题目内容

先化简,再求值:
(1)
2a2-8
a2-4a+4
,其中a=1;
(2)
ab-3a2
-b2+6ab-9a2
,其中b=2a.
(1)
2a2-8
a2-4a+4

=
2(a+2)(a-2)
(a-2)2

=
2(a+2)
a-2

当a=1时,上式=
2×3
3-2
=6,即
2a2-8
a2-4a+4
=6;

(2)
ab-3a2
-b2+6ab-9a2

=
a(b-3a)
-(b-3a)2

=-
a
b-3a

当b=2a时,上式=-
a
2a-3a
=1,即
ab-3a2
-b2+6ab-9a2
=1.
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网