ÌâÄ¿ÄÚÈÝ

£¨2010?ÎâÖÐÇø¶þÄ££©Ä³Ð£³õÖл¯Ñ§ÐËȤС×é¶ÔһƿNaOHÈÜÒºÊÇ·ñ±äÖʽøÐÐÁË̽¾¿£®ËûÃÇ´Ó¸ÃÊÔ¼ÁÆ¿ÖÐÈ¡ÏàͬÌå»ýµÄÈÜÒº£¬·Ö±ðÊ¢ÓÚA¡¢B¡¢CÈýÖ§ÊÔ¹ÜÖУ¬½øÐÐÏÂÁÐʵÑ飮
ÊԹܱàºÅ²Ù×÷ÏÖÏ󲿷Öͬѧ½áÂÛ
AµÎÈë×ÏɫʯÈïÈÜÒº______¸ÃNaOHÈÜҺδ±äÖÊ
B¼ÓÈë¹ýÁ¿Ï¡ÑÎËá______¸ÃNaOHÈÜÒºÒѱäÖÊ
CµÎÈë³ÎÇåʯ»ÒË®______¸ÃNaOHÈÜÒºÒѱäÖÊ
£¨1£©ÇëÄãÔÚÉϱí¿Õ¸ñÄÚÌîÉÏÏàÓ¦µÄÏÖÏó£®
£¨2£©BÊÔ¹ÜÄÚÑÎËá±ØÐë¹ýÁ¿µÄÀíÓÉÊÇ______£®
£¨3£©Ð´³öBÊÔ¹ÜÄÚ·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
¢ÙÒ»¶¨·¢ÉúµÄ·´Ó¦______£»
¢Ú¿ÉÄÜ·¢ÉúµÄ·´Ó¦______£®
£¨4£©ÏÔÈ»£¬ËûÃǵÄʵÑé½áÂÛÊÇì¶ÜµÄ£®ÊµÑéÖУ¬¸ù¾Ý______ÊԹܣ¨Ìî¡°A¡±¡¢¡°B¡±»ò¡°C¡±£©µÄÏÖÏóµÃ³öµÄ½áÂÛÊÇ´íÎóµÄ£¬Ô­ÒòÊÇ______£®
¡¾´ð°¸¡¿·ÖÎö£ºÇâÑõ»¯ÄÆÎüÊÕ¿ÕÆøÖжþÑõ»¯Ì¼Éú³É̼ËáÄƶø±äÖÊ£¬Òò´Ë£¬ÈôÇâÑõ»¯ÄÆÈÜÒº±äÖÊÔòÈÜÒºÖÐÓ¦º¬ÓÐ̼ËáÄÆ£»ÀûÓõμÓÑÎËá¹Û²ìÊÇ·ñÓÐÆøÅݷųö»òµÎ¼Ó³ÎÇåʯ»ÒË®ÈÜÒº¹Û²ìÊÇ·ñ³öÏÖ°×É«³ÁµíµÄ·½·¨¿É¼ìÑéÇâÑõ»¯ÄÆÈÜÒºÊÇ·ñ±äÖÊ£®
½â´ð£º½â£º
£¨1£©ÇâÑõ»¯ÄÆÒ×Óë¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦£¬Éú³É̼ËáÄÆ£¬¼ìÑéÊÇ·ñ±äÖÊ£¬Ö÷ÒªÊǼìÑéÊÇ·ñÓÐ̼ËáÄÆÉú³É£»
¢ÙAÊÔ¹ÜÖеμÓ×ÏɫʯÈïÊÔÒº£¬ÒòÈÜÒº³Ê¼îÐÔ£¬ÈÜÒº±äÀ¶£¬²¿·ÖͬѧÈÏΪÈÜҺδ±äÖÊ£»
¢ÚBÊÔ¹ÜÖмÓÈë¹ýÁ¿ÑÎËᣬÏÖÏóΪÓÐÆøÅݲúÉú£¬ÒòΪ̼ËáÄÆÓëÑÎËá·´Ó¦Éú³É¶þÑõ»¯Ì¼£¬ÔòÈÜÒºÒѱäÖÊ£»
¢ÛBÊԹܵμӳÎÇåʯ»ÒË®£¬Óа×É«³ÁµíÉú³É£¬ÒòΪ̼ËáÄÆÓëÇâÑõ»¯¸Æ·´Ó¦Éú³É̼Ëá¸Æ°×É«³Áµí£¬ÔòÈÜÒºÒѱäÖÊ£»
£¨2£©µ±ÑÎËᲿ·Ö±äÖÊʱ£¬¼ÓÈëÉÙÁ¿ÑÎËᣬÑÎËáÖ»ÓëÇâÑõ»¯ÄÆ·´Ó¦£¬¶øÎÞÆøÅÝð³ö£¬Ôò²»Äܿ϶¨ÇâÑõ»¯ÄÆÈÜÒºÊÇ·ñ±äÖÊ£¬ËùÒÔBÊÔ¹ÜÖÐÓ¦¼ÓÈë¹ýÁ¿ÑÎË᣻
£¨3£©ÈôÇâÑõ»¯ÄƱäÖÊÔòBÊÔ¹ÜÖÐËù·¢ÉúµÄ·´Ó¦ÎªÌ¼ËáÄƺÍÑÎËáµÄ·´Ó¦£¬¿ÉÄÜ·¢ÉúµÄÊÇÇâÑõ»¯ÄƺÍÑÎËáµÄ·´Ó¦£¬¿ÉÒÔд³ö»¯Ñ§·½³Ìʽ£»
£¨4£©ÇâÑõ»¯ÄÆÈô±äÖÊÔòÉú³É̼ËáÄÆ£¬¶ø̼ËáÄÆÈÜÒºÒ²³Ê¼îÐÔ£¬Äܹ»ÊÇ×ÏɫʯÈïÊÔÒº±äÀ¶£¬ËùÒÔ½ö½ö¸ù¾ÝÈÜÒº±äÀ¶¾ÍÅж¨ÇâÑõ»¯ÄƱäÖÊÊDz»ºÏÊʵģ®
¹Ê´ð°¸Îª£º
£¨1£©
ÊԹܱàºÅ²Ù×÷ÏÖÏ󲿷Öͬѧ½áÂÛ
AµÎÈë×ÏɫʯÈïÈÜÒºÈÜÒº±äÀ¶¸ÃNaOHÈÜҺδ±äÖÊ
B¼ÓÈë¹ýÁ¿Ï¡ÑÎËáÓÐÆøÅݲúÉú¸ÃNaOHÈÜÒºÒѱäÖÊ
CµÎÈë³ÎÇåʯ»ÒË®Óа×É«³ÁµíÉú³É¸ÃNaOHÈÜÒºÒѱäÖÊ
£¨2£©ÈôÑÎËá²»¹ýÁ¿£¬µ±ÇâÑõ»¯ÄÆÈÜÖʲ¿·Ö±äÖÊʱ£¬ÑÎËáÖ»ÓëÇâÑõ»¯ÄÆ·´Ó¦¶øÎÞÆøÅÝð³ö£¬Ôò²»Äܿ϶¨²»±äÖÊ£»
£¨3£©¢ÙNa2CO3+2HCl=2NaCl+H2O+CO2¡ü£»¢ÚNaOH+HCl=NaCl+H2O£»
£¨4£©A£¬Ì¼ËáÄÆÈÜÒºÒ²ÓмîÐÔ£¬Ò²ÄÜʹ×ÏɫʯÈïÊÔÒº±äÀ¶£®
µãÆÀ£ºÃ÷È·ÈÜÒº±äÖʺóµÄ²úÎÀûÓñäÖʺóËùÐγÉÎïÖÊÓëÔ­ÎïÖÊÐÔÖʲîÒ죬¿É¼ìÑéÎïÖÊÊÇ·ñ±äÖÊ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø