ÌâÄ¿ÄÚÈÝ

£¨5·Ö£©Çëд³ö»¯Ñ§·½³Ìʽ£º
£¨1£©ºìÁ×ÔÚ¿ÕÆøÖÐȼÉÕ£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                 ¡£
£¨2£©¼ÓÈȸßÃÌËá¼ØʹÆä·Ö½â£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                               ¡£
£¨3£©¼ÓÈÈÑõ»¯¹¯Ê¹Æä·Ö½â£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                ¡£
£¨4£©½«ÇâÆøºÍµªÆøÔÚ¸ßΡ¢¸ßѹºÍ´ß»¯¼ÁµÄÌõ¼þϺϳɰ±£¨NH3£©£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                        ¡£
£¨5£©ÔÚ¡°ºê¹Û¡ª¡ªÎ¢¹Û¡ª¡ª·ûºÅ¡±Ö®¼ä½¨Á¢ÁªÏµ£¬ÊÇ»¯Ñ§Ñ§¿ÆÌØÓеÄ˼ά·½Ê½¡£Ä³»¯Ñ§·´Ó¦µÄ΢¹ÛÄ£ÄâʾÒâͼÈçÏ£º

¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                        ¡£
£¨1£©4P+5O22P2O5    £¨2£©2KMnO4K2MnO4+MnO2+O2¡ü      
£¨3£©2HgO 2Hg+O2¡ü £¨4£©N2+3H2  2NH3   
£¨5£©C+H2O¸ßÎÂCO+H2
½â£º£¨1£©ºìÁ×ÔÚ¿ÕÆøÖÐȼÉÕÉú³ÉÎåÑõ»¯¶þÁ×£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ 4P+5O22P2O5
£¨2£©¼ÓÈȸßÃÌËá¼Ø£¬·Ö½âÉú³ÉÃÌËá¼Ø¡¢¶þÑõ»¯Ã̺ÍÑõÆø£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
2KMnO4  K2MnO4+MnO2+O2¡ü 
£¨3£©Ñõ»¯¹¯ÊÜÈÈ·Ö½âÉú³É¹¯ºÍÑõÆø£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2HgO ="===" 2Hg+O2¡ü£®
£¨4£©½«ÇâÆøºÍµªÆøÔÚ¸ßΡ¢¸ßѹºÍ´ß»¯¼ÁµÄÌõ¼þϺϳɰ±£¨NH3£©£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ N2+3H2  2NH3£®
£¨5£©´Ó»¯Ñ§·´Ó¦µÄ΢¹ÛÄ£ÄâʾÒâͼ¿´³ö£¬·´Ó¦ÎïµÄ̼ºÍË®£¬Éú³ÉÎïµÄÒ»Ñõ»¯Ì¼ºÍÇâÆø£¬Ìõ¼þÊǸßΣº
¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇC+H2O¸ßÎÂCO+H2
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø