ÌâÄ¿ÄÚÈÝ

£¨2013?·¬Ø®Çøһģ£©ÈçͼÊÇij¹¤³§Éú²úÉÕ¼îµÄÖ÷ÒªÁ÷³Ì£®

£¨1£©XµÄ»¯Ñ§Ê½Îª
H2O
H2O
£®
£¨2£©¸Ã³§Éú²ú¹ý³ÌÖÐìÑÉÕÁ˺¬Ì¼Ëá¸Æ75%µÄʯ»Òʯ12t£¬ÀíÂÛÉÏ¿ÉÖƵÃÑõ»¯¸Æ
5.04
5.04
t£®
£¨3£©×ãÁ¿µÄAÓë´¿¼îÔÚ·´Ó¦³ØÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Ca£¨OH£©2+Na2CO3¨TCaCO3¡ý+2NaOH
Ca£¨OH£©2+Na2CO3¨TCaCO3¡ý+2NaOH
£®
£¨4£©½á¾§µÃµ½µÄ¹ÌÌåÉռ¾­²â¶¨º¬ÓÐÇâÑõ»¯ÄƵÄÖÊÁ¿·ÖÊýΪ99.2%£¬»¹º¬µÄÉÙÁ¿µÄÔÓÖÊ£¬ÔÓÖÊÊÇ
Na2CO3
Na2CO3
£¬Ô­ÒòÊÇ
NaOHÈÜÒºÔÚ¹ýÂË¡¢Õô·¢¡¢½á¾§¹ý³ÌÖÐÎüÊÕÁË¿ÕÆøÖеÄCO2ÆøÌå
NaOHÈÜÒºÔÚ¹ýÂË¡¢Õô·¢¡¢½á¾§¹ý³ÌÖÐÎüÊÕÁË¿ÕÆøÖеÄCO2ÆøÌå
£®
£¨5£©ÂËÒº2ÖеÄÈÜÖʵĻ¯Ñ§Ê½Îª
Ca£¨OH£©2
Ca£¨OH£©2
£¬ÎªÁ˽µµÍÉú²ú³É±¾ºÍ·ÀÖ¹¶Ô»·¾³Ôì³ÉÎÛȾ£¬ÄãµÄ½¨ÒéÊÇ
½«ÂËÒºCa£¨OH£©2ÖØÐÂ×¢Èëµ½·´Ó¦³ØÖÐÑ­»·ÀûÓÃ
½«ÂËÒºCa£¨OH£©2ÖØÐÂ×¢Èëµ½·´Ó¦³ØÖÐÑ­»·ÀûÓÃ
£®
·ÖÎö£º£¨1£©¸ù¾ÝÖÆÈ¡ÉÕ¼îµÄÔ­Àí¿ÉÒÔÖªµÀ£¬ËùÐèÔ­ÁÏΪÇâÑõ»¯¸ÆºÍ̼ËáÄÆ£¬ËùÒÔ¿ÉÒÔÖªµÀXΪˮ£¬Éúʯ»ÒÓëË®·´Ó¦ºóÉú³ÉÁËÇâÑõ»¯¸Æ£¬¿ÉÒԾݴ˽â´ð¸ÃÌ⣻
£¨2£©¸ù¾Ý̼Ëá¸Æ·Ö½âµÄ»¯Ñ§·½³Ìʽ¿ÉÒÔ¼ÆËã³ö¿ÉÒÔÖƵõÄÑõ»¯¸ÆµÄÖÊÁ¿£»
£¨3£©¸ù¾Ý£¨1£©ÖеķÖÎö¿ÉÒÔÖªµÀ£¬·´Ó¦Éú³ÉµÄAΪÇâÑõ»¯¸Æ£¬ÇâÑõ»¯¸ÆºÍ̼ËáÄÆ·´Ó¦Éú³ÉÁË̼Ëá¸ÆºÍÇâÑõ»¯ÄÆ£¬¿ÉÒԾݴËд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£»
£¨4£©ÇâÑõ»¯ÄÆÒ×ÓÚ¿ÕÆøÖеĶþÑõ»¯Ì¼·¢Éú·´Ó¦£¬ËùÒÔÔÚÇâÑõ»¯ÄÆÖлá»ìÓÐ̼ËáÄÆ£¬¿ÉÒԾݴ˽â´ð¸ÃÌ⣻
£¨5£©¸ù¾Ý·´Ó¦¹ý³Ì¿ÉÒÔÖªµÀÄܹ»ÈÜÓÚµÄÂËÔüÖ»ÓÐÇâÑõ»¯¸Æ£¬ËùÒÔ¿ÉÒÔÅжÏÂËÒº2ÖеÄÈÜÖÊΪÇâÑõ»¯¸Æ£¬¶øÇâÑõ»¯¸Æ¿ÉÒÔÖظ´ÀûÓ㬿ÉÒԾݴ˽â´ð¸ÃÌ⣮
½â´ð£º½â£º£¨1£©¸ù¾ÝÖÆÈ¡ÉÕ¼îµÄÔ­Àí¿ÉÒÔÖªµÀ£¬ËùÐèÔ­ÁÏΪÇâÑõ»¯¸ÆºÍ̼ËáÄÆ£¬ËùÒÔ¿ÉÒÔÖªµÀXΪˮ£¬Éúʯ»ÒÓëË®·´Ó¦ºóÉú³ÉÁËÇâÑõ»¯¸Æ£¬Ë®µÄ»¯Ñ§Ê½Îª£ºH2O£»
£¨2£©12tʯ»ÒʯÖк¬ÓеÄ̼Ëá¸ÆµÄÖÊÁ¿Îª£º12t¡Á75%=9t£»
Éè¿ÉÒÔÖƵõÄÑõ»¯¸ÆµÄÖÊÁ¿Îªx
CaCO3
 ìÑÉÕ 
.
 
 CaO+CO2¡ü
100          56
9t           x
100
9t
=
56
x

½âµÃ£ºx=5.04t
£¨3£©¸ù¾Ý£¨1£©ÖеķÖÎö¿ÉÒÔÖªµÀ£¬·´Ó¦Éú³ÉµÄAΪÇâÑõ»¯¸Æ£¬ÇâÑõ»¯¸ÆºÍ̼ËáÄÆ·´Ó¦Éú³ÉÁË̼Ëá¸ÆºÍÇâÑõ»¯ÄÆ£¬¿ÉÒԾݴËд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCa£¨OH£©2+Na2CO3¨TCaCO3¡ý+2NaOH£»
£¨4£©NaOHÈÜÒºÔÚ¹ýÂË¡¢Õô·¢¡¢½á¾§¹ý³ÌÖÐÎüÊÕÁË¿ÕÆøÖеÄCO2£¬Óë¿ÕÆøÖеĶþÑõ»¯Ì¼·¢Éú·´Ó¦£¬ËùÒÔÔÚÇâÑõ»¯ÄÆÖлá»ìÓÐ̼ËáÄÆ£»
£¨5£©¸ù¾Ý·´Ó¦¹ý³Ì¿ÉÒÔÖªµÀÄܹ»ÈÜÓÚµÄÂËÔüÖ»ÓÐÇâÑõ»¯¸Æ£¬ËùÒÔ¿ÉÒÔÅжÏÂËÒº2ÖеÄÈÜÖÊΪÇâÑõ»¯¸Æ£¬¶øÇâÑõ»¯¸ÆÊÇÖÆÈ¡ÇâÑõ»¯ÄƵÄÔ­²ÄÁÏ£¬¿ÉÒÔÖظ´ÀûÓã®
¹Ê´ð°¸Îª£º£¨1£©H2O£»
£¨2£©5.04£»
£¨3£©Ca£¨OH£©2+Na2CO3¨TCaCO3¡ý+2NaOH£»
£¨4£©Na2CO3£»NaOHÈÜÒºÔÚ¹ýÂË¡¢Õô·¢¡¢½á¾§¹ý³ÌÖÐÎüÊÕÁË¿ÕÆøÖеÄCO2ÆøÌ壻
£¨5£©Ca£¨OH£©2£»½«ÂËÒºCa£¨OH£©2ÖØÐÂ×¢Èëµ½·´Ó¦³ØÖÐÑ­»·ÀûÓã®
µãÆÀ£º½â´ðºÃÕâÀàÌâÄ¿£¬Ê×ÏÈÒªÀí½âºÍÊì¼ÇÎïÖʵÄÏ໥ת»¯ºÍÖƱ¸·½·¨£¬ÒÔ¼°ÓëÖ®Ïà¹ØµÄ֪ʶ£®È»ºó£¬¸ù¾ÝËù¸øµÄʵÑé¡¢ÎÊÌâÇé¾°»òͼ±íÐÅÏ¢µÈ£¬½áºÏËùѧµÄÏà¹Ø֪ʶºÍ¼¼ÄÜ£¬ÒÔ¼°×Ô¼ºµÄÉú²ú»òÉú»î¾­ÑéËùµÃ£¬Ï¸ÖµطÖÎöÌâÒ⣨»òʵÑ顢ͼ±íÐÅÏ¢£©µÈ£¬²¢Ï¸ÐĵØ̽¾¿¡¢ÍÆÀíºó£¬°´ÕÕÌâÄ¿ÒªÇó½øÐÐÈÏÕæµØÑ¡Ôñ»ò½â´ð¼´¿É£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø