ·Ä·¶¨ÂÉ¿ÉÖªµç·ÖеĵçÁ÷²»±ä£¬ËùÒÔÎÞÂÛ·çÁ¦´óС£¬µçÁ÷±íµÄʾÊý²»±ä£®
½â:£¨1£©ÎÞ·çʱ£¬µçѹ±íʾÊýÊÇ0¡£ £¨1·Ö£©
¡ßR1 ¡¢R2´®Áª£¬
¡à £¨1·Ö£©
£¨1·Ö£©
£¨2£©·çÁ¦×îǿʱ£¬ËÜÁÏƬÔÚ×î×ó¶Ë¡£
I2=I=0.15A £¨1·Ö£©
£¨2·Ö£©
£¨3£©ÒòΪ·çÁ¦·¢Éú±ä»¯Ê±£¬ÎÞÂÛËÜÁÏƬÔں䦣¬µç·ÖеĵçÁ÷¶¼²»»á±ä»¯£¬ËùÒÔ²»ÔÚµç·Öд®ÁªµçÁ÷±í£¬°ÑµçÁ÷±í¸Ä×°³É·çÁ¦±í¡£ £¨2·Ö£©
½â:£¨1£©ÎÞ·çʱ£¬µçѹ±íʾÊýÊÇ0¡£ £¨1·Ö£©
¡ßR1 ¡¢R2´®Áª£¬
¡à £¨1·Ö£©
£¨1·Ö£©
£¨2£©·çÁ¦×îǿʱ£¬ËÜÁÏƬÔÚ×î×ó¶Ë¡£
I2=I=0.15A £¨1·Ö£©
£¨2·Ö£©
£¨3£©ÒòΪ·çÁ¦·¢Éú±ä»¯Ê±£¬ÎÞÂÛËÜÁÏƬÔں䦣¬µç·ÖеĵçÁ÷¶¼²»»á±ä»¯£¬ËùÒÔ²»ÔÚµç·Öд®ÁªµçÁ÷±í£¬°ÑµçÁ÷±í¸Ä×°³É·çÁ¦±í¡£ £¨2·Ö£©
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿