ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÉÕ±ÖÐ×°ÓÐÒ»¶¨Á¿ÁòËáºÍÁòËá͵ĻìºÏÈÜÒº£¬ÒÑÖª¸ÃÈÜÒºÖк¬H2SO4µÄÖÊÁ¿Îª9.8g£®Ä³Í¬Ñ§Îª²â¶¨¸Ã»ìºÏÈÜÒºÖÐÁòËá͵ÄÖÊÁ¿£¬ÏòÉÕ±ÖÐÖð½¥¼ÓÈë10%µÄNaOHÈÜÒº£¬µÃµ½³ÁµíµÄÖÊÁ¿¼Ç¼ÈçÏ£º
¼ÓÈëNaOHÈÜÒºµÄÖÊÁ¿/g | 50.0 | 100.0 | 150.0 | 200.0 | 250.0 |
Éú³É³ÁµíµÄÖÊÁ¿/g | 0.0 | 2.5 | 8.6 | 9.8 | 9.8 |
£¨1£©¸Ã»ìºÏÈÜÒºÖÐÁòËá͵ÄÖÊÁ¿Îªg£®
£¨2£©²Î¼Ó·´Ó¦µÄNaOHÈÜÒºµÄ×ÜÖÊÁ¿ÊǶàÉÙ£¿
¡¾´ð°¸¡¿
£¨1£©16
£¨2£©½â£ºÉèÓëÁòËá·´Ó¦µÄNaOHµÄÖÊÁ¿Îªy£¬ÓëCuSO4·´Ó¦µÄNaOHµÄÖÊÁ¿Îªz£®
H2SO4+2NaOH=Na2SO4+2H2O
98 80
9.8g y
y=8.0g
CuSO4+2NaOH=Cu£¨OH£©2¡ý+Na2SO4
80 98
z 9.8g
z=8g
¹Ê²Î¼Ó·´Ó¦µÄNaOHÈÜÒºµÄÖÊÁ¿¹²Îª =160g
¡¾½âÎö¡¿½â£º£¨1£©ÓɼǼÊý¾Ý±í¿ÉÖª£¬ÖÁÁòËáÍÍêÈ«·´Ó¦¹²Éú³ÉÀ¶É«³Áµí9.8g£»
ÉèÈÜÒºÖÐÁòËá͵ÄÖÊÁ¿Îªx
CuSO4+2NaOH=Na2SO4+Cu£¨OH£©2¡ý
160 98
x 9.8g
x=16g
ÏòÁòËáºÍÁòËá͵ĻìºÏÈÜÒºµÎ¼ÓÇâÑõ»¯ÄÆÈÜÒº£¬ÁòËá¡¢ÁòËáͶ¼¿ÉÓëÇâÑõ»¯ÄÆ·¢Éú·´Ó¦£¬ÓÉÓÚÁòËáµÄ´æÔÚÇâÑõ»¯ÄÆÓëÁòËáͲ»ÄÜÉú³ÉÇâÑõ»¯Í³Áµí£¬´ýÁòËá·´Ó¦Íê²ÅÄܲúÉúÇâÑõ»¯Í³Áµí£»ËùÒԼǼÊý¾ÝÖУ¬¼ÓÈë50.0gÇâÑõ»¯ÄÆÈÜҺʱ²úÉú³ÁµíµÄÖÊÁ¿Îª0£»¶øÔÚ¼ÓÈëÇâÑõ»¯ÄÆÈÜÒº200.0gÒÔºó³ÁµíÖÊÁ¿²»Ôٱ仯£¬ËµÃ÷ÁòËáÍÒ²ÒÑÍêÈ«·´Ó¦£¬¹ÊÉú³É³ÁµíÁ¿×î´óֵΪ9.8g£»
¸ù¾ÝÁòËáÍÓëÇâÑõ»¯ÄÆ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬ÓɳÁµíÇâÑõ»¯ÍµÄÖÊÁ¿¿É¼ÆËã»ìºÏÈÜÒºÖÐÁòËá͵ÄÖÊÁ¿£»
ÀûÓÃÓëÁòËá¼°ÁòËáÍ·´Ó¦µÄÇâÑõ»¯ÄƵÄÖÊÁ¿ºÍÓëÇâÑõ»¯ÄÆÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýµÄ±È¿É¼ÆËã²Î¼ÓÇâÑõ»¯ÄÆÈÜÒºµÄÖÊÁ¿£®
¡¾¿¼µã¾«Îö¡¿ÕÆÎÕ¸ù¾Ý»¯Ñ§·´Ó¦·½³ÌʽµÄ¼ÆËãÊǽâ´ð±¾ÌâµÄ¸ù±¾£¬ÐèÒªÖªµÀ¸÷ÎïÖʼäÖÊÁ¿±È=ϵÊý¡ÁÏà¶Ô·Ö×ÓÖÊÁ¿Ö®±È£®