ÌâÄ¿ÄÚÈÝ
£¨2007?ÆÎÌΪÁ˽¨ÉèÉç»áÖ÷ÒåÐÂÅ©´å£¬ÆÎÌïÊÐÕþ¸®»ý¼«¹ÄÀøÅ©ÃñÐ˽¨ÕÓÆø³Ø£¬²¢¸øÓèÊʵ±µÄ¾¼Ã²¹Öú£®Å©ÃñÀûÓýոѡ¢ÔӲݡ¢ÈËÐó·à±ãµÈ·ÏÆúÎïÔÚÃܱյÄÕÓÆø³ØÖз¢½Í£¬²úÉúÕÓÆø£®ÕÓÆøµÄÖ÷Òª³É·ÖÊǼ×Í飨CH4£©£®
£¨1£©Ð´³ö¼×ÍéÍêȫȼÉյĻ¯Ñ§·½³Ìʽ£º
£¨2£©Å©´åÍƹãÐ˽¨ÕÓÆø³ØµÄÓŵãÓУ¨ÈÎдһµã£©£º
£¨3£©ÎªÁ˳ýÈ¥ÕÓÆøÖÐÓгôζµÄÁò»¯ÇâÆøÌ壨H2S£¬ÆäË®ÈÜÒº³ÆΪÇâÁòËᣩ£¬ÎÒÊÐÕþ¸®Ãâ·ÑΪũÃñ°²×°ÍÑÁòÆ÷£¨ÄÚ×°ÇâÑõ»¯ÄÆ£©£¬Ð´³öÕâÒ»·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
£¨4£©ÎªÁË·ÀÖ¹CH4й©Ôì³ÉΣÏÕ£¬ÓÒͼÖеı¨¾¯Æ÷°²×°ÕýÈ·µÄÊÇ
£¨1£©Ð´³ö¼×ÍéÍêȫȼÉյĻ¯Ñ§·½³Ìʽ£º
CH4+2O2
CO2+2H2O
| ||
CH4+2O2
CO2+2H2O
| ||
£¨2£©Å©´åÍƹãÐ˽¨ÕÓÆø³ØµÄÓŵãÓУ¨ÈÎдһµã£©£º
¸ÄÉÆ»·¾³ÎÀÉú£¬»ò½â¾öÅ©ÃñÉú»îÓÃȼÁÏ£¬»òÌá¸ß·ÊЧ£¬»ò¼õÉÙ²¡³æº¦£¬»ò±ä·ÏΪ±¦£¬»òÌá¸ßÄÜÔ´µÄÀûÓÃÂʵÈ
¸ÄÉÆ»·¾³ÎÀÉú£¬»ò½â¾öÅ©ÃñÉú»îÓÃȼÁÏ£¬»òÌá¸ß·ÊЧ£¬»ò¼õÉÙ²¡³æº¦£¬»ò±ä·ÏΪ±¦£¬»òÌá¸ßÄÜÔ´µÄÀûÓÃÂʵÈ
£¨3£©ÎªÁ˳ýÈ¥ÕÓÆøÖÐÓгôζµÄÁò»¯ÇâÆøÌ壨H2S£¬ÆäË®ÈÜÒº³ÆΪÇâÁòËᣩ£¬ÎÒÊÐÕþ¸®Ãâ·ÑΪũÃñ°²×°ÍÑÁòÆ÷£¨ÄÚ×°ÇâÑõ»¯ÄÆ£©£¬Ð´³öÕâÒ»·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
H2S+2NaOH¨TNa2S+2H2O
H2S+2NaOH¨TNa2S+2H2O
£¨4£©ÎªÁË·ÀÖ¹CH4й©Ôì³ÉΣÏÕ£¬ÓÒͼÖеı¨¾¯Æ÷°²×°ÕýÈ·µÄÊÇ
A
A
£¨Ñ¡Ìî¡°A¡±»ò¡°B¡±£©£®·ÖÎö£º£¨1£©¸ù¾Ý¼×ÍéÍêȫȼÉÕÉú³É¶þÑõ»¯Ì¼ºÍË®½øÐнâ´ð£»
£¨2£©¸ù¾ÝÅ©´åÍƹãÐ˽¨ÕÓÆø³Ø¿ÉÒÔ¸ÄÉÆ»·¾³ÎÀÉú£¬»ò½â¾öÅ©ÃñÉú»îÓÃȼÁÏ£¬»òÌá¸ß·ÊЧ£¬»ò¼õÉÙ²¡³æº¦£¬»ò±ä·ÏΪ±¦£¬»òÌá¸ßÄÜÔ´µÄÀûÓÃÂʵȽøÐнâ´ð£»
£¨3£©¸ù¾ÝÇâÁòËáºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉÁò»¯ÄƺÍË®½øÐнâ´ð£»
£¨4£©¸ù¾Ý¼×ÍéµÄÃܶÈСÓÚ¿ÕÆøµÄÃܶȽøÐнâ´ð£®
£¨2£©¸ù¾ÝÅ©´åÍƹãÐ˽¨ÕÓÆø³Ø¿ÉÒÔ¸ÄÉÆ»·¾³ÎÀÉú£¬»ò½â¾öÅ©ÃñÉú»îÓÃȼÁÏ£¬»òÌá¸ß·ÊЧ£¬»ò¼õÉÙ²¡³æº¦£¬»ò±ä·ÏΪ±¦£¬»òÌá¸ßÄÜÔ´µÄÀûÓÃÂʵȽøÐнâ´ð£»
£¨3£©¸ù¾ÝÇâÁòËáºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉÁò»¯ÄƺÍË®½øÐнâ´ð£»
£¨4£©¸ù¾Ý¼×ÍéµÄÃܶÈСÓÚ¿ÕÆøµÄÃܶȽøÐнâ´ð£®
½â´ð£º½â£º£¨1£©¼×ÍéÍêȫȼÉÕÉú³É¶þÑõ»¯Ì¼ºÍË®£¬»¯Ñ§·½³Ìʽ£ºCH4+2O2
CO2+2H2O£»
£¨2£©Å©´åÍƹãÐ˽¨ÕÓÆø³Ø¿ÉÒÔ¸ÄÉÆ»·¾³ÎÀÉú£¬»ò½â¾öÅ©ÃñÉú»îÓÃȼÁÏ£¬»òÌá¸ß·ÊЧ£¬»ò¼õÉÙ²¡³æº¦£¬»ò±ä·ÏΪ±¦£¬»òÌá¸ßÄÜÔ´µÄÀûÓÃÂʵȣ»
£¨3£©ÇâÁòËáºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉÁò»¯ÄƺÍË®£¬»¯Ñ§·½³Ìʽ£ºH2S+2NaOH¨TNa2S+2H2O£»
£¨4£©¼×ÍéµÄÃܶÈСÓÚ¿ÕÆøµÄÃܶȣ¬ËùÒÔΪÁË·ÀÖ¹CH4й©Ôì³ÉΣÏÕ£¬ÓÒͼÖеı¨¾¯Æ÷°²×°ÔÚÉÏ·½£®
¹Ê´ð°¸Îª£º£¨1£©CH4+2O2
CO2+2H2O£»
£¨2£©¸ÄÉÆ»·¾³ÎÀÉú£¬»ò½â¾öÅ©ÃñÉú»îÓÃȼÁÏ£¬»òÌá¸ß·ÊЧ£¬»ò¼õÉÙ²¡³æº¦£¬»ò±ä·ÏΪ±¦£¬»òÌá¸ßÄÜÔ´µÄÀûÓÃÂʵȣ»
£¨3£©H2S+2NaOH¨TNa2S+2H2O£»
£¨4£©A£®
| ||
£¨2£©Å©´åÍƹãÐ˽¨ÕÓÆø³Ø¿ÉÒÔ¸ÄÉÆ»·¾³ÎÀÉú£¬»ò½â¾öÅ©ÃñÉú»îÓÃȼÁÏ£¬»òÌá¸ß·ÊЧ£¬»ò¼õÉÙ²¡³æº¦£¬»ò±ä·ÏΪ±¦£¬»òÌá¸ßÄÜÔ´µÄÀûÓÃÂʵȣ»
£¨3£©ÇâÁòËáºÍÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉÁò»¯ÄƺÍË®£¬»¯Ñ§·½³Ìʽ£ºH2S+2NaOH¨TNa2S+2H2O£»
£¨4£©¼×ÍéµÄÃܶÈСÓÚ¿ÕÆøµÄÃܶȣ¬ËùÒÔΪÁË·ÀÖ¹CH4й©Ôì³ÉΣÏÕ£¬ÓÒͼÖеı¨¾¯Æ÷°²×°ÔÚÉÏ·½£®
¹Ê´ð°¸Îª£º£¨1£©CH4+2O2
| ||
£¨2£©¸ÄÉÆ»·¾³ÎÀÉú£¬»ò½â¾öÅ©ÃñÉú»îÓÃȼÁÏ£¬»òÌá¸ß·ÊЧ£¬»ò¼õÉÙ²¡³æº¦£¬»ò±ä·ÏΪ±¦£¬»òÌá¸ßÄÜÔ´µÄÀûÓÃÂʵȣ»
£¨3£©H2S+2NaOH¨TNa2S+2H2O£»
£¨4£©A£®
µãÆÀ£º½â´ð±¾ÌâʱҪÕÆÎÕ»¯Ñ§·½³ÌʽµÄÊéд·½·¨¼°Æä½ÚÄÜ»·±£·½ÃæµÄ֪ʶ£¬Ö»ÓÐÕâÑù²ÅÄܶÔÎÊÌâ×ö³öÕýÈ·µÄÅжϣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿