题目内容
用“>”、“<”、“=”填空
(1)?0.02 1 (2) - -
(3)?(? ) ?[+(?0.75)]
(1)?0.02 1 (2) - -
(3)?(? ) ?[+(?0.75)]
(1)< (2)< (3)=
根据正数大于负数,负数的绝对值越大则负数越小可判断出(1)(2)(3)的大小
(1)-0.02<1;
(2)|- |= ,|- |=, > ,
∴- <- ;
(3)-(- )=,-[+(-0.75)]= ,
∴-(- )=-[+(-0.75)]
(1)-0.02<1;
(2)|- |= ,|- |=, > ,
∴- <- ;
(3)-(- )=,-[+(-0.75)]= ,
∴-(- )=-[+(-0.75)]
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