ÌâÄ¿ÄÚÈÝ

ÔĶÁÏÂÁвÄÁÏ£¬Íê³É1¡«2Ì⣮ ±±¾©2008Äê°ÂÔË»á»ð¾æ¡°ÏéÔÆ¡±£¬³¤72 cm£¬ÖØ985 g£¬ÍâÌåÓÃÇᱡ¸ßÆ·ÖÊÂÁºÏ½ðºÍÓÅÖÊÓлú²ÄÁϼӹ¤¶ø³É£¬ÄÚ²¿Ê¹ÓõÄȼÁϱûÍé(C3H8)ȼÉÕʱ¼ä³¤´ï15·ÖÖÓ£¬ÔÚÁã·çËÙÏ»ðÑæ¸ß¶È25 cmÖÁ30 cm£¬È¼ÉÕºó¶Ô»·¾³Ôì³ÉµÄÓ°ÏìС£¬ÌåÏÖÁË¡°ÂÌÉ«°ÂÔË¡±µÄÀíÄ
1£®ÒÔ϶ԡ°ÏéÔÆ¡±ÖÐʹÓõÄÂÁºÏ½ðµÄÐðÊö²»ÕýÈ·µÄÊÇ
[     ]
A£®ÂÁºÏ½ðÊôÓÚ½ðÊô²ÄÁÏ
B£®ÂÁºÏ½ðÊÇÈËÀàÀúÊ·ÉÏʹÓÃ×îÔçµÄºÏ½ð
C£®ÂÁºÏ½ðÖпÉÄܺ¬ÓзǽðÊôÔªËØ
D£®ÂÁºÏ½ð¿ÉÒÔµ¼µçµ¼ÈÈ
2£®±ûÍéȼÉյĻ¯Ñ§·½³ÌʽΪ£ºC3H8+5O23X+4H2O£¬ÔòXµÄ»¯Ñ§Ê½Îª
[     ]
A£®C
B£®CO
C£®CO2
D£®CH4
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2007?ÏÌÄþ£©ÔĶÁÏÂÁвÄÁÏ£º
£¨1£©ÎÒ¹ú¼Æ»®Ê¹Óá°³¤Õ÷ÈýºÅ¼×¡±ÔËÔØ»ð¼ý£¬½«¡°æ϶ð¢ñºÅ¡±ËÍÉÏÔÂÇò£¬ÈÎÎñÖ®Ò»ÊÇ̽²âÔÂÇòÉϷḻµÄº¤-3£¨ÖÊ×ÓÊýΪ2£¬ÖÐ×ÓÊýΪ1£©ÕâÒ»Çå½àÄÜÔ´£®Çë»Ø´ð£º
¢Ù¸ÃÔËÔØ»ð¼ýµÄ¶¯Á¦ÊÇÓɸßÂÈËá泥¨NH4ClO4£©·Ö½âËùÌṩµÄÍê³ÉÆä·Ö½âµÄ»¯Ñ§·½³Ìʽ£º2NH4ClO4
  ¡÷  
.
 
N2
N2
¡ü+Cl2¡ü+4H2O¡ü+2O2¡ü
¢Úë²-3Ô­×ӵĽṹʾÒâͼΪ
B
B


£¨2£©2007Äê4ÔÂ18ÈÕÔÚÎÒÊмÎÓãƼÖÞÍ忪×êµÄÓÍÆø¾®£¬ÓÐÍû´ò¿ªºþ±±ÌìÈ»Æø¿±Ì½µÄоÖÃ棬ΪÎÒÃǽñºóÒÔÆø´úú×÷ȼÁÏÌṩÁ˱£ÕÏ£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÌìÈ»ÆøµÄÖ÷Òª³É·ÖÊǼ×Í飬Íê³ÉÆäȼÉյĻ¯Ñ§·½³Ìʽ£º
CH4+2O2
 µãȼ 
.
 
CO2+2H20
CH4+2O2
 µãȼ 
.
 
CO2+2H20

¢ÚÁоÙÒ»ÌõÌìÈ»ÆøÈ¡´úú×÷ȼÁϵÄÓŵ㣺
¼õÉÙ¶Ô¿ÕÆøÔì³ÉµÄÎÛȾ
¼õÉÙ¶Ô¿ÕÆøÔì³ÉµÄÎÛȾ

¢ÛÌìÈ»ÆøµÚÒ»´Îͨ¹ý¹ÜµÀÊäË͵½Óû§Ê±£¬±ØÐëÏȽ«¹ÜµÀÄÚ×¢ÂúµªÆø£®Ìî³äµªÆøµÄÄ¿µÄÊÇ
Åž¡¹ÜµÀÄڵĿÕÆø£¬·ÀÖ¹±¬Õ¨
Åž¡¹ÜµÀÄڵĿÕÆø£¬·ÀÖ¹±¬Õ¨

¢ÜÌìÈ»Æø±¾ÉíÊÇÒ»ÖÖÎÞÉ«ÎÞζµÄÆøÌ壬µ«ÔÚʹÓÃʱ³£ÔÚÌìÈ»ÆøÖмÓÈëÉÙÁ¿ÓÐÌØÊâÆøζµÄÒÒÁò´¼£®¼ÓÈëÒÒÁò´¼µÄ×÷ÓÃÊÇ
¼°Ê±·¢ÏÖÌìÈ»Æøй¶£¬·ÀÖ¹±¬Õ¨Ê¹ʵķ¢Éú
¼°Ê±·¢ÏÖÌìÈ»Æøй¶£¬·ÀÖ¹±¬Õ¨Ê¹ʵķ¢Éú
£®
ÔĶÁÏÂÁвÄÁÏ£¬Íê³ÉÏÂÁÐ̽¾¿£º
ÕäÖéÔ¼º¬92%µÄCaCO3¡¢4%µÄµ°°×ÖÊ£¨°±»ùËᣩÒÔ¼°Ë®µÈÆäËûÎïÖÊ£®ÒÔÕäÖéÄ¥³ÉµÄÕäÖé·Û¾ßÓа²Éñ¡¢ÃÀÈݵÈÒ½ÓüÛÖµ£®ÑëÊÓ¡¶Ã¿ÖÜÖÊÁ¿±¨¸æ¡·Ôø½Ò¶ÏÖ½ñÊг¡ÉÏ´æÔÚ´óÁ¿ÒÔ°ö¿Ç·Ûð³äµÄÕäÖé·Û£¨ÓÃÇâÑõ»¯ÄÆÈÜҺȥ³ý°ö¿Ç±íÃæµÄÓлúÎÓÃË«Ñõˮȥ³ý±íÃæµÄºÚÉ«Ëصȣ¬È»ºóÄ¥³É·Û¼´¿É£©£®Ä³Ñо¿ÐÔѧϰС×é¶Ô±¾µØµÄÒ»ÖÖÊÐÊÛÕäÖé·Û½øÐÐÁËÒÔÏÂ̽¾¿£®
̽¾¿Ò»£º¸ÃÕäÖé·ÛµÄÖ÷Òª³É·Ö£¨ÎÂÜ°Ìáʾ£º°±»ùËáÓöµ½Å¨ÏõËá²¢¼ÓÈÈ»á³ÊÏÖ»ÆÉ«»òºÚÉ«  £©
ÐòºÅ ʵÑéÄÚÈÝ ÊµÑéÏÖÏó ʵÑé½áÂÛ
¢Ù È¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬µÎ¼ÓÏ¡ÑÎËá ÓдóÁ¿ÆøÅÝÉú³É      ±¾¸ñ²»Ìî
¢Ú Óò¬Ë¿ÕºÈ¡¢ÙÖÐÈÜÒº£¬Ôھƾ«µÆÉÏ×ÆÉÕ »ðÑæΪשºìÉ« ÈÜÒºÖк¬ÓиÆÀë×Ó
¢Û ÁíÈ¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬¼ÓË®³ä·ÖÈܽ⣬µÎ¼Ó
µâË®»òµâ¾Æ
µâË®»òµâ¾Æ
ÎÞÀ¶É«³öÏÖ ÑùÆ·Öв»º¬Óеí·Û
¢Ü ÁíÈ¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬¼ÓË®Èܽ⣬¾²ÖᢹýÂË£¬ÔÚÂËÒºÖмÓÈëÊÊÁ¿Å¨ÏõËᣬ¼ÓÈÈÖÁ·Ð
²úÉú»ÆÉ«¹ÌÌå
²úÉú»ÆÉ«¹ÌÌå
ÑùÆ·Öꬵ°°×·Û
£¨°±»ùËᣩ
£¨1£©Ð¡ÃûÈÏΪ¸ù¾ÝʵÑé¢Ù¡¢¢Ú¿ÉÒÔÍƶÏÑùÆ·ÖÐÒ»¶¨º¬ÓÐ̼Ëá¸Æ£¬Ð¡ÐDz»Í¬ÒâÆä¹Ûµã£®ÎªÁËÈ·ÈÏÑùÆ·Öк¬ÓÐ̼Ëá¸Æ£¬ËûÐèÒª²¹³äÍê³ÉµÄʵÑéÊÇ£¨Ð´³öʵÑé·½·¨ÓëÏÖÏ󣩣º
½«¢ÙÉú³ÉµÄÆøÌåͨÈëÊ¢ÓгÎÇåʯ»ÒË®µÄÊÔ¹ÜÖУ¬±ä»ë×ÇÔòÖ¤Ã÷ÊǺ¬ÓÐ̼Ëá¸Æ
½«¢ÙÉú³ÉµÄÆøÌåͨÈëÊ¢ÓгÎÇåʯ»ÒË®µÄÊÔ¹ÜÖУ¬±ä»ë×ÇÔòÖ¤Ã÷ÊǺ¬ÓÐ̼Ëá¸Æ
£»
£¨2£©¸ù¾ÝÉÏÊöʵÑ飬¿ÉÒÔÅжϸÃÕäÖé·ÛΪ
Õæ
Õæ
£¨Ìî¡°Õ桱»ò¡°¼Ù¡±£©£®
̽¾¿¶þ£º¸ÃÕäÖé·ÛÖÐ̼Ëá¸Æº¬Á¿µÄ²â¶¨
¡¾·½·¨1¡¿Ð¡ÍõÓÃÈçͼ1ËùʾװÖòⶨ¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄº¬Á¿£®ÊµÑé·½°¸ÈçÏ£º

£¨1£©¼ì²é×°ÖÃÆøÃÜÐÔ£º°´Í¼Á¬½Ó×°ºÃÖú󣬽«×¢ÉäÆ÷»îÈû£¨²»¿¼ÂÇ»îÈûµÄĦ²ÁºÍ×ÔÖØ£¬ÏÂͬ£©´Ó¿Ì¶È1mL´¦ÏòÉÏÀ­ÖÁ¿Ì¶È20mL´¦£¬
ËÉ¿ª×¢ÉäÆ÷»îÈû£¬»îÈûÖØлص½1¿Ì¶È´¦
ËÉ¿ª×¢ÉäÆ÷»îÈû£¬»îÈûÖØлص½1¿Ì¶È´¦
£¨Ìî²Ù×÷ºÍÏÖÏ󣩣¬ÔòÆøÃÜÐÔÁ¼ºÃ£®
£¨2£©ÔÚ׶ÐÎÆ¿ÄÚ×°Èë0.4gÉÏÊöÕäÖé·ÛÑùÆ·£¬×¢ÉäÆ÷ÄÚÎüÈë12mLµÄÏ¡ÑÎËᣬÔÙ´ÎÁ¬½Ó×°Öã®
£¨3£©ÓÃÁ¦Ïò׶ÐÎÆ¿ÄÚ×¢ÈëËùÓÐÏ¡ÑÎËᣬ²¢»Î¶¯×¶ÐÎÆ¿£®µ±Ã»ÓÐÆøÅݲúÉúºó£¬¼Ç¼עÉäÆ÷¿Ì¶ÈΪ92mL£®
£¨4£©Êý¾Ý´¦Àí£º¸ÃʵÑé¹ý³ÌÖвúÉúCO2µÄÌå»ýΪ
80
80
mL£¬ÔÙ¸ù¾ÝCO2µÄÃܶȣ¨Ô¼2g/L£©¼ÆËã³öÆäÖÊÁ¿£¬¼ÆËã³ö̼Ëá¸ÆµÄÖÊÁ¿£¬´Ó¶ø¼ÆËã¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄº¬Á¿£®
¡¾·½·¨2¡¿Í¬×éµÄСÃ÷ͬѧÁíÍâÉè¼ÆÁËÒ»Ì××°Öã¬Èçͼ2£®ÊµÑé·½°¸ÈçÏ£º
£¨1£©¼ì²é×°ÖÃÆøÃÜÐÔ£»
£¨2£©ÔÚÓÒͼYÐÎ×°ÖÃ×ó¹ÜÄÚ×°Èë1.1gÉÏÊöÕäÖé·ÛÑùÆ·£¬ÓÒ¹ÜÄÚµ¹ÈëÒ»¶¨Á¿µÄÏ¡ÑÎËᣬÕëͲ£¨¹æ¸ñΪ250mL£©»îÈûÍƵ½µ×²¿£¬ÔÙ´ÎÁ¬½Ó×°Öã®
£¨3£©É跨ʹ×óÓÒÁ½¹ÜÄÚµÄÒ©Æ·»ìºÏ£¬·´Ó¦½áÊøºó¶ÁÈ¡ÕëͲ¶ÁÊýΪ220mL£®
£¨4£©Êý¾Ý´¦Àí£ºÇë¼ÆËã¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£®£¨Ð´³ö¼ÆËã¹ý³Ì£¬×îÖÕ½á¹û±£ÁôСÊýµãºó1λ£®
¸ù¾Ý×¢ÉäÆ÷¶ÁÊýΪ220mL£¬ÔòÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿=0.22L¡Á2g/L=0.44g
ÉèÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO3+2HCl=CaCl2+H2O+CO2¡ü
10044
x 0.44g
100
x
=
44
0.44g

x=1g
Ôò¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý
1g
1.1g
¡Á100%¡Ö90.9%
´ð£ºÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýÊÇ90.9%
¸ù¾Ý×¢ÉäÆ÷¶ÁÊýΪ220mL£¬ÔòÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿=0.22L¡Á2g/L=0.44g
ÉèÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO3+2HCl=CaCl2+H2O+CO2¡ü
10044
x 0.44g
100
x
=
44
0.44g

x=1g
Ôò¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý
1g
1.1g
¡Á100%¡Ö90.9%
´ð£ºÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýÊÇ90.9%

¡¾ÊµÑ鷴˼¡¿
£¨1£©¿¼ÂÇÕëͲµÄÒòËØ£¬ÉÏÊöÁ½¸öʵÑé·½°¸¶ÔÕäÖé·ÛµÄÓÃÁ¿¶àÉÙ±ØÐë×÷ÒªÇóÂð£¿ÎªÊ²Ã´£¿
Èç¹ûÕäÖé·ÛÓÃÁ¿Ì«´ó£¬Éú³ÉµÄÆøÌ峬¹ýÕëͲµÄÈÝÁ¿ÏÞÖÆ£¬ÎÞ·¨²âÁ¿Éú³É¶þÑõ»¯Ì¼µÄÌå»ý
Èç¹ûÕäÖé·ÛÓÃÁ¿Ì«´ó£¬Éú³ÉµÄÆøÌ峬¹ýÕëͲµÄÈÝÁ¿ÏÞÖÆ£¬ÎÞ·¨²âÁ¿Éú³É¶þÑõ»¯Ì¼µÄÌå»ý
£®
£¨2£©¡¾·½·¨2¡¿Öеڣ¨3£©²½ÈçºÎʵÏÖÁ½ÖÖÒ©Æ·µÄ»ìºÏ£¿
½«YÐÎ×°ÖÃÏò×óÇãб£¬Ö±ÖÁʹϡÑÎËáÁ÷Èë×ó±ß¹ÜÄÚÓëÕäÖé·Û³ä·Ö½Ó´¥
½«YÐÎ×°ÖÃÏò×óÇãб£¬Ö±ÖÁʹϡÑÎËáÁ÷Èë×ó±ß¹ÜÄÚÓëÕäÖé·Û³ä·Ö½Ó´¥
£®
£¨3£©Ð¡Ã÷Éè¼ÆµÄ×°ÖÃÓëСÍõ±È£¬ÓкÎÓŵ㣿
²»ÐèÒª¿¼ÂǼÓÈëµÄÑÎËá¶Ô²âÁ¿ÆøÌåÌå»ýµÄÓ°Ï죨»òËáÓëÕäÖé·Û»ìºÏʱ²»»á³öÏÖ³åÈûÏÖÏó»ò·½·¨1¼ÓÈëÑÎËáʱ¿ÉÄÜ»áÁ˳öÏÖ³åÈûÏÖÏó£©
²»ÐèÒª¿¼ÂǼÓÈëµÄÑÎËá¶Ô²âÁ¿ÆøÌåÌå»ýµÄÓ°Ï죨»òËáÓëÕäÖé·Û»ìºÏʱ²»»á³öÏÖ³åÈûÏÖÏó»ò·½·¨1¼ÓÈëÑÎËáʱ¿ÉÄÜ»áÁ˳öÏÖ³åÈûÏÖÏó£©
£¨Ð´³ö1µã¼´¿É£©£®

ÔĶÁÏÂÁвÄÁÏ£¬Íê³ÉÏÂÁÐ̽¾¿£º

ÕäÖéÔ¼º¬92%µÄCaCO3¡¢4%µÄµ°°×ÖÊ£¨°±»ùËᣩÒÔ¼°Ë®µÈÆäËûÎïÖÊ¡£ÒÔÕäÖéÄ¥³ÉµÄÕäÖé·Û¾ßÓа²Éñ¡¢ÃÀÈݵÈÒ½ÓüÛÖµ¡£ÑëÊÓ¡¶Ã¿ÖÜÖÊÁ¿±¨¸æ¡·Ôø½Ò¶ÏÖ½ñÊг¡ÉÏ´æÔÚ´óÁ¿ÒÔ°ö¿Ç·Ûð³äµÄÕäÖé·Û£¨ÓÃÇâÑõ»¯ÄÆÈÜҺȥ³ý°ö¿Ç±íÃæµÄÓлúÎÓÃË«Ñõˮȥ³ý±íÃæµÄºÚÉ«Ëصȣ¬È»ºóÄ¥³É·Û¼´¿É£©¡£Ä³Ñо¿ÐÔѧϰС×é¶Ô±¾µØµÄÒ»ÖÖÊÐÊÛÕäÖé·Û½øÐÐÁËÒÔÏÂ̽¾¿¡£

̽¾¿Ò»£º¸ÃÕäÖé·ÛµÄÖ÷Òª³É·Ö

ÐòºÅ

ʵÑéÄÚÈÝ

ʵÑéÏÖÏó

ʵÑé½áÂÛ

¢Ù

È¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬µÎ¼ÓÏ¡ÑÎËá

ÓдóÁ¿ÆøÅÝÉú³É

     ±¾¸ñ²»Ìî

¢Ú

Óò¬Ë¿ÕºÈ¡¢ÙÖÐÈÜÒº£¬Ôھƾ«µÆÉÏ×ÆÉÕ

»ðÑæΪשºìÉ«

ÈÜÒºÖк¬ÓиÆÀë×Ó

¢Û

ÁíÈ¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬¼ÓË®³ä·ÖÈܽ⣬µÎ¼Ó   

ÎÞÀ¶É«³öÏÖ

ÑùÆ·Öв»º¬Óеí·Û

¢Ü

ÁíÈ¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬¼ÓË®Èܽ⣬¾²ÖᢹýÂË£¬ÔÚÂËÒºÖмÓÈëÊÊÁ¿Å¨ÏõËᣬ¼ÓÈÈÖÁ·Ð

__     

ÑùÆ·Öꬵ°°×·Û

£¨°±»ùËᣩ

£¨1£©Ð¡ÃûÈÏΪ¸ù¾ÝʵÑé¢Ù¡¢¢Ú¿ÉÒÔÍƶÏÑùÆ·ÖÐÒ»¶¨º¬ÓÐ̼Ëá¸Æ£¬Ð¡ÐDz»Í¬ÒâÆä¹Ûµã¡£ÎªÁËÈ·ÈÏÑùÆ·Öк¬ÓÐ̼Ëá¸Æ£¬ËûÐèÒª²¹³äÍê³ÉµÄʵÑéÊÇ£¨Ð´³öʵÑé·½·¨ÓëÏÖÏ󣩣º        £»

£¨2£©¸ù¾ÝÉÏÊöʵÑ飬¿ÉÒÔÅжϸÃÕäÖé·ÛΪ    £¨Ìî¡°Õ桱»ò¡°¼Ù¡±£©¡£

̽¾¿¶þ£º¸ÃÕäÖé·ÛÖÐ̼Ëá¸Æº¬Á¿µÄ²â¶¨

¡¾·½·¨1¡¿Ð¡ÍõÓÃÓÒͼ1ËùʾװÖòⶨ¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄº¬Á¿¡£ÊµÑé·½°¸ÈçÏ£º

£¨1£©¼ì²é×°ÖÃÆøÃÜÐÔ£º°´Í¼Á¬½Ó×°ºÃÖú󣬽«×¢ÉäÆ÷»îÈû£¨²»¿¼ÂÇ»îÈûµÄĦ²ÁºÍ×ÔÖØ£¬ÏÂͬ£©´Ó¿Ì¶È1mL´¦ÏòÉÏÀ­ÖÁ¿Ì¶È20mL´¦£¬  £¨Ìî²Ù×÷ºÍÏÖÏ󣩣¬ÔòÆøÃÜÐÔÁ¼ºÃ¡£

£¨2£©ÔÚ׶ÐÎÆ¿ÄÚ×°Èë0.4gÉÏÊöÕäÖé·ÛÑùÆ·£¬×¢ÉäÆ÷ÄÚÎüÈë12mLµÄÏ¡ÑÎËᣬÔÙ´ÎÁ¬½Ó×°Öá£

£¨3£©ÓÃÁ¦Ïò׶ÐÎÆ¿ÄÚ×¢ÈëËùÓÐÏ¡ÑÎËᣬ²¢»Î¶¯×¶ÐÎÆ¿¡£µ±Ã»ÓÐÆøÅݲúÉúºó£¬¼Ç¼עÉäÆ÷¿Ì¶ÈΪ92mL¡£

£¨4£©Êý¾Ý´¦Àí£º¸ÃʵÑé¹ý³ÌÖвúÉúCO2µÄÌå»ýΪ    mL£¬ÔÙ¸ù¾ÝCO2µÄÃܶȣ¨Ô¼2g/L£©¼ÆËã³öÆäÖÊÁ¿£¬¼ÆËã³ö̼Ëá¸ÆµÄÖÊÁ¿£¬´Ó¶ø¼ÆËã¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄº¬Á¿¡£

¡¾·½·¨2¡¿Í¬×éµÄСÃ÷ͬѧÁíÍâÉè¼ÆÁËÒ»Ì××°Öã¬ÈçÓÒͼ2¡£ÊµÑé·½°¸ÈçÏ£º

£¨1£©¼ì²é×°ÖÃÆøÃÜÐÔ£»

£¨2£©ÔÚÓÒͼYÐÎ×°ÖÃ×ó¹ÜÄÚ×°Èë1.1gÉÏÊöÕäÖé·ÛÑùÆ·£¬ÓÒ¹ÜÄÚµ¹ÈëÒ»¶¨Á¿µÄÏ¡ÑÎËᣬÕëͲ£¨¹æ¸ñΪ250mL£©»îÈûÍƵ½µ×²¿£¬ÔÙ´ÎÁ¬½Ó×°Öá£

£¨3£©É跨ʹ×óÓÒÁ½¹ÜÄÚµÄÒ©Æ·»ìºÏ£¬·´Ó¦½áÊøºó¶ÁÈ¡ÕëͲ¶ÁÊýΪ220mL¡£

£¨4£©Êý¾Ý´¦Àí£ºÇë¼ÆËã¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý¡££¨Ð´³ö¼ÆËã¹ý³Ì£¬×îÖÕ½á¹û±£ÁôСÊýµãºó1λ¡£4·Ö£©

           

¡¾ÊµÑ鷴˼¡¿

£¨1£©¿¼ÂÇÕëͲµÄÒòËØ£¬ÉÏÊöÁ½¸öʵÑé·½°¸¶ÔÕäÖé·ÛµÄÓÃÁ¿¶àÉÙ±ØÐë×÷ÒªÇóÂð£¿ÎªÊ²Ã´£¿

        ¡£

£¨2£©¡¾·½·¨2¡¿Öеڣ¨3£©²½ÈçºÎʵÏÖÁ½ÖÖÒ©Æ·µÄ»ìºÏ£¿    ¡£

£¨3£©Ð¡Ã÷Éè¼ÆµÄ×°ÖÃÓëСÍõ±È£¬ÓкÎÓŵ㣿    £¨Ð´³ö1µã¼´¿É£©¡£

 

ÔĶÁÏÂÁвÄÁÏ£¬Íê³ÉÏÂÁÐ̽¾¿£º

ÕäÖéÔ¼º¬92%µÄCaCO3¡¢4%µÄµ°°×ÖÊ£¨°±»ùËᣩÒÔ¼°Ë®µÈÆäËûÎïÖÊ¡£ÒÔÕäÖéÄ¥³ÉµÄÕäÖé·Û¾ßÓа²Éñ¡¢ÃÀÈݵÈÒ½ÓüÛÖµ¡£ÑëÊÓ¡¶Ã¿ÖÜÖÊÁ¿±¨¸æ¡·Ôø½Ò¶ÏÖ½ñÊг¡ÉÏ´æÔÚ´óÁ¿ÒÔ°ö¿Ç·Ûð³äµÄÕäÖé·Û£¨ÓÃÇâÑõ»¯ÄÆÈÜҺȥ³ý°ö¿Ç±íÃæµÄÓлúÎÓÃË«Ñõˮȥ³ý±íÃæµÄºÚÉ«Ëصȣ¬È»ºóÄ¥³É·Û¼´¿É£©¡£Ä³Ñо¿ÐÔѧϰС×é¶Ô±¾µØµÄÒ»ÖÖÊÐÊÛÕäÖé·Û½øÐÐÁËÒÔÏÂ̽¾¿¡£

̽¾¿Ò»£º¸ÃÕäÖé·ÛµÄÖ÷Òª³É·Ö

ÐòºÅ

ʵÑéÄÚÈÝ

ʵÑéÏÖÏó

ʵÑé½áÂÛ

¢Ù

È¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬µÎ¼ÓÏ¡ÑÎËá

ÓдóÁ¿ÆøÅÝÉú³É

     ±¾¸ñ²»Ìî

¢Ú

Óò¬Ë¿ÕºÈ¡¢ÙÖÐÈÜÒº£¬Ôھƾ«µÆÉÏ×ÆÉÕ

»ðÑæΪשºìÉ«

ÈÜÒºÖк¬ÓиÆÀë×Ó

¢Û

ÁíÈ¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬¼ÓË®³ä·ÖÈܽ⣬µÎ¼Ó  ¡ø 

ÎÞÀ¶É«³öÏÖ

ÑùÆ·Öв»º¬Óеí·Û

¢Ü

ÁíÈ¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±­ÖУ¬¼ÓË®Èܽ⣬¾²ÖᢹýÂË£¬ÔÚÂËÒºÖмÓÈëÊÊÁ¿Å¨ÏõËᣬ¼ÓÈÈÖÁ·Ð

__  ¡ø   

ÑùÆ·Öꬵ°°×·Û

£¨°±»ùËᣩ

£¨1£©Ð¡ÃûÈÏΪ¸ù¾ÝʵÑé¢Ù¡¢¢Ú¿ÉÒÔÍƶÏÑùÆ·ÖÐÒ»¶¨º¬ÓÐ̼Ëá¸Æ£¬Ð¡ÐDz»Í¬ÒâÆä¹Ûµã¡£ÎªÁËÈ·ÈÏÑùÆ·Öк¬ÓÐ̼Ëá¸Æ£¬ËûÐèÒª²¹³äÍê³ÉµÄʵÑéÊÇ£¨Ð´³öʵÑé·½·¨ÓëÏÖÏ󣩣º    ¡ø    £»

£¨2£©¸ù¾ÝÉÏÊöʵÑ飬¿ÉÒÔÅжϸÃÕäÖé·ÛΪ  ¡ø  £¨Ìî¡°Õ桱»ò¡°¼Ù¡±£©¡£

̽¾¿¶þ£º¸ÃÕäÖé·ÛÖÐ̼Ëá¸Æº¬Á¿µÄ²â¶¨

¡¾·½·¨1¡¿Ð¡ÍõÓÃÓÒͼ1ËùʾװÖòⶨ¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄº¬Á¿¡£ÊµÑé·½°¸ÈçÏ£º

£¨1£©¼ì²é×°ÖÃÆøÃÜÐÔ£º°´Í¼Á¬½Ó×°ºÃÖú󣬽«×¢ÉäÆ÷»îÈû£¨²»¿¼ÂÇ»îÈûµÄĦ²ÁºÍ×ÔÖØ£¬ÏÂͬ£©´Ó¿Ì¶È1mL´¦ÏòÉÏÀ­ÖÁ¿Ì¶È20mL´¦£¬ ¡ø £¨Ìî²Ù×÷ºÍÏÖÏ󣩣¬ÔòÆøÃÜÐÔÁ¼ºÃ¡£

£¨2£©ÔÚ׶ÐÎÆ¿ÄÚ×°Èë0.4gÉÏÊöÕäÖé·ÛÑùÆ·£¬×¢ÉäÆ÷ÄÚÎüÈë12mLµÄÏ¡ÑÎËᣬÔÙ´ÎÁ¬½Ó×°Öá£

£¨3£©ÓÃÁ¦Ïò׶ÐÎÆ¿ÄÚ×¢ÈëËùÓÐÏ¡ÑÎËᣬ²¢»Î¶¯×¶ÐÎÆ¿¡£µ±Ã»ÓÐÆøÅݲúÉúºó£¬¼Ç¼עÉäÆ÷¿Ì¶ÈΪ92mL¡£

£¨4£©Êý¾Ý´¦Àí£º¸ÃʵÑé¹ý³ÌÖвúÉúCO2µÄÌå»ýΪ  ¡ø  mL£¬ÔÙ¸ù¾ÝCO2µÄÃܶȣ¨Ô¼2g/L£©¼ÆËã³öÆäÖÊÁ¿£¬¼ÆËã³ö̼Ëá¸ÆµÄÖÊÁ¿£¬´Ó¶ø¼ÆËã¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄº¬Á¿¡£

¡¾·½·¨2¡¿Í¬×éµÄСÃ÷ͬѧÁíÍâÉè¼ÆÁËÒ»Ì××°Öã¬ÈçÓÒͼ2¡£ÊµÑé·½°¸ÈçÏ£º

£¨1£©¼ì²é×°ÖÃÆøÃÜÐÔ£»

£¨2£©ÔÚÓÒͼYÐÎ×°ÖÃ×ó¹ÜÄÚ×°Èë1.1gÉÏÊöÕäÖé·ÛÑùÆ·£¬ÓÒ¹ÜÄÚµ¹ÈëÒ»¶¨Á¿µÄÏ¡ÑÎËᣬÕëͲ£¨¹æ¸ñΪ250mL£©»îÈûÍƵ½µ×²¿£¬ÔÙ´ÎÁ¬½Ó×°Öá£

£¨3£©É跨ʹ×óÓÒÁ½¹ÜÄÚµÄÒ©Æ·»ìºÏ£¬·´Ó¦½áÊøºó¶ÁÈ¡ÕëͲ¶ÁÊýΪ220mL¡£

£¨4£©Êý¾Ý´¦Àí£ºÇë¼ÆËã¸ÃÕäÖé·ÛÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý¡££¨Ð´³ö¼ÆËã¹ý³Ì£¬×îÖÕ½á¹û±£ÁôСÊýµãºó1λ¡£4·Ö£©

     ¡ø      

¡¾ÊµÑ鷴˼¡¿

£¨1£©¿¼ÂÇÕëͲµÄÒòËØ£¬ÉÏÊöÁ½¸öʵÑé·½°¸¶ÔÕäÖé·ÛµÄÓÃÁ¿¶àÉÙ±ØÐë×÷ÒªÇóÂð£¿ÎªÊ²Ã´£¿

   ¡ø     ¡£

£¨2£©¡¾·½·¨2¡¿Öеڣ¨3£©²½ÈçºÎʵÏÖÁ½ÖÖÒ©Æ·µÄ»ìºÏ£¿  ¡ø  ¡£

£¨3£©Ð¡Ã÷Éè¼ÆµÄ×°ÖÃÓëСÍõ±È£¬ÓкÎÓŵ㣿  ¡ø  £¨Ð´³ö1µã¼´¿É£©¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø