题目内容
计算:①
3 |
②
cos60° |
1+sin60° |
1 |
tan30° |
分析:分别把sin60°=cos30°=
,tan60°=
,cos60°=
,tan30°=1代入原式计算即可.
| ||
2 |
3 |
1 |
2 |
解答:解:①原式=
×
+
-2×(
)2
=
+
-
=
.
②原式=
+
=
+
=2-
+
=2.
3 |
| ||
2 |
3 |
| ||
2 |
=
3 |
2 |
3 |
3 |
2 |
=
3 |
②原式=
| ||||
1+
|
1 | ||||
|
=
| ||||
|
3 |
=2-
3 |
3 |
=2.
点评:本题比较简单,只要熟知特殊角度的三角函数值即可.
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