题目内容
已知
=
≠0,求代数式
•(a-2b)的值.
a |
2 |
b |
3 |
5a-2b |
a2-4b2 |
5a-2b |
a2-4b2 |
=
5a-2b |
(a+2b)(a-2b) |
=
5a-2b |
a+2b |
∵
a |
2 |
b |
3 |
2 |
3 |
∴原式=
| ||
|
10b-6b |
2b+6b |
4b |
8b |
1 |
2 |
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题目内容
a |
2 |
b |
3 |
5a-2b |
a2-4b2 |
5a-2b |
a2-4b2 |
5a-2b |
(a+2b)(a-2b) |
5a-2b |
a+2b |
a |
2 |
b |
3 |
2 |
3 |
| ||
|
10b-6b |
2b+6b |
4b |
8b |
1 |
2 |