题目内容
(8分)某手机专营店代理销售A、B两种型号手机.手机的进价、售价如下表:
(1)第一季度:用36000元购进A、B两种型号的手机,全部售完后获利6300元,求第一季度购进A、B两种型号手机的数量;
小题1:(2)第二季度:计划购进A、B两种型号手机共34部,且不超出第一季度的购机总费用,则A型号手机最多能购多少部?
型 号 | A | B |
进 价 | 1200元/部 | 1000元/部 |
售 价 | 1380元/部 | 1200元/部 |
(1)第一季度:用36000元购进A、B两种型号的手机,全部售完后获利6300元,求第一季度购进A、B两种型号手机的数量;
小题1:(2)第二季度:计划购进A、B两种型号手机共34部,且不超出第一季度的购机总费用,则A型号手机最多能购多少部?
小题1:(1)解:设该专营店第一季度购进A、B两种型号手机的数量分别为x部和y部. 1分
由题意可知:·························································· 3分
解得:
答:该专营店本次购进A、B两种型号手机的数分别为15部和18部.····················· 4分
小题2:(2)解:设第二季度购进A型号手机a部.········································ 5分
由题意可知:1200a+1000(34-a)≤36000,····················································· 6分
解得:a≤10··························································································· 7分
不等式的最大整数解为10
答:第二季度最多能购A型号手机10部.······················································· 8分
略
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