题目内容
已知ab≠0,那么
+
=______.
a |
|a| |
b |
|b| |
∵ab≠0,
∴①a>0,b>0,
+
=2;
②a<0,b<0,
+
=-2,
③a>0,b<0,
+
=0.
④a<0,b>0,
+
=0,
故答案为:2或-2或0.
∴①a>0,b>0,
a |
|a| |
b |
|b| |
②a<0,b<0,
a |
|a| |
b |
|b| |
③a>0,b<0,
a |
|a| |
b |
|b| |
④a<0,b>0,
a |
|a| |
b |
|b| |
故答案为:2或-2或0.
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