题目内容
化简:
(1)(
-
)0-(-
)-2
(2)(m-3n)-2•(2m-2n-3)-2
(3)a-2b2•(-2a2b-2)-2÷(a-4b2)
(4)(2m2n-3)3(-mn-2)-2.
(1)(
3 |
2 |
1 |
2 |
(2)(m-3n)-2•(2m-2n-3)-2
(3)a-2b2•(-2a2b-2)-2÷(a-4b2)
(4)(2m2n-3)3(-mn-2)-2.
(1)(
-
)0-(-
)-2
=1-4
=-3;
(2)(m-3n)-2•(2m-2n-3)-2
=m6n-2•2-2m4n6
=
m6+4n-2+6
=
m10n4;
(3)a-2b2•(-2a2b-2)-2÷(a-4b2)
=a-2b2•(-2)-2a-4b4÷(a-4b2)
=
a-2-4-(-4)b2+4-2
=
a-2b4
=
;
(4)(2m2n-3)3(-mn-2)-2
=23m6n-9(-m)-2n4
=8m6-2n-9+4
=8m4n-5
=
.
3 |
2 |
1 |
2 |
=1-4
=-3;
(2)(m-3n)-2•(2m-2n-3)-2
=m6n-2•2-2m4n6
=
1 |
4 |
=
1 |
4 |
(3)a-2b2•(-2a2b-2)-2÷(a-4b2)
=a-2b2•(-2)-2a-4b4÷(a-4b2)
=
1 |
4 |
=
1 |
4 |
=
b4 |
4a2 |
(4)(2m2n-3)3(-mn-2)-2
=23m6n-9(-m)-2n4
=8m6-2n-9+4
=8m4n-5
=
8m4 |
n5 |

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