题目内容
如图,数轴上A、B两点对应的实数分别为
,b, 则下列结论不正确的是
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A.
B.
C.
D.|
|—|b|>0
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A.
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D
解:根据题意,得-1<a<0,1<b<2,
A、0<a+b<2;不等式两边同时相加,不等式符号不变,故A正确;
B、-2<ab<-1,不等式两边同时乘以负数,不等式符号改变,故B正确;
C、∵-2<-b<-1,不等式两边同乘以负数,不等式符号改变,
∴-3<a-b<-1<0,故C正确;
D、由上式得0<|a|<1,1<|b|<2,
∴|a|<|b|,即a|-|b|<0,故D错误.
故选D.
A、0<a+b<2;不等式两边同时相加,不等式符号不变,故A正确;
B、-2<ab<-1,不等式两边同时乘以负数,不等式符号改变,故B正确;
C、∵-2<-b<-1,不等式两边同乘以负数,不等式符号改变,
∴-3<a-b<-1<0,故C正确;
D、由上式得0<|a|<1,1<|b|<2,
∴|a|<|b|,即a|-|b|<0,故D错误.
故选D.
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