题目内容
已知多项式ax5+bx3+cx-1,当x=1时值为4,那么该多项式当x=-1时的值为 .
-6
∵ax5+bx3+cx-1,当x=1时值为4,
∴a+b+c=5,
∵x=-1,
∴ax5+bx3+cx-1=-a-b-c-1
=-(a+b+c)-1
=-5-1
=-6.
∴a+b+c=5,
∵x=-1,
∴ax5+bx3+cx-1=-a-b-c-1
=-(a+b+c)-1
=-5-1
=-6.
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