题目内容
如右图，在△ABC中，AC = BC，D是BC边上一点，且AB=AD=DC，则∠C=_________°
36解析:
AD="DC," 
∠C=∠DAC, ∠ADB=∠C+∠DAC, ∠ADB=2∠C AB="AD," AC =" BC" ∠B=∠BAC=∠ADB=2∠C, ∠B+∠BAC+∠C=180°∠C=36°
AD="DC," ∠C=∠DAC, ∠ADB=∠C+∠DAC, ∠ADB=2∠C AB="AD," AC =" BC" ∠B=∠BAC=∠ADB=2∠C, ∠B+∠BAC+∠C=180°∠C=36° 
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