题目内容
计算:
-
.
1 |
x-3 |
6 |
x2-9 |
分析:将后面一个分式的分母因式分解,找公因式,再通分.
解答:解:原式=
-
=
=
.
1 |
x-3 |
6 |
(x+3)(x-3) |
=
x+3-6 |
(x+3)(x-3) |
=
1 |
x+3 |
点评:本题考查了分式的加减运算.关键是将分母因式分解,找公因式通分.
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题目内容
1 |
x-3 |
6 |
x2-9 |
1 |
x-3 |
6 |
(x+3)(x-3) |
x+3-6 |
(x+3)(x-3) |
1 |
x+3 |