题目内容
若单项式3ab4n+1与9ab(2n+2)―1是同类项,则n的值是
- A.7
- B.2
- C.0
- D.-1
C
∵单项式3ab4n+1与9ab(2n+2)-1是同类项,
∴4n+1=(2n+2)-1,
∴4n+1=2n+2-1,
移项得:2n=0
∴n=0,
故选C.
∵单项式3ab4n+1与9ab(2n+2)-1是同类项,
∴4n+1=(2n+2)-1,
∴4n+1=2n+2-1,
移项得:2n=0
∴n=0,
故选C.
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