ÌâÄ¿ÄÚÈÝ

ϱíÊý¾ÝÊÇÔÚijζÈÏ£¬½ðÊôþºÍÄø£¨Ni£©·Ö±ðÔÚÑõÆøÖнøÐÐÑõ»¯·´Ó¦Ê±£¬ÔÚ½ðÊô±íÃæÉú³ÉÑõ»¯±¡Ä¤µÄʵÑé¼Ç¼£º
·´Ó¦Ê±¼ä/h1491625
MgO²ãºñ/nm0.05a0.2a0.45a0.8a1.25a
NiO²ãºñ/nmb2b3b4b5b
×¢£ºaºÍb¾ùΪÓëζÈÓйصij£Êý£¬nm±íʾ¡°ÄÉÃס±
Çë»Ø´ð£º
MgÓëNi±È½Ï£¬ÄÄÒ»ÖÖ¸üÒ×Ñõ»¯£¿    £¬ÆäÀíÓÉÊÇ    £®
Èç¹ûÓÃY±íʾÑõ»¯±¡Ä¤²ãºñ£¬ÓÃt±íʾÐγÉÑõ»¯±¡Ä¤²ãºñËùÐèʱ¼ä£¬YºÍtµÄ¹Øϵ·Ö±ðΪ    £¬    £®
¡¾´ð°¸¡¿·ÖÎö£º¸ù¾ÝÌâ¸ÉÌṩµÄÐÅÏ¢½øÐзÖÎö£¬±í¸ñÖеÄÊý¾Ý±íÃ÷Ëæ×Åʱ¼äµÄÔö¶à£¬½ðÊô±íÃæµÄÑõ»¯ÎﱡĤԽÀ´Ô½ºó£¬µ«ÊÇÔö¼ÓµÄËÙ¶ÈÔÚ²»¶ÏµÄ¼õÂý£¬¸ù¾Ýºñ¶ÈµÄ±ä»¯¼´¿ÉµÃµ½Ñõ»¯ËٶȵĿìÂý£®
½â´ð£º½â£º¿ªÊ¼Ê±Ñõ»¯Ã¾ºñ¶ÈÔö¼ÓµÄËÙ¶ÈΪ£º=4£¬¶øÑõ»¯Äøºñ¶ÈÔö¼ÓµÄËÙ¶ÈΪ£º=2£¬ËùÒÔþ±ÈÄø¸üÈÝÒ×Ñõ»¯£¬ËùÒÔ±¾Ìâ´ð°¸Îª£ºMg£¬Ñõ»¯Ã¾ºñ¶ÈÔö¼ÓµÄËٶȱÈÑõ»¯Äø¿ì£»
¸ù¾Ý±íÖÐÊý¾Ý¿ÉÒÔ¿´³ö£¬Ê±¼äΪ1ʱ£¬Ñõ»¯Ã¾Ôö¼Óºñ¶ÈΪ0.05a£¬ËùÒÔYÓëtµÄ¹ØϵΪY=0.05at£¬Ñõ»¯ÄøÔö¼ÓµÄºñ¶ÈΪb£¬Ê±¼äΪ4ʱ£¬Ñõ»¯ÄøµÄºñ¶ÈΪ2b£¬ËùÒÔYÓëtµÄ¹ØϵΪY=b£¬ËùÒÔ±¾Ìâ´ð°¸Îª£ºY=0.05at£¬Y=b£®
µãÆÀ£º±¾Ì⿼²éÁ˽ðÊôÑõ»¯µÄËٶȣ¬Íê³É´ËÌ⣬¿ÉÒÔÒÀ¾Ý±í¸ñÌṩµÄÐÅÏ¢£¬¸ù¾ÝÒÑÓеÄ֪ʶ½øÐУ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø