题目内容
计算:
(1)(1+
)÷
(2)
-a-1.
(1)(1+
1 |
x |
x2-1 |
x |
(2)
a2 |
a-1 |
(1)原式=
•
=
;
(2)原式=
=
.
x+1 |
x |
x |
(x+1)(x-1) |
1 |
x-1 |
(2)原式=
a2-(a+1)(a-1) |
a-1 |
1 |
a-1 |
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题目内容
1 |
x |
x2-1 |
x |
a2 |
a-1 |
x+1 |
x |
x |
(x+1)(x-1) |
1 |
x-1 |
a2-(a+1)(a-1) |
a-1 |
1 |
a-1 |