题目内容
(2011广东广州市,19,10分)分解因式8(x2-2y2)-x(7x+y)+xy.
8(x2-2y2)-x(7x+y)+xy
=8x2-16y2-7x2-xy+xy
=x2-16y2
=(x+4y)(x-4y)
=8x2-16y2-7x2-xy+xy
=x2-16y2
=(x+4y)(x-4y)
分析:首先利用多项式乘以多项式法则进行计算,然后移项,合并同类项,正好符合平方差公式,再运用公式法分解因式即可解答.
解答:解:原式=8x2-16y2-7x2-xy+xy
=x2-16y2
=(x+4y)(x-4y).
解答:解:原式=8x2-16y2-7x2-xy+xy
=x2-16y2
=(x+4y)(x-4y).
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