ÌâÄ¿ÄÚÈÝ

£¨6·Ö£©Çë»Ø´ðÏÂÁÐÉú»îÖеĻ¯Ñ§ÎÊÌ⣺
£¨1£©È¼ÉÕľ²ñʱ£¬Í¨³£¼Ü¿ÕЩ£¬²ÅÄÜȼÉյøüÍú£¬ÆäʵÖÊÊÇ        ¡£
A£®É¢ÈȵÄËٶȼӿìB£®Ôö´óľ²ñÓë¿ÕÆøµÄ½Ó´¥Ãæ»ý
C£®Ä¾²ñµÄ×Å»ðµã½µµÍD£®Ìá¸ß¿ÕÆøÖÐÑõÆøµÄº¬Á¿
£¨2£©Å©´åÐí¶à¼ÒÍ¥ÓÃÕÓÆø×÷ȼÁÏ£¬ÕÓÆøµÄÖ÷Òª³É·ÖÊÇ         £¬Ëü·¢ÉúȼÉÕʱµÄ»¯Ñ§·½³ÌʽΪ                        ¡£
£¨3£©³´²Ëʱ£¬²»Ð¡ÐÄÓ͹ø×Å»ðÁË£¬¿ÉѸËÙÓùø¸Ç¸ÇÃ𣬸ÃÃð»ðµÄÔ­ÀíÊÇ      ¡£
£¨4£©Ï´Íëʱ£¬¼Ó¼¸µÎÏ´µÓ¼Á¿É³ýÈ¥ÍëÅÌÉϵÄÓÍ×Õ£¬ÕâÊÇÀûÓÃÁËÏ´µÓ¼ÁµÄ     ¹¦ÄÜ¡£
£¨1£©B     £¨2£©CH4»ò¼×Í飻 CH4 + 2O2CO2 + 2H2O
£¨3£©¸ô¾ø¿ÕÆø»òÑõÆø£¨4£©È黯
£¨1£©´Ù½ø¿ÉȼÎïȼÉյķ½·¨Ö÷ÒªÓУºÔö´ó¿ÉȼÎïÓëÑõÆøµÄ½Ó´¥Ãæ»ý¡¢Ôö´óÑõÆøµÄŨ¶È£»È¼ÉÕľ²ñʱ£¬Í¨³£¼Ü¿ÕЩ£¬²ÅÄÜȼÉյøüÍú£¬ÊDzÉÓÃÁ˵ÚÒ»ÖÖ·½·¨¡£¹ÊÑ¡
£¨2£©ÕÓÆøµÄÖ÷Òª³É·ÖÊǼ×Í飬ȼÉյĻ¯Ñ§·½³ÌʽΪ£ºCH4 + 2O2CO2 + 2H2O£»£¨3£©Óùø¸ÇÃð»ð£¬ÊÇÈÿÉȼÎï¸ô¾øÑõÆø£¨»ò¿ÕÆø£©£»£¨4£©ÓͲ»ÄÜÈܽâÔÚË®ÖУ¬µ«ÔÚÏ´½à¾«µÈÕâÖÖ±íÃæ»îÐÔ¼ÁµÄ×÷ÓÃÏ£¬¿ÉÒÔ½«ÍëÉϵÄÓÍÏ´È¥£¬ÕâÊôÓÚÈ黯ÏÖÏó¡£ÊÇÀûÓÃÁËÏ´µÓ¼ÁµÄÈ黯¹¦ÄÜ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø