ËÑË÷
ÌâÄ¿ÄÚÈÝ
ÏÂÃæ×ó±ßÊý¾ÝÊÇÈ¡×ÔijÕý³£ÈËÔÄòºÍÄòÒºµÄÑùÆ·£¬ÓÒͼÊÇÉöµ¥Î»½á¹¹Ä£Ê½Í¼£®Çë¸ù¾Ý±í¸ñºÍʾÒâͼ»Ø´ðÎÊÌ⣮
ÎïÖÊ
ÑùÆ·A£¨g/L£©
ÑùÆ·B£¨g/L£©
ÆÏÌÑÌÇ
ÎÞ»úÑÎ
µ°°×ÖÊ
ÄòËØ
Ѫϸ°û
0
16.0
0
2.0
ÎÞ
1.0
7.5
0
0.3
ÎÞ£¨1£©¾Ý×ó±í·ÖÎö£¬ÔÄòÊÇÑùÆ·
B
B
£¨Ìî¡°A¡±»ò¡°B¡±£©£¬´æÔÚÓÚͼÖеÄ
4
4
ÖУ®
£¨2£©ÄòÒºÊÇÔÄò¾ÓÒͼÖÐ
6
6
µÄÖØÎüÊÕºóÐγɵģ¬ÖØÎüÊÕµÄÎïÖÊ°üÀ¨È«²¿µÄ
ÆÏÌÑÌÇ
ÆÏÌÑÌÇ
£¬´ó²¿·ÖµÄË®ºÍ²¿·ÖÎÞ»úÑΣ®Í¼ÖÐ4¡¢5¡¢6ºÏ³Æ
Éöµ¥Î»
Éöµ¥Î»
£®
£¨3£©ÈôÄòÒºÖлá³öÏÖѪϸ°ûºÍ´ó·Ö×Ó
µ°°×ÖÊ
µ°°×ÖÊ
£¬Ôò˵Ã÷
ÉöСÇò
ÉöСÇò
ͨ͸ÐÔ±ä´ó£®
ÊÔÌâ´ð°¸
Ïà¹ØÁ·Ï°²á´ð°¸
·ÖÎö£º
´ËÌ⿼²éµÄ֪ʶµãÊÇÄòµÄÐγɣ®¿ÉÒÔ´ÓÉöСÇòµÄ¹ýÂË×÷ÓúÍÉöС¹ÜµÄÖØÎüÊÕ×÷ÓõÄÌص㷽ÃæÀ´ÇÐÈ룮ÔÚÓÒͼÖÐ1ÊÇÈëÇòС¶¯Âö£¬2ÊdzöÇòС¶¯Âö£¬3ÊÇÉöС¹ÜÖÜΧµÄëϸѪ¹Ü£¬4ÊÇÉöСÄÒÇ»£¬5ÊÇÉöСÇò£¬6ÊÇÉöС¹Ü£®
½â´ð£º
½â£ºÄòµÄÐγɹý³ÌÖ÷Òª°üÀ¨ÉöСÇòµÄÂ˹ý×÷Óá¢ÉöС¹ÜµÄÖØÎüÊÕ×÷ÓÃÁ½¸ö¹ý³Ì£ºµ±ÑªÒºÁ÷¾ÉöСÇòʱ£¬³ýÁËѪϸ°ûºÍ´ó·Ö×ӵĵ°°×ÖÊÍ⣬Ѫ½¬ÖеÄÒ»²¿·ÖË®¡¢ÎÞ»úÑΡ¢ÆÏÌÑÌǺÍÄòËصÈÎïÖÊ£¬¶¼¿ÉÒÔ¾¹ýÉöСÇòÂ˹ýµ½ÉöСÄÒÄÚ£¬ÐγÉÔÄò£»µ±ÔÄòÁ÷¾ÉöС¹Üʱ£¬ÆäÖжÔÈËÌåÓÐÓõÄÎïÖÊ£¬°üÀ¨´ó²¿·ÖË®¡¢È«²¿ÆÏÌÑÌǺͲ¿·ÖÎÞ»úÑΣ¬±»ÉöС¹ÜÖØÐÂÎüÊÕ£¬²¢ÇÒ½øÈë°üÈÆÔÚÉöС¹ÜÍâÃæµÄëϸѪ¹ÜÖУ¬ÖØлص½ÑªÒºÀʣϵÄÎïÖÊÐγÉÄòÒºÅųöÌåÍ⣮
£¨1£©ÔÄòλÓÚ[4]ÉöСÄÒÇ»ÖУ¬ÓÉÓÚ[5]ÉöСÇò²»ÄܹýÂË´ó·Ö×Óµ°°×ÖʺÍѪϸ°û£¬Òò´ËÔÄòÖÐûÓÐѪϸ°ûºÍµ°°×ÖÊ£¬ÓÐÆÏÌÑÌÇ£»ÔÄòÁ÷¾ÉöС¹ÜʱÆÏÌÑÌDZ»[6]ÉöС¹ÜÈ«²¿ÖØÎüÊÕ£¬Òò´ËÄòÒºÖÐûÓе°°×ÖÊ¡¢ÑªÏ¸°û¡¢Ã»ÓÐÆÏÌÑÌÇ£®Òò´ËÔÄòÑùÆ·ÊÇB£¬ÑùÆ·AÊÇÄòÒº£®
£¨2£©µ±ÔÄòÁ÷¾[6]ÉöС¹Üʱ£¬´ó²¿·ÖµÄË®¡¢È«²¿µÄÆÏÌÑÌǺͲ¿·ÖÎÞ»úÑλᱻÖØÎüÊÕ½øÈë[3]ÖеÄѪҺ£®Éöµ¥Î»ÊÇÉöÔà½á¹¹ºÍ¹¦ÄܵĻù±¾µ¥Î»£¬ÓÉ[6]ÉöС¹ÜºÍÉöСÌå×é³É£¬ÉöСÌåÓÉ[5]ÉöСÇòºÍ[4]ÉöСÄÒ×é³É£®Òò´ËͼÖÐ[4][5][6]ºÏ³ÆΪÉöµ¥Î»£®
£¨3£©ÈôÄòÒºÖгöÏÖµ°°×ÖʺÍѪϸ°û£¬ÄÇÊÇÒòΪÉöµ¥Î»µÄ[5]ÉöСÇò·¢Éú²¡±ä£®Ê¹ÉöСÇòµÄͨ͸ÐÔÔö´ó£¬ÔÀ´²»ÄܹýÂ˵ĵ°°×ÖʺÍѪϸ°ûÒ²ÄܹýÂ˵½ÔÄòÖУ¬ÔÄòÁ÷¾ÉöС¹ÜʱÉöС¹Ü²»ÄÜÖØÎüÊÕµ°°×ÖʺÍѪϸ°û£¬Òò´ËÄòÖгöÏÖµ°°×ÖʺÍѪϸ°û£®
¹Ê´ð°¸Îª£º
£¨1£©B£»4
£¨2£©6£¬ÆÏÌÑÌÇ£»Éöµ¥Î»£»
£¨3£©ÉöСÇò
µãÆÀ£º
ÕýÈ··ÖÎö±í¸ñÖеÄÊý¾ÝÕÒ³öÖ÷Òª²»Í¬µã£¬Àí½âÉöµ¥Î»½á¹¹Ä£Ê½Í¼¸÷²¿·ÖËù´ú±íµÄ½á¹¹¼°¹¦ÄÜÊǽâ´ð´ËÌâµÄ¹Ø¼ü
Á·Ï°²áϵÁдð°¸
ÐÂÁì³ÌϵÁдð°¸
ÓÅ¿ÎÌøøÁ¦A¼ÓϵÁдð°¸
Ì츮ÊýѧϵÁдð°¸
Ì츮ǰÑØϵÁдð°¸
ÎÄ¿Æ°®ºÃÕßϵÁдð°¸
Àí¿Æ°®ºÃÕßϵÁдð°¸
ÐÂѧ°¸Í¬²½µ¼ÓëÁ·ÏµÁдð°¸
Ãûʦ´ó¿ÎÌÃϵÁдð°¸
351¸ßЧ¿ÎÌõ¼Ñ§°¸ÏµÁдð°¸
×´Ôª³É²Å·״Ԫµ¼Á·ÏµÁдð°¸
Ïà¹ØÌâÄ¿
£¨2011?ȪÖÝÖʼ죩ÏÂÃæ×ó±ßÊý¾ÝÊÇÈ¡×ÔijÕý³£ÈËÔÄòºÍÄòÒºµÄÑùÆ·£¬Í¼ÊÇÉöµ¥Î»½á¹¹Ä£Ê½Í¼£®Çë¸ù¾Ý±í¸ñºÍʾÒâͼ»Ø´ðÎÊÌ⣮£¨¡°[]¡±ÖÐÌîдÐòºÅ£¬¡°
4
4
¡±ÄÚÌîдÎÄ×Ö£®£©
ÎïÖÊ
ÑùÆ·A£¨g/L£©
ÑùÆ·B£¨g/L£©
ÆÏÌÑÌÇ
ÎÞ»úÑÎ
µ°°×ÖÊ
ÄòËØ
Ѫϸ°û
0
16.0
0
2.0
ÎÞ
1.0
7.5
0
0.3
ÎÞ£¨1£©¸ù¾Ý×ó±ß±íÄÚÊý¾Ý·ÖÎö£¬ÔÄòÊÇ
ÑùÆ·B
ÑùÆ·B
£¨Ìî¡°ÑùÆ·A¡±»ò¡°ÑùÆ·B¡±£©£¬´æÔÚÓÚÓÒͼÖеÄ[]ÉöСÄÒÇ»ÖУ®
£¨2£©ÄòÒºÊÇÔÄò¾ÓÒͼÖÐÉöС¹ÜµÄÖØÎüÊÕºóÐγɵģ¬ÖØÎüÊÕµÄÎïÖÊ°üÀ¨È«²¿µÄ
ÆÏÌÑÌÇ
ÆÏÌÑÌÇ
£¬´ó²¿·ÖµÄË®ºÍ²¿·Ö
ÎÞ»úÑÎ
ÎÞ»úÑÎ
£®Í¼ÖÐ[4][5][6]ºÏ³ÆΪ
Éöµ¥Î»
Éöµ¥Î»
£®
£¨3£©Èô[5]ÉöСÇòÓÐÑ×Ö¢£¬ÄòÒºÖлá³öÏÖѪϸ°ûºÍ´ó·Ö×Ó
µ°°×ÖÊ
µ°°×ÖÊ
£»Èô
ÒȵºËØ
ÒȵºËØ
·ÖÃÚµÄÒȵºËز»×㣬ÄòÒºÖлá³öÏÖÆÏÌÑÌÇ£®
£¨4£©´úл·ÏÎïÖеÄÄòËسýÁËÒÔÄòÒºÐÎʽÅųöÍ⣬»¹¿ÉÒÔͨ¹ýƤ·ôÒÔ
º¹Òº
º¹Òº
ÐÎʽÅųö£®
ÏÂÃæ×ó±ßÊý¾ÝÊÇÈ¡×ÔijÕý³£ÈËÔÄòºÍÄòÒºµÄÑùÆ·£¬Í¼ÊÇÉöµ¥Î»½á¹¹Ä£Ê½Í¼£®Çë¸ù¾Ý±í¸ñºÍʾÒâͼ»Ø´ðÎÊÌ⣮£¨¡°[]¡±ÖÐÌîдÐòºÅ£¬¡°
1
1
¡±ÄÚÌîдÎÄ×Ö£®£©
ÎïÖÊ
ÑùÆ·A
£¨g/L£©
ÑùÆ·B
£¨g/L£©
ÆÏÌÑÌÇ
ÎÞ»úÑÎ
µ°°×ÖÊ
ÄòËØ
Ѫϸ°û
0
16.0
0
2.0
ÎÞ
1.0
7.5
0
0.3
ÎÞ£¨1£©¸ù¾Ý±íÄÚÊý¾Ý·ÖÎö£¬ÔÄòÊÇ
ÑùÆ·B
ÑùÆ·B
£¨Ìî¡°ÑùÆ·A¡±»ò¡°ÑùÆ·B¡±£©£®
£¨2£©ÄòÒºÊÇÔÄò¾Í¼ÖÐ[
5
5
]ÉöС¹ÜµÄÖØÎüÊÕºóÐγɵģ¬ÖØÎüÊÕµÄÎïÖÊ°üÀ¨È«²¿µÄ
ÆÏÌÑÌÇ
ÆÏÌÑÌÇ
£¬´ó²¿·ÖµÄ
Ë®
Ë®
ºÍ²¿·ÖÎÞ»úÎ
£¨3£©Èô[3]ÉöСÇòÓÐÑ×Ö¢£¬ÄòÒºÖлá³öÏÖѪϸ°ûºÍ´ó·Ö×Ó
µ°°×ÖÊ
µ°°×ÖÊ
£»ÈôÒȵºËØ·ÖÃÚ²»×㣬ÄòÒºÖлá³öÏÖ
ÆÏÌÑÌÇ
ÆÏÌÑÌÇ
£®
£¨2012?ȪÖÝ£©ÏÂÃæ×ó±ßÊý¾ÝÊÇÈ¡×ÔijÕý³£ÈËÔÄòºÍÄòÒºµÄÑùÆ·£¬ÓÒͼÊÇÉöµ¥Î»½á¹¹Ä£Ê½Í¼£®Çë¸ù¾Ý±í¸ñºÍʾÒâͼ»Ø´ðÎÊÌ⣮£¨¡°[]¡±ÖÐÌîдÐòºÅ£¬¡°___¡±ÄÚÌîдÎÄ×Ö£®£©
ÎïÖÊ
ÑùÆ·A£¨g/L£©
ÑùÆ·B£¨g/L£©
ÆÏÌÑÌÇ
0
1.0
ÎÞ»úÑÎ
16.0
7.5
µ°°×ÖÊ
0
0
ÄòËØ
2.0
0.3
Ѫϸ°û
ÎÞ
ÎÞ£¨1£©¸ù¾Ý×ó±ß±íÄÚÊý¾Ý·ÖÎö£¬ÔÄòÊÇ
ÑùÆ·B
ÑùÆ·B
£¨Ìî¡°ÑùÆ·A¡±»ò¡°ÑùÆ·B¡±£©£¬´æÔÚÓÚÓÒͼÖеÄ[
4
4
]ÉöСÄÒÇ»ÖУ®
£¨2£©ÄòÒºÊÇÔÄò¾ÓÒͼÖÐ[
6
6
]ÉöС¹ÜµÄÖØÎüÊÕºóÐγɵģ¬ÖØÎüÊÕµÄÎïÖÊ°üÀ¨È«²¿µÄ
ÆÏÌÑÌÇ
ÆÏÌÑÌÇ
£¬´ó²¿·ÖµÄ
Ë®
Ë®
ºÍ²¿·ÖÎÞ»úÎ
£¨3£©Èô[5]ÉöСÇòÓÐÑ×Ö¢£¬ÄòÒºÖлá³öÏÖѪϸ°ûºÍ´ó·Ö×Ó
µ°°×ÖÊ
µ°°×ÖÊ
£»Èô
Òȵº
Òȵº
·ÖÃÚµÄÒȵºËز»×㣬ÄòÒºÖлá³öÏÖ
ÆÏÌÑÌÇ£¨¡°ÌÇÄò¡±Ò²¸ø·Ö£©
ÆÏÌÑÌÇ£¨¡°ÌÇÄò¡±Ò²¸ø·Ö£©
£®
ÏÂÃæ×ó±ßÊý¾ÝÊÇÈ¡×ÔijÕý³£ÈËÔÄòºÍÄòÒºµÄÑùÆ·£¬ÓÒͼÊÇÉöµ¥Î»½á¹¹Ä£Ê½Í¼£®Çë¸ù¾Ý±í¸ñºÍʾÒâͼ»Ø´ðÎÊÌ⣮
ÎïÖÊ
ÑùÆ·A£¨g/L£©
ÑùÆ·B£¨g/L£©
ÆÏÌÑÌÇ
0
1.0
ÎÞ»úÑÎ
16.0
7.5
µ°°×ÖÊ
0
0
ÄòËØ
2.0
0.3
Ѫϸ°û
ÎÞ
ÎÞ£¨1£©¾Ý×ó±í·ÖÎö£¬ÔÄòÊÇÑùÆ·
B
B
£¨Ìî¡°A¡±»ò¡°B¡±£©£¬´æÔÚÓÚÓÒͼÖеÄ
[4]ÉöСÄÒ
[4]ÉöСÄÒ
ÖУ®
£¨2£©ÄòÒºÊÇÔÄò¾ÓÒͼÖÐ
[6]ÉöС¹Ü
[6]ÉöС¹Ü
µÄÖØÎüÊÕºóÐγɵģ¬ÖØÎüÊÕµÄÎïÖÊ°üÀ¨È«²¿
µÄ
ÆÏÌÑÌÇ
ÆÏÌÑÌÇ
£¬´ó²¿·ÖµÄË®ºÍ²¿·ÖÎÞ»úÑΣ®Í¼ÖÐ[4]¡¢[5]¡¢[6]ºÏ³ÆΪ
Éöµ¥Î»
Éöµ¥Î»
£®
£¨3£©ÈôÄòÒºÖлá³öÏÖѪϸ°ûºÍ´ó·Ö×Ó
µ°°×ÖÊ
µ°°×ÖÊ
£¬Ôò˵Ã÷
ÉöСÇò
ÉöСÇò
ͨ͸ÐÔ±ä´ó£®
£¨4£©ÓÒͼÖеĢÙÊÇ
ÈëÇòС¶¯Âö
ÈëÇòС¶¯Âö
£¬Á÷
¶¯Âö
¶¯Âö
Ѫ£®
ÏÂÃæ×ó±ßÊý¾ÝÊÇÈ¡×ÔijÕý³£ÈËÔÄòºÍÄòÒºµÄÑùÆ·£¬ÓÒͼÊÇÉöµ¥Î»½á¹¹Ä£Ê½Í¼£®Çë»Ø´ð£®
ÎïÖÊ
ÆÏÌÑÌÇ
ÎÞ»úÑÎ
µ°°×ÖÊ
ÄòËØ
Ѫϸ°û
ÑùÆ·A£¨g/L£©
0
16.0
0
2.0
ÎÞ
ÑùÆ·B£¨g/L£©
1.0
7.5
0
0.3
ÎÞ£¨1£©¸ù¾Ý×ó±ß±íÄÚÊý¾Ý·ÖÎö£¬ÔÄòÊÇ
ÑùÆ·B
ÑùÆ·B
£¨Ìî¡°ÑùÆ·A¡±»ò¡°ÑùÆ·B¡±£©£¬´æÔÚÓÚͼÖеÄ
4
4
ÉöСÄÒÇ»ÖУ®
£¨2£©µ±ÑªÒºÁ÷¾5ʱ£¬Ñª½¬ÖеĴ󲿷ÖË®¡¢ÎÞ»úÑΡ¢ÆÏÌÑÌǼ°ÄòËصÈÎïÖÊͨ¹ý
ÉöСÇòÂ˹ý
ÉöСÇòÂ˹ý
µ½ÉöСÄÒÖÐÐγÉÔÄò£®Í¼ÖÐ6 ´¦µÄ¼¸¸öÏòÉϵļýÍ·µÄº¬ÒåÊÇ
ÉöС¹ÜµÄÖØÎüÊÕ×÷ÓÃ
ÉöС¹ÜµÄÖØÎüÊÕ×÷ÓÃ
£®Í¼ÖТܢݢ޺ϳÆ
Éöµ¥Î»
Éöµ¥Î»
£®
£¨3£©ÔÄòºÍÄòÒºÏà±È£¬ÄòÒºÖв»º¬
ÆÏÌÑÌÇ
ÆÏÌÑÌÇ
£¬Èô[5]ÉöСÇòÓÐÑ×Ö¢£¬ÄòÒºÖлá³öÏÖѪϸ°ûºÍ´ó·Ö×Ó
µ°°×ÖÊ
µ°°×ÖÊ
£®
¹Ø ±Õ
ÊÔÌâ·ÖÀà
¸ßÖÐ
Êýѧ
Ó¢Óï
ÎïÀí
»¯Ñ§
ÉúÎï
µØÀí
³õÖÐ
Êýѧ
Ó¢Óï
ÎïÀí
»¯Ñ§
ÉúÎï
µØÀí
Сѧ
Êýѧ
Ó¢Óï
ÆäËû
ÔĶÁÀí½â´ð°¸
ÒѻشðÏ°Ìâ
δ»Ø´ðÏ°Ìâ
ÌâÄ¿»ã×Ü
ÊÔ¾í»ã×Ü