ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿¸ù¾ÝÏÂÁÐ×°ÖÃͼ£¬»Ø´ðÓйØÎÊÌ⣺

£¨1£©Í¼ÖбêºÅÒÇÆ÷µÄÃû³Æ£º¢Ù_______£¬¢Ú_______¡£

£¨2£©ÀûÓÃÉÏͼÖÐA¡¢D×°ÖõÄ×éºÏ¿ÉÒÔÖÆȡijÖÖÆøÌ壬ʵÑéÊÒÖÆÈ¡¸ÃÆøÌåµÄ»¯Ñ§·½³ÌʽÊÇ_______£¬ÑéÂú·½·¨ÊÇ_______________¡£

£¨3£©ÀûÓÃÉÏͼÖÐB¡¢F×°ÖõÄ×éºÏÖÆÈ¡ÑõÆø£¬µ±BÖв»ÔÙðÆøÅÝʱ·¢ÏÖ¼¯ÆøÆ¿Öл¹ÓÐÉÙÁ¿Ë®£¬ÔÚ²»Ìí¼ÓÒ©Æ·µÄÇé¿öϲÉÈ¡_______________·½·¨Ê¹¼¯ÆøÆ¿ÄÚÊÕ¼¯ÂúÑõÆø¡£

£¨4£©ÊµÑéÊÒͨ³£ÀûÓÃÉÏͼÖÐ×°ÖÃBÓë______µÄ×éºÏÖÆÈ¡¶þÑõ»¯Ì¼£¨Ñ¡Ìî×Öĸ£©£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________¡£ÈôÓÃC×°ÖôúÌæB×°ÖýøÐÐʵÑ飬ÓŵãΪ_______¡£

¢ÙΪÁ˵õ½´¿¾»¡¢¸ÉÔïµÄ¶þÑõ»¯Ì¼ÆøÌ壬³ýÔÓ×°Öã¨Èçͼ£©µÄµ¼¹Ü°´ÆøÁ÷·½ÏòÁ¬½Ó˳ÐòÊÇ_______£¨Ñ¡Ìî×Öĸ£©¡£

A a¡úb¡úd¡úc B b¡úa¡úc¡úd C d¡úc¡úa¡úb D c¡úd¡úb¡úa

¢Ú³£ÓóÎÇåʯ»ÒË®¼ìÑé¶þÑõ»¯Ì¼µÄ´æÔÚ£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________________¡£

¡¾´ð°¸¡¿¾Æ¾«µÆ Ë®²Û 2KMnO4K2MnO4+MnO2+O2¡ü ½«´ø»ðÐǵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬¹Û²ìľÌõÊÇ·ñ¸´È¼£¬¸´È¼ÔòÖ¤Ã÷ÒѼ¯Âú Ïò³¤¾±Â©¶·ÖмÓË® D CaCO3 +2HCl=CaCl2 +H2O +CO2¡ü ¿ØÖÆ·´Ó¦µÄ·¢ÉúºÍÍ£Ö¹ C CO2+Ca(OH)2=CaCO3¡ý+H2O

¡¾½âÎö¡¿

£¨1£©¢ÙÊǾƾ«µÆ£¬³£ÓÃ×÷ÈÈÔ´£»¢ÚÊÇË®²Û£¬³£ÓÃÓÚÊÕ¼¯ÆøÌå¡£¹ÊÌ¾Æ¾«µÆ£»Ë®²Û¡£

£¨2£©ÀûÓÃÉÏͼÖÐA¡¢D×°ÖõÄ×éºÏ¿ÉÒÔÖÆȡijÖÖÑõÆø£¬ÊµÑéÊÒÖÆÈ¡ÑõÆøµÄ»¯Ñ§·½³ÌʽÊÇ£º2KMnO4K2MnO4+MnO2+O2¡ü£»ÑéÂú·½·¨ÊÇ°Ñ´ø»ðÐǵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬Èç¹û´ø»ðÐǵÄľÌõ¸´È¼£¬ËµÃ÷ÒѾ­ÊÕ¼¯Âú¡£

£¨3£©ÀûÓÃÉÏͼÖÐB¡¢F×°ÖõÄ×éºÏÖÆÈ¡ÑõÆø£¬µ±BÖв»ÔÙðÆøÅÝʱ·¢ÏÖ¼¯ÆøÆ¿Öл¹ÓÐÉÙÁ¿Ë®£¬ÔÚ²»Ìí¼ÓÒ©Æ·µÄÇé¿öϲÉÈ¡Ïò³¤¾±Â©¶·ÖмÓË®µÄ·½·¨Ê¹¼¯ÆøÆ¿ÄÚÊÕ¼¯ÂúÑõÆø¡£

£¨4£©¶þÑõ»¯Ì¼µÄÃܶȱȿÕÆø´ó£¬ÄÜÈÜÓÚË®ÇÒÓëË®·´Ó¦£¬Ó¦ÓÃÏòÉÏÅÅ¿ÕÆø·¨ÊÕ¼¯£¬¹ÊʵÑéÊÒͨ³£ÀûÓÃÉÏͼÖÐ×°ÖÃBÓëDµÄ×éºÏÖÆÈ¡¶þÑõ»¯Ì¼£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCO3 +2HCl=CaCl2 +H2O +CO2¡ü¡£ÔËÓÃC×°ÖÃÖƱ¸ÆøÌåµÄ×î´óÌصãÊÇÄÜʹ·´Ó¦Ëæʱ½øÐлòÍ£Ö¹¡£

¢ÙΪÁ˵õ½´¿¾»¡¢¸ÉÔïµÄ¶þÑõ»¯Ì¼ÆøÌ壬³ýÔÓ×°Öõĵ¼¹Ü°´ÆøÁ÷·½ÏòÁ¬½Ó˳ÐòÊÇ£ºÍ¨¹ýdµ¼¹Ü½øÈë±¥ºÍ̼ËáÇâÄÆÈÜÒºÖУ¬³ýÈ¥ÂÈ»¯ÇâÆøÌ壬´Ócµ¼¹Üµ¼³ö£¬ÔÙͨ¹ýaµ¼¹Ü½øÈëŨÁòËáÖУ¬³ýȥˮÕôÆø£¬´Óbµ¼¹Üµ¼³ö£¬¹ÊÌC¡£

¢Ú¶þÑõ»¯Ì¼Í¨Èë³ÎÇåʯ»ÒË®ÖÐʯ»ÒË®±ä»ë×Ç£¬·´Ó¦µÄ·½³ÌʽΪ£ºCO2+Ca(OH)2=CaCO3¡ý+H2O¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿Ä³¹¤³§²úÉúµÄ·ÏÔüÖ÷Òª³É·ÖÊǺ¬¸ÆµÄ»¯ºÏÎï(ÔÓÖÊΪFe2O3)¡£Óø÷ÏÔüÖÆÈ¡CaCl2¾§Ìå(CaCl2¡¤xH2O)²¢½øÐÐ×é³É²â¶¨£¬ÆäÖÆÈ¡µÄÁ÷³ÌÈçÏÂͼËùʾ£º

ÒÑÖª£ºNH4ClÈÜÒºÏÔËáÐÔ£¬ÇÒŨ¶ÈÔ½¸ßËáÐÔԽǿ

(1)XRDͼÆ׿ÉÓÃÓÚÅжÏij¹Ì̬ÎïÖÊÊÇ·ñ´æÔÚ¡£ÓÒͼΪìÑÉÕÇ°ºó·ÏÔüµÄXRDͼÆס£Ð´³öìÑÉÕʱ·¢ÉúµÄ»¯Ñ§·´Ó¦·½³Ìʽ________________________________¡£

(2)½þȡʱÐèÁ¬Ðø½Á°è£¬ÆäÄ¿µÄÊÇ_________________£»Éú³ÉµÄNH3ÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±ä____________É«¡£

(3)ÔÚÆäËüÌõ¼þÏàͬµÄÇé¿öÏ£¬CaCl2µÄ²úÂÊËæ½þȡζȵı仯ÈçÏÂͼËùʾ¡£ÔòÒËÑ¡ÔñµÄ½þȡζÈΪ____________¡æ×óÓÒ¡£

(4)ÈôʹÓùýÁ¿Å¨¶È½Ï¸ßµÄNH4ClÈÜÒº£¬ÔòËùµÃCaCl2ÈÜÒºÖлẬÓÐNH4Cl¡¢_______(Ìѧʽ)µÈÔÓÖÊ¡£

(5)¹ýÂ˵õ½µÄFe2O3ÔÚ¸ßÎÂÏ¿ÉÓëCO·´Ó¦£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ____________¡£

(6)²â¶¨¾§Ìå(CaCl2¡¤xH2O)µÄ×é³É£º

a.³ÆÈ¡14.7000g CaCl2¾§ÌåÓÚ׶ÐÎÆ¿ÄÚ£¬¼ÓÈëÊÊÁ¿ÕôÁóË®.ʹÆäÈ«²¿Èܽ⡣

b.ÔÙÏòÆäÖмÓÈë×ãÁ¿µÄNa2CO3ÈÜÒº£¬¾²Öá£

C.¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿£¬µÃµ½10.0000g¹ÌÌå¡£

¢Ùͨ¹ý¼ÆË㣬ȷ¶¨xµÄÖµ(д³ö¼ÆËã¹ý³Ì)¡£______________________¡£

¢ÚÅжϲ½ÖèbÖгÁµíÍêÈ«µÄ·½·¨ÊÇ£º¾²Öã¬ÏòÉϲãÇåÒºÖеμÓ__________£¬Ôò˵Ã÷ÒѳÁµíÍêÈ«£»Èô³Áµí²»ÍêÈ«£¬Ôò²âµÃµÄxÖµ±Èʵ¼ÊÖµ______(Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡° ²»±ä¡±¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø