题目内容
先化简,再求值.
(1) (6分)
,其中
.
(2) (6分)已知
,求
的值
(1) (6分)
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(2) (6分)已知


(1)(6分)解:原式
… …1分
… …2分
… …3分
… …4分
把
代入
中,有
… …6分
(2)(6分)解:
… …2分
… …4分
∴把
代入,有
=
… …6分




把


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(2)(6分)解:



∴把



(1)先利用完全平方公式与平方差公式将原式化简,再代入数值计算即可解答.
(2)利用根式的基本性质将原式化简,再通分,最后代入数值计算即可解答.
(2)利用根式的基本性质将原式化简,再通分,最后代入数值计算即可解答.

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