题目内容
(1)2×(-5)+23-3÷12;
(2)1
×[3×(-
)2-1]-
×(-2)3;
(3)x-
=2-
;
(4)
[x-
(x-1)]=
(2x+1).
(2)1
1 |
2 |
2 |
3 |
1 |
3 |
(3)x-
x-1 |
2 |
x+2 |
3 |
(4)
1 |
2 |
1 |
3 |
3 |
4 |
(1)原式=-10+8-4
=-6;
(2)原式=
×[3×
-1]-
×(-8)
=
×[
-1]+
=
×
+
=
+
=
;
(3)x-
=2-
6x-3(x-1)=12-2(x+2)
6x-3x+3=12-2x-4
6x-3x+2x=12-4-3
5x=5
x=1;
(4)
[x-
(x-1)]=
(2x+1)
x-
(x-1)=3x+
6x-2x+2=18x+9
6x-2x-18x=9-2
-14x=7
x=-
.
=-6;
(2)原式=
3 |
2 |
4 |
9 |
1 |
3 |
=
3 |
2 |
4 |
3 |
8 |
3 |
=
3 |
2 |
1 |
3 |
8 |
3 |
=
1 |
2 |
8 |
3 |
=
19 |
6 |
(3)x-
x-1 |
2 |
x+2 |
3 |
6x-3(x-1)=12-2(x+2)
6x-3x+3=12-2x-4
6x-3x+2x=12-4-3
5x=5
x=1;
(4)
1 |
2 |
1 |
3 |
3 |
4 |
x-
1 |
3 |
3 |
2 |
6x-2x+2=18x+9
6x-2x-18x=9-2
-14x=7
x=-
1 |
2 |
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