ÌâÄ¿ÄÚÈÝ

ÏÖÓÐA¡¢B¡¢C¡¢DËÄÖÖÔªËØ£¬AÔªËصÄÔ­×Óʧȥһ¸öµç×Óºó½öÊ£Ò»¸öÖÊ×Ó£¬BÔªËØÊÇÈËÌåÖк¬Á¿×î¶àµÄÔªËØ£¬CÔªËØÊǵؿÇÖк¬Á¿×î¶àµÄ½ðÊôÔªËØ£¬DÔªËØÓÐÈý¸öµç×Ӳ㣬×îÍâ²ãÓÐ7¸öµç×Ó£¬º¬A¡¢B¡¢CÈýÖÖÔªËØ×é³ÉµÄÒ»ÖÖ»¯ºÏÎïµÄÒ©Îï¿ÉÓÃÀ´ÖÎÁÆθËá¹ý¶à¡£Ôò£ºAÔªËصÄÃû³ÆÊÇ      £¬BÔªËصķûºÅÊÇ       £¬CÔªËصÄÀë×Ó·ûºÅÊÇ      £¬DÔªËص¥ÖʵĻ¯Ñ§Ê½ÊÇ      ¡£Ð´³öB¡¢C×é³ÉµÄ»¯ºÏÎïÓëA¡¢D×é³ÉµÄ»¯ºÏÎïµÄË®ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                     ¡£
Çâ   O    Al3+    Cl2     A2O3+6HCl=2AlCl3+3H2O
AÔªËصÄÔ­×Óʧȥһ¸öµç×Óºó½öÊ£Ò»¸öÖÊ×Ó£¬ËùÒÔAΪÇ⣬BÔªËØÊÇÈËÌåÖк¬Á¿×î¶àµÄÔªËØ£¬ËùÒÔÊÇÑõÔªËØ£¬CÔªËØÊǵؿÇÖк¬Á¿×î¶àµÄ½ðÊôÔªËØ£¬ËùÒÔCÊÇÂÁÔªËØ¡£DÔªËØÓÐÈý¸öµç×Ӳ㣬×îÍâ²ãÓÐ7¸öµç×Ó£¬ÔòDÔªËصÄÔ­×ÓºËÄÚÖÊ×ÓÊýΪ17£¬ËùÒÔDΪÂÈÔªËØ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø