ÌâÄ¿ÄÚÈÝ
32¡¢¡°ÉñÖÝÆߺš±·É´¬µÄ³É¹¦·¢ÉäÊÇÎÒ¹úº½ÌìÊÂÒµµÄÓÖÒ»Àï³Ì±®£®½ðÊô¹ýÑõ»¯ÎïµÈ¿É×÷ÓîÖæ·É´¬»òDZˮͧÖеÄÑõÆøÔÙÉú¼Á£¬È磺¹ýÑõ»¯ÄÆ£¨Na2O2£©ÔÚ³£ÎÂÏÂÄÜÓëÈ˺ô³öµÄ¶þÑõ»¯Ì¼·´Ó¦Éú³ÉÑõÆø£¬»¯Ñ§·½³ÌʽΪ£º2Na2O2+2CO2¨T2Na2CO3+O2£®ÎªÁËÑéÖ¤¸Ã·´Ó¦ÖÐÓÐÑõÆø²úÉú£¬Ä³ÐËȤС×éµÄͬѧÉè¼ÆÁËÈçÏÂͼËùʾµÄʵÑ飮
£¨1£©½øÈëBÆ¿µÄÆøÌå¿ÉÄÜÓÐ
£¨2£©BƿװÓÐ×ãÁ¿³ÎÇåʯ»ÒË®£¬ÆäµÄ×÷ÓÃÊÇ
£¨3£©C×°ÖõÄ×÷ÓÃÊÇ
£¨1£©½øÈëBÆ¿µÄÆøÌå¿ÉÄÜÓÐ
ÑõÆøºÍ¶þÑõ»¯Ì¼
£»£¨2£©BƿװÓÐ×ãÁ¿³ÎÇåʯ»ÒË®£¬ÆäµÄ×÷ÓÃÊÇ
³ýȥδ·´Ó¦µôµÄ¶þÑõ»¯Ì¼
£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCO2+Ca£¨OH£©2=CaCO3¡ý+H2O
£®£¨3£©C×°ÖõÄ×÷ÓÃÊÇ
ÊÕ¼¯ÑõÆø
£¬ÎªÁË´ïµ½Õû¸öʵÑéÄ¿µÄ£¬½ÓÏÂÀ´µÄʵÑé¾ßÌå²Ù×÷Êǽ«´ø»ðÐǵÄСľÌõÉìÈ뼯ÆøÆ¿ÖУ®
£®·ÖÎö£ºÔÚ¼ìÑé¶þÑõ»¯Ì¼ÆøÌåʱ£¬¿ÉÓóÎÇåµÄʯ»ÒË®À´½øÐУ®ÔÚ¼ìÑéÑõÆøʱ£¬¿ÉÓôø»ðÐǵÄľÌõÀ´½øÐУ®Èô³ÎÇåµÄʯ»ÒË®±ä»ë×Ç˵Ã÷ÊǶþÑõ»¯Ì¼£¬Èô´ø»ðÐǵÄľÌõ¸´È¼£¬ËµÃ÷¸ÃÆøÌåÊÇÑõÆø£®
½â´ð£º½â£º£¨1£©Òò¶þÑõ»¯Ì¼ÄÜÓë¹ýÑõ»¯ÄÆ·´Ó¦Éú³ÉÑõÆø£¬ËùÒÔÔÚ×°ÖÃBÖпÉÄÜÓеÄÆøÌåΪÑõÆøºÍ¶þÑõ»¯Ì¼£®
£¨2£©B×°ÖÃÖеijÎÇåʯ»ÒË®¼´¿É¼ìÑéBÖÐÊÇ·ñÓжþÑõ»¯Ì¼£¬Ò²¿ÉÎüÊÕÉÙÁ¿µÄ¶þÑõ»¯Ì¼£®
£¨3£©×°ÖÃC£¬¿ÉÓÃÀ´ÊÕ¼¯²úÉúµÄÑõÆø£®Óôø»ðÐǵÄľÌõÀ´¼ìÑ飬ÊÕ¼¯µÄÆøÌåÊÇ·ñÊÇÑõÆø£®
¹Ê´ð°¸Îª£º
£¨1£©ÑõÆø¶þÑõ»¯Ì¼
£¨2£©³ýȥδ·´Ó¦µôµÄ¶þÑõ»¯Ì¼£»CO2+Ca£¨OH£©2=CaCO3¡ý+H2O
£¨3£©ÊÕ¼¯ÑõÆø£»½«´ø»ðÐǵÄСľÌõÉìÈ뼯ÆøÆ¿ÖÐ
£¨2£©B×°ÖÃÖеijÎÇåʯ»ÒË®¼´¿É¼ìÑéBÖÐÊÇ·ñÓжþÑõ»¯Ì¼£¬Ò²¿ÉÎüÊÕÉÙÁ¿µÄ¶þÑõ»¯Ì¼£®
£¨3£©×°ÖÃC£¬¿ÉÓÃÀ´ÊÕ¼¯²úÉúµÄÑõÆø£®Óôø»ðÐǵÄľÌõÀ´¼ìÑ飬ÊÕ¼¯µÄÆøÌåÊÇ·ñÊÇÑõÆø£®
¹Ê´ð°¸Îª£º
£¨1£©ÑõÆø¶þÑõ»¯Ì¼
£¨2£©³ýȥδ·´Ó¦µôµÄ¶þÑõ»¯Ì¼£»CO2+Ca£¨OH£©2=CaCO3¡ý+H2O
£¨3£©ÊÕ¼¯ÑõÆø£»½«´ø»ðÐǵÄСľÌõÉìÈ뼯ÆøÆ¿ÖÐ
µãÆÀ£ºÒò¹ýÑõ»¯ÄÆÄÜÎüÊÕ²úÉúµÄ¶þÑõ»¯Ì¼ÆøÌ壬ËùÒÔÎÒÃÇÔÚº½ÌìÊÂÒµÖлòº½º£ÊÂÒµÖо³£Óõ½£¬¼´¿Éƽºâ¿ÕÆøÖжþÑõ»¯Ì¼µÄº¬Á¿£¬Óֿɵõ½ÎÒÃÇËùÐèµÄÑõÆø£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿