题目内容
计算:2x |
x+y |
x-y |
x+y |
分析:根据同分母的分式的加减运算法则求解即可求得答案,注意结果要化为最简.
解答:解:
-
=
=
=1.
故答案为:1.
2x |
x+y |
x-y |
x+y |
2x-x+y |
x+y |
x+y |
x+y |
故答案为:1.
点评:此题考查了同分母分式的加减运算法则.此题比较简单,解题需细心,注意结果要化为最简.
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目
题目内容
计算:2x |
x+y |
x-y |
x+y |
2x |
x+y |
x-y |
x+y |
2x-x+y |
x+y |
x+y |
x+y |