ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿£¨10·Ö£©Ä³¿ÎÍâ»î¶¯Ð¡×éµÄͬѧÓÃÏÂͼËùʾװÖ㬶ÔÑõ»¯Ìú·ÛÄ©(º¬ÉÙÁ¿Ìú·Û)ÑùÆ·½øÐÐʵÑ顣ͼÖÐÌú¼Ų̈µÈ×°ÖÃÒÑÂÔÈ¥¡£Çë»Ø´ðÓйØÎÊÌ⣺

£¨1£©ÊµÑéÄ¿µÄ£º²â¶¨ ¡£

£¨2£©¿ÎÍâ»î¶¯Ð¡×éµÄͬѧÔÚʵÑé²Ù×÷ʱ£¬Ó¦×¢Òâ¼ÓÈÈÇ°ÏÈͨһ»á¶ùÇâÆø£¬Ä¿µÄÊÇ £¬·´Ó¦Íêºó£¬»¹Òª¼ÌÐøͨÇâÆøµ½ÊÔ¹ÜÀäÈ´£¬ÊÇΪÁË ¡£

£¨3£©ÊµÑéÏÖÏóºÍÓйػ¯Ñ§·½³ÌʽÈçÏÂ±í£¨H2µÄ»¯Ñ§ÐÔÖÊÓëCOÏàËÆ£©£ºÇëÍê³É±í¸ñ¡£

ʵÑéÏÖÏó

»¯Ñ§·½³Ìʽ

AÖз´Ó¦²úÉú´óÁ¿ÆøÅÝ£»

AÖУºZn+ H2SO4= ZnSO4+H2¡ü¡£

BÖÐ ·ÛÄ©Öð½¥±äºÚÉ«£»

BÖУº ¡£

£¨4£©ÊµÑéÊý¾Ý¼Ç¼ºÍ´¦Àí£º¾­¹ý¹æ·¶µÄ²Ù×÷ºÍÕýÈ·µÄ³ÆÁ¿£¬µÃµ½ÈçÏÂÁ½×éÊý¾Ý(BÖз´Ó¦ÍêÈ«£¬CÖÐÎüÊÕÍêÈ«)£º

·´Ó¦Ç°

Ñõ»¯ÌúÍêÈ«·´Ó¦ºó

¢Ù×é

B£º²£Á§¹ÜµÄÖÊÁ¿32.4¿Ë Ñõ»¯ÌúÑùÆ·µÄÖÊÁ¿10.0¿Ë

B£º²£Á§¹ÜºÍ¹ÜÄÚ¹ÌÌåÎïÖʵÄÖÊÁ¿40.0¿Ë

¢Ú×é

C£º¸ÉÔï¹ÜºÍÉúʯ»ÒÖÊÁ¿40£®O¿Ë

C£º¸ÉÔï¹ÜºÍ¹ÜÄÚ¹ÌÌåÎïÖʵÄÖÊÁ¿43.0¿Ë

ͨ¹ý¼ÆË㣬ͬѧÃÇ·¢ÏÖ£¬Óõõ½µÄÁ½×éÊý¾ÝÇó³öµÄÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý²»Í¬¡£Äã¾õµÃÓ¦¸ÃÑ¡Ôñ ×éÊý¾Ý¡£ÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊýÊÇ_______¡£

£¨5£©ÎÊÌâºÍÌÖÂÛ£º

¾­¹ýÌÖÂÛ£¬Í¬Ñ§ÃǶÔ×°ÖýøÐÐÁ˸Ľø£¬ÔÚ £¨Ìî2¸ö×°ÖôúºÅ£©Ö®¼äÔö¼ÓÁËÒ»¸öÈçͼËùʾµÄD×°Öã¬ÔÙ´ÎʵÑéºó£¬Óõõ½µÄÁ½×éÊý¾ÝÇó³öµÄÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý»ù±¾Ïàͬ¡£Í¼D×°ÖÃÀïµÄÒºÌåÊÇ ¡£

¡¾´ð°¸¡¿£¨1£©²â¶¨Ñõ»¯Ìú·ÛÄ©ÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý

£¨2£©Åž¡¿ÕÆø£¬·ÀÖ¹¼ÓÈÈʱ·¢Éú±¬Õ¨£¬ ΪÁË·ÀÖ¹¿ÕÆø½øÈëʹÌúÖØб»Ñõ»¯

£¨3£©ºì×ØÉ« 3H2 + Fe2O3 ¸ßΠ2Fe + 3 H2O

£¨4£©¢Ù 80%

£¨5£©A¡¢B ŨH2SO4

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£º£¨1£©ÊµÑéÄ¿µÄ£º²â¶¨²â¶¨Ñõ»¯Ìú·ÛÄ©ÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý

£¨2£©ÓÉÓÚÇâÆø¾ßÓпÉȼÐÔ£¬µ±ÇâÆø²»´¿Ê±£¬Óöµ½Ã÷»ð»ò¸ßοÉÄÜ·¢Éú±¬Õ¨£¬¹ÊÔÚʵÑé²Ù×÷ʱ£¬Ó¦×¢Òâ¼ÓÈÈÇ°ÏÈͨһ»á¶ùÇâÆø£¬Ä¿µÄÊÇÅž¡¿ÕÆø£¬·ÀÖ¹¼ÓÈÈʱ·¢Éú±¬Õ¨£¬·´Ó¦Íêºó£¬»¹Òª¼ÌÐøͨÇâÆøµ½ÊÔ¹ÜÀäÈ´£¬ÊÇΪÁË£ºÎªÁË·ÀÖ¹¿ÕÆø½øÈëʹÌúÖØб»Ñõ»¯

£¨3£©×°ÖÃAÖÐÉú³ÉµÄÇâÆø¾ßÓл¹Ô­ÐÔ£¬ÄÜÓëÑõ»¯Ìú·´Ó¦£¬¹ÊBÖеÄʵÑéÏÖÏóʱ£ººì×ØÉ«·ÛÄ©Öð½¥±äºÚÉ«£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º3H2 + Fe2O3 ¸ßΠ2Fe + 3 H2O

£¨4£©Óõõ½µÄÁ½×éÊý¾ÝÇó³öµÄÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý²»Í¬£¬Ô­ÒòÊÇ×°ÖÃCÖеÄÉúʯ»Ò²»½ö»áÎüÊÕ×°ÖÃBÖÐÉú³ÉµÄË®£¬»¹»áÎüÊÕÔ­ÇâÆøÖÐË®·Ö£¬ÕâÑù»áʹˮµÄÖÊÁ¿Æ«´ó£¬´Ó¶ø¼ÆËã³öÀ´µÄÑõ»¯ÌúµÄÖÊÁ¿·ÖÊýҲƫ´ó£¬¹ÊÓ¦¸ÃÑ¡Ôñ¢Ù×éÊý¾ÝÀ´¼ÆË㣬¸ù¾Ý»¯Ñ§·´Ó¦£º3H2 + Fe2O3 ¸ßΠ2Fe + 3 H2O£¬·´Ó¦Ç°ºóµÄÖÊÁ¿²î¼´ÎªFe2O3ÖеÄÑõÔªËصÄÖÊÁ¿£¬¼´=32.4g+10g-40g=2.4g,ÔÙ¸ù¾ÝÔªËØÖÊÁ¿=ÎïÖʵÄÖÊÁ¿¡ÁÔªËصÄÖÊÁ¿·ÖÊý£¬¹Ê¿ÉÉèÑõ»¯ÌúµÄÖÊÁ¿Îªx£¬ÁÐʽΪ£º2.4g=x¡Á48/160¡Á100%£¬x=8g£¬¹ÊÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý=8g/10g¡Á100%=80%

£¨5£©¹ÊÓ¦¶Ô×°ÖýøÐÐÁ˸Ľø£¬ÔÚA¡¢BÖ®¼äÔö¼ÓÁËÒ»¸öÈçͼËùʾµÄD×°Ö㨽«ÇâÆø½øÐиÉÔ£¬ÔÙ´ÎʵÑéºó£¬Óõõ½µÄÁ½×éÊý¾ÝÇó³öµÄÑùÆ·ÖÐÑõ»¯ÌúµÄÖÊÁ¿·ÖÊý»ù±¾Ïàͬ£¬Í¼D×°ÖÃÀïµÄÒºÌåÊÇ Å¨H2SO4

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø