题目内容
计算:
(1)(
×103)2×(
×104)
(2)t3-2t[t2-2t(t-3)]
(3)(2a+b)(b-2a)-(a-3b)2
(4)-5x(-x2+2x+1)-(2x+3)(5-x2)
(1)(
6 |
5 |
1 |
2 |
(2)t3-2t[t2-2t(t-3)]
(3)(2a+b)(b-2a)-(a-3b)2
(4)-5x(-x2+2x+1)-(2x+3)(5-x2)
(1)原式=
×106×
×104=
×1010;
(2)原式=t3-2t(t2-2t2+6t)=t3-2t3+4t3-12t2=3t3-12t2;
(3)原式=b2-4a2-a2+6ab-9b2=-5a2+6ab-8b2;
(4)原式=5x3-10x2-5x-(10x-2x3+15-3x2)=5x3-10x2-5x-10x+2x3-15+3x2=7x3-7x2-15x-15.
36 |
25 |
1 |
2 |
18 |
25 |
(2)原式=t3-2t(t2-2t2+6t)=t3-2t3+4t3-12t2=3t3-12t2;
(3)原式=b2-4a2-a2+6ab-9b2=-5a2+6ab-8b2;
(4)原式=5x3-10x2-5x-(10x-2x3+15-3x2)=5x3-10x2-5x-10x+2x3-15+3x2=7x3-7x2-15x-15.
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