题目内容
(2013•绥化)计算:
-
=
.
1 |
x-1 |
1 |
x2-1 |
x |
x2-1 |
x |
x2-1 |
分析:首先通分,然后根据同分母的分式加减运算法则求解即可求得答案.注意运算结果需化为最简.
解答:解:
-
=
-
=
=
=
.
故答案为:
.
1 |
x-1 |
1 |
x2-1 |
=
x+1 |
(x+1)(x-1) |
1 |
(x+1)(x-1) |
=
x+1-1 |
(x+1)(x-1) |
=
x |
(x+1)(x-1) |
=
x |
x2-1 |
故答案为:
x |
x2-1 |
点评:此题考查了分式的加减运算法则.此题比较简单,注意运算要细心,注意运算结果需化为最简.
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