ÌâÄ¿ÄÚÈÝ
£¨2007?³¯ÑôÇøһģ£©ÎªÁ˲ⶨÈ˺ô³öÆøÌåÖÐCO2µÄÌå»ýº¬Á¿£¬»¯Ñ§Ð¡×éµÄͬѧÉè¼ÆÈçÏÂʵÑ飺¢ÙÊÕ¼¯5Lijͬѧºô³öµÄÆøÌåÑùÆ·£»
¢ÚÔÚÆøÌåÑùÆ·ÖмÓÈë¹ýÁ¿µÄ³ÎÇåʯ»ÒË®£¬Õñµ´£¬³ä·Ö·´Ó¦£®
¢Û°Ñ·´Ó¦ºóµÄÈÜҺתÒƵ½ÉÕ±ÖУ¬µÎÈë5%µÄÏ¡ÑÎËᣬµ½²»²úÉúÆøÅÝΪֹ£®²úÉúÆøÌåÌå»ýÓë¼ÓÈëÑÎËáÖÊÁ¿µÄ¹ØϵÈçÈçͼËùʾ£®
Çë»Ø´ðÎÊÌ⣺
£¨1£©¼ÓÈë5gÑÎËáǰûÓвúÉúÆøÌåµÄÔÒò£¿
£¨Óû¯Ñ§·½³Ìʽ±íʾ£©______
£¨2£©¼ÓÈëÑÎËá²úÉúCO2µÄÖÊÁ¿ÊǶàÉÙ¿Ë£¿£¨ÈÜÓÚË®µÄCO2ºöÂÔ²»¼Æ£©
£¨3£©¼ÆËã¸ÃÆøÌåÑùÆ·ÓëËùº¬CO2µÄÌå»ý±È£®£¨³£ÎÂÏÂCO2µÄÃܶÈΪ1.96g/L£©

¡¾´ð°¸¡¿·ÖÎö£º¸ù¾ÝͼÏó¿ÉÖª£¬Ï¡ÑÎËáÏȺ͹ýÁ¿µÄ³ÎÇåʯ»ÒË®·´Ó¦£¬ÔÙºÍ̼Ëá¸Æ·´Ó¦£¬²¢ÄÜ¿´³öºÍÕâÁ½ÖÖÎïÖÊ·´Ó¦µÄÏ¡ÑÎËáµÄÖÊÁ¿£¬¸ù¾Ý²ÎÓë·´Ó¦µÄÏ¡ÑÎËáÖÐÂÈ»¯ÇâµÄÖÊÁ¿¾Í¿ÉÇó³öÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿£®
½â´ð£º½â£º£¨1£©ÓÉÓÚËáÊ×ÏȺͼÉú·´Ó¦£¬ËùÒÔ¼ÓÈë5gÑÎËáǰûÓвúÉúÆøÌ壬¹Ê´ð°¸Îª£ºCa£¨OH£©2+2HCl=CaCl2+2H2O
£¨2£©É裺²úÉúCO2µÄÖÊÁ¿Îªx
2HCl+CaCO3=CaCl2+H2O+CO2¡ü
73 44
£¨19.6g-5g£©×5% x
=
x=
=0.44g
£¨3£©VCO2=0.44g÷1.96g/L=0.22L
VÑùÆ·£ºVCO2=
=
´ð£ºÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª0.44g£¬¸ÃÆøÌåÑùÆ·ÓëËùº¬¶þÑõ»¯Ì¼µÄÌå»ý±ÈÊÇ250£º11£®
µãÆÀ£º±¾ÌâÄѶȲ»ÊǺܴó£¬Ö÷Òª¿¼²éÁËͼÏóºÍÊý¾ÝµØ·ÖÎö¼°¸ù¾Ý»¯Ñ§·½³Ìʽ½øÐмÆË㣬ÅàÑøѧÉúµÄ·ÖÎöÄÜÁ¦ºÍ½â¾öÎÊÌâµÄÄÜÁ¦£®
½â´ð£º½â£º£¨1£©ÓÉÓÚËáÊ×ÏȺͼÉú·´Ó¦£¬ËùÒÔ¼ÓÈë5gÑÎËáǰûÓвúÉúÆøÌ壬¹Ê´ð°¸Îª£ºCa£¨OH£©2+2HCl=CaCl2+2H2O
£¨2£©É裺²úÉúCO2µÄÖÊÁ¿Îªx
2HCl+CaCO3=CaCl2+H2O+CO2¡ü
73 44
£¨19.6g-5g£©×5% x


x=

£¨3£©VCO2=0.44g÷1.96g/L=0.22L
VÑùÆ·£ºVCO2=


´ð£ºÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª0.44g£¬¸ÃÆøÌåÑùÆ·ÓëËùº¬¶þÑõ»¯Ì¼µÄÌå»ý±ÈÊÇ250£º11£®
µãÆÀ£º±¾ÌâÄѶȲ»ÊǺܴó£¬Ö÷Òª¿¼²éÁËͼÏóºÍÊý¾ÝµØ·ÖÎö¼°¸ù¾Ý»¯Ñ§·½³Ìʽ½øÐмÆË㣬ÅàÑøѧÉúµÄ·ÖÎöÄÜÁ¦ºÍ½â¾öÎÊÌâµÄÄÜÁ¦£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2007?³¯ÑôÇøһģ£©Ä³ÐËȤС×éÔÚ̽¾¿ÎïÖÊȼÉÕµÄÌõ¼þʱ£¬ÓÃÒ»¸ö¼¯ÆøÆ¿ÕÖסȼ×ŵÄСÀ¯Öò£¬Ð¡À¯ÖòÒ»»á¶ùϨÃðÁË£®ËüΪʲô»áϨÃðÄØ£¿Ã¿¸öÈËÌá³öÁ˲»Í¬µÄ²ÂÏ룮
¡¾Ìá³ö²ÂÏë¡¿

´ó¼ÒÌÖÂÛºóºÜÄÑ´ï³ÉÒ»Ö£¬ÓÚÊÇÉè¼ÆÁËÈçÏÂËùʾµÄʵÑé×°Ö㬲¢½øÐÐʵÑéÀ´ÑéÖ¤£®
¡¾ÊµÑéÉè¼Æ¼°ÑéÖ¤¡¿
¡¾ÊµÑ鷴˼¡¿
¢ÙÔÚʵÑéÖУ¬Éúʯ»ÒµÄÖ÷Òª×÷ÓÃÊÇ______£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£®
¢ÚʵÑé½áÊøºó£¬×¶ÐÎÆ¿µ×²¿µÄ¹ÌÌåÖÐÒ»¶¨º¬ÓеijɷÖÊÇ______£®
¡¾Ìá³ö²ÂÏë¡¿

´ó¼ÒÌÖÂÛºóºÜÄÑ´ï³ÉÒ»Ö£¬ÓÚÊÇÉè¼ÆÁËÈçÏÂËùʾµÄʵÑé×°Ö㬲¢½øÐÐʵÑéÀ´ÑéÖ¤£®
¡¾ÊµÑéÉè¼Æ¼°ÑéÖ¤¡¿
ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé·ÖÎö | ʵÑé½áÂÛ |
£¨1£©È¡Ò»Ð¡¿é°×Á×£¨×Å»ðµã40¡æ£©£¬·ÅÔÚÒ»ÂÁ²ÖƵÄСºÐÖУ¬È»ºó·ÅÈë×°ÓÐÉúʯ»ÒµÄ׶ÐÎÆ¿ÄÚ£¬µãȼÀ¯Öò£¬¹Û²ìÏÖÏó | ȼÉÕµÄÀ¯ÖòÒ»»á¶ù¾ÍϨÃðÁË | Á×ȼÉÕÐèÂú×ãµÄÌõ¼þ£º¢Ùζȴﵽ×Å»ðµã£» ¢Ú______ | ²ÂÏëÕýÈ·µÄͬѧÊÇ______ |
£¨2£©´ýÀäÈ´ºó£¬´ò¿ª·ÖҺ©¶·»îÈû£¬Ïò׶ÐÎÆ¿ÖÐ×¢ÈëÉÙÁ¿µÄË®£¬Á¢¼´¹Ø±Õ»îÈû£¬¹Û²ìÏÖÏó | ÂÁºÐÖеİ×Á×ȼÉÕ£¬·Å³öÈÈÁ¿µÄͬʱ²úÉúÁË______ |
¢ÙÔÚʵÑéÖУ¬Éúʯ»ÒµÄÖ÷Òª×÷ÓÃÊÇ______£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£®
¢ÚʵÑé½áÊøºó£¬×¶ÐÎÆ¿µ×²¿µÄ¹ÌÌåÖÐÒ»¶¨º¬ÓеijɷÖÊÇ______£®
