题目内容

观察下列等式:a1=
1
1×2×3
+
1
2
=
2
1×3
a2=
1
2×3×4
+
1
3
=
3
2×4
a3=
1
3×4×5
+
1
4
=
4
3×5

(1)猜想并写出第n个等式;
(2)证明你猜想的正确性.
分析:(1)通过观察得出规律后即可写出第n个等式;
(2)先对分式的左边通分,再相加后即可证出猜想的正确性.
解答:解:(1)an=
1
n(n+1)(n+2)
+
1
n+1
=
n+1
n(n+2)

 
(2)证明:左边=
1
n(n+1)(n+2)
+
n(n+2)
n(n+1)(n+2)

=
1+n(n+2)
n(n+1)(n+2)
 
=
n2+2n+1
n(n+1)(n+2)
=
(n+1)2
n(n+1)(n+2)
=
n+1
n(n+2)
=右边
1
n(n+1)(n+2)
+
1
n+1
=
n+1
n(n+2)
点评:此题考查了分式的加减,关键是能通过观察找出规律,并用式子表示出来.
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