ÌâÄ¿ÄÚÈÝ
¶ÔʵÑéÊÒÖÆÈ¡CO2·´Ó¦ºóÂËÒºµÄÏà¹Ø̽¾¿
(1)¿é״ʯ»ÒʯºÍÊÊÁ¿Ï¡ÑÎËá·´Ó¦ÖÁÆøÅÝÒݳö²»Ã÷ÏԺ󣬹ýÂË,²âµÃÂËÒºµÄpH=2¡£ÔòÂËÒº³Ê ___________ÐÔ£¬ÂËÒºÖÐËùº¬µÄÖ÷ÒªÀë×ÓÓÐ________________¡£
(2)ÒòºóÐøʵÑéÐèÒª£¬ÏÖÒªÅäÖÆÖÊÁ¿·ÖÊýΪ26.5%µÄ̼ËáÄÆÈÜÒº200g
¢Ù¼ÆË㣺ÐèҪ̼ËáÄƹÌÌåµÄÖÊÁ¿Îª___________g£»Ë®µÄÌå»ýΪ__________mL£¨Ë®µÄÃܶȽüËÆ¿´×÷1g/cm3£©
¢Ú³ÆÁ¿£ºµ÷½ÚÍÐÅÌÌìƽƽºâºó£¬½«__________·ÅÔÚÍÐÅÌÌìƽµÄ×óÅÌ£¬³ÆÁ¿ÆäÖÊÁ¿¡£ È»ºóÔÚÓÒÅÌÌí¼Ó__________¡£×îºó¼Ó̼ËáÄƹÌÌ壬ֱÖÁÌìƽƽºâ¡£
¢ÛÈܽ⣺ÓÃÁ¿Í²Á¿È¡ËùÐèµÄË®£¬µ¹Èë×°ÓÐ̼ËáÄƹÌÌåµÄÉÕ±ÀÓò£Á§°ô____________£¬Ê¹ÆäÈܽ⣬²¢ÀäÈ´ÖÁÊÒΡ£
¢Ü´æ´¢£º°ÑÅäºÃµÄÈÜҺװÈëÊÔ¼ÁÆ¿£¬ÈûºÃÏðƤÈû²¢___________£¬·Åµ½Ö¸¶¨µÄµØ·½¡£
(3)È¡50gÂËÒº£¬ÖðµÎµÎÈëÉÏÊöÅäÖƵÄ̼ËáÄÆÈÜÒº£¬²¢ÓÃpHÊý×Ö̽²âÒÇÁ¬Ðø¼à²â£¬µÃÇúÏßÈçÏÂ[pHΪ×Ý×ø±ê£¬Ê±¼äs(Ãë)Ϊºá×ø±ê]£º
(1)¿é״ʯ»ÒʯºÍÊÊÁ¿Ï¡ÑÎËá·´Ó¦ÖÁÆøÅÝÒݳö²»Ã÷ÏԺ󣬹ýÂË,²âµÃÂËÒºµÄpH=2¡£ÔòÂËÒº³Ê ___________ÐÔ£¬ÂËÒºÖÐËùº¬µÄÖ÷ÒªÀë×ÓÓÐ________________¡£
(2)ÒòºóÐøʵÑéÐèÒª£¬ÏÖÒªÅäÖÆÖÊÁ¿·ÖÊýΪ26.5%µÄ̼ËáÄÆÈÜÒº200g
¢Ù¼ÆË㣺ÐèҪ̼ËáÄƹÌÌåµÄÖÊÁ¿Îª___________g£»Ë®µÄÌå»ýΪ__________mL£¨Ë®µÄÃܶȽüËÆ¿´×÷1g/cm3£©
¢Ú³ÆÁ¿£ºµ÷½ÚÍÐÅÌÌìƽƽºâºó£¬½«__________·ÅÔÚÍÐÅÌÌìƽµÄ×óÅÌ£¬³ÆÁ¿ÆäÖÊÁ¿¡£ È»ºóÔÚÓÒÅÌÌí¼Ó__________¡£×îºó¼Ó̼ËáÄƹÌÌ壬ֱÖÁÌìƽƽºâ¡£
¢ÛÈܽ⣺ÓÃÁ¿Í²Á¿È¡ËùÐèµÄË®£¬µ¹Èë×°ÓÐ̼ËáÄƹÌÌåµÄÉÕ±ÀÓò£Á§°ô____________£¬Ê¹ÆäÈܽ⣬²¢ÀäÈ´ÖÁÊÒΡ£
¢Ü´æ´¢£º°ÑÅäºÃµÄÈÜҺװÈëÊÔ¼ÁÆ¿£¬ÈûºÃÏðƤÈû²¢___________£¬·Åµ½Ö¸¶¨µÄµØ·½¡£
(3)È¡50gÂËÒº£¬ÖðµÎµÎÈëÉÏÊöÅäÖƵÄ̼ËáÄÆÈÜÒº£¬²¢ÓÃpHÊý×Ö̽²âÒÇÁ¬Ðø¼à²â£¬µÃÇúÏßÈçÏÂ[pHΪ×Ý×ø±ê£¬Ê±¼äs(Ãë)Ϊºá×ø±ê]£º
¢Ùд³öAB¶ÎÄÚÓйػ¯Ñ§·½³Ìʽ____________ £¬_______________£¬_______________¡£
¢Úд³öBC¡°Æ½Ì¨¡±¶ÎÏÖÏó____________¡£
¢ÛCD¶ÎÉÏÉýµÄÔÒòÊÇ£º__________________ ¡£
(4)¸ù¾ÝÉÏÊöʵÑé²âµÃµÄÁíÒ»×éÊý¾Ý»æÖƳöÏÂͼ£¨×Ý×ø±êmÊÇʵÑéµÃµ½µÄ³Áµí»òÆøÌåµÄÖÊÁ¿£¬ºá×ø±ê±íʾµÄÊÇ̼ËáÄÆÈÜÒºÖÊÁ¿£©£¬Çë¼ÆËã³öÔÂËÒºÖÐÂÈ»¯¸ÆµÄÖÊÁ¿·ÖÊý¡£
¢Úд³öBC¡°Æ½Ì¨¡±¶ÎÏÖÏó____________¡£
¢ÛCD¶ÎÉÏÉýµÄÔÒòÊÇ£º__________________ ¡£
(4)¸ù¾ÝÉÏÊöʵÑé²âµÃµÄÁíÒ»×éÊý¾Ý»æÖƳöÏÂͼ£¨×Ý×ø±êmÊÇʵÑéµÃµ½µÄ³Áµí»òÆøÌåµÄÖÊÁ¿£¬ºá×ø±ê±íʾµÄÊÇ̼ËáÄÆÈÜÒºÖÊÁ¿£©£¬Çë¼ÆËã³öÔÂËÒºÖÐÂÈ»¯¸ÆµÄÖÊÁ¿·ÖÊý¡£
£¨1£©Ëá £» H+ ¡¢Ca2+¡¢Cl-
£¨2£©¢Ù53 £»147£»¢ÚÉÕ±íÀÂ룻¢Û½Á°è£»¢ÜÌùÉϱêÇ©
£¨3£©¢ÙNa2CO3+2HCl=2NaCl+ H2O+CO2¡ü £»CaCO3+2HCl=CaCl2+H2O+CO2¡ü£»
Na2CO3+CaCl2= CaCO3¡ý+2NaCl £»¢Ú³öÏÖ°×É«³Áµí£»¢Û̼ËáÄÆÈÜÒº³Ê¼îÐÔ£¬¹ýÁ¿µÄ̼ËáÄÆÈÜҺʹÈÜÒº¼îÐÔÔöÇ¿
£¨4£©11.1%
£¨2£©¢Ù53 £»147£»¢ÚÉÕ±íÀÂ룻¢Û½Á°è£»¢ÜÌùÉϱêÇ©
£¨3£©¢ÙNa2CO3+2HCl=2NaCl+ H2O+CO2¡ü £»CaCO3+2HCl=CaCl2+H2O+CO2¡ü£»
Na2CO3+CaCl2= CaCO3¡ý+2NaCl £»¢Ú³öÏÖ°×É«³Áµí£»¢Û̼ËáÄÆÈÜÒº³Ê¼îÐÔ£¬¹ýÁ¿µÄ̼ËáÄÆÈÜҺʹÈÜÒº¼îÐÔÔöÇ¿
£¨4£©11.1%
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿