ÌâÄ¿ÄÚÈÝ

ÏÖ´úÉú»îÖУ¬ÈËÃÇÔ½À´Ô½×¢Òâ΢Á¿ÔªËصÄÉãÈ룮Ѫºìµ°°×ÖеÄÌúÊÇÈËÌåÄÚÑõµÄÊäËÍÕߣ¬È±ÌúÒ×»¼Æ¶Ñª£®
£¨1£©ÈçͼÊÇ¡°XX¡±ÅÆÌúÇ¿»¯½´ÓͱêÇ©ÖеÄÒ»²¿·Ö£®¸ù¾ÝʵÑé²âµÃ£¬½´ÓÍÖÐÌúÖ»ÓÐ10%Äܱ»ÈËÌåÎüÊÕ£¬ÒÔijÈËÒ»ÌìʹÓÃ16m L¸Ã½´ÓͼÆË㣬ËûÒ»Ìì´Ó½´ÓÍÖÐÎüÊÕµÄÌúÔªËØÊǶàÉÙºÁ¿Ë£¿
XXÅƽ´ÓÍ
500mL
ÿ100 mL½´ÓÍÖк¬ÌúÓªÑøÌí¼Ó¼Á200mg
ÌúÓªÑøÌí¼Ó¼ÁÖÐÌúÔªËØÖÊÁ¿·ÖÊýΪ8%£¨2£©Ä³Æ¶Ñª»¼Õß³ýÕý³£ÒûʳÎüÊÕÌúÔªËØÍ⣬»¹Ðè·þÓú¬ÌúÔªËصÄijÖÖÒ©ÎÈôÖÎÁÆÒ»¸öÁƳÌÐè²¹³ä1.68gÌúÔªËØ£¬Ôò·þÓÃÒ©ÎïÖеÄÌúÔªËØÏ൱ÓÚÐèÒªÁòËáÑÇÌú¾§Ì壨FeSO4?7H2O£©¶àÉÙ¿Ë£¿[£¨FeSO4?7H2O£©µÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª278]
£¨3£©ÈôÁòËáÑÇÌúÊÇÓÉÌúºÍÏ¡ÁòËá·´Ó¦ÖƵã¬ÒªµÃµ½ÉÏÊöµÄÁòËáÑÇÌú¾§Ì壨FeSO4?7H2O£©£¬Í¬Ê±²úÉú¶àÉÙÉýÇâÆø£¿£¨±ê¿öϦ±H2=0.09g/L£©
·ÖÎö£º£¨1£©¸ù¾Ý±êÇ©ËùʾµÄÊý¾Ý£¬¸ù¾ÝÿºÁÉý½´ÓÍÖк¬Ì¼ÔªËصÄÖÊÁ¿Ò»¶¨Áгö±ÈÀýʽ£¬¼´¿É¼ÆËã³öËûÒ»Ìì´Ó½´ÓÍÖÐÎüÊÕµÄÌúÔªËصÄÖÊÁ¿£»
£¨2£©¸ù¾ÝÌúºÍÁòËáÑÇÌú¾§ÌåµÄÏà¶ÔÖÊÁ¿±ÈµÈÓÚÁ½ÕßµÄʵ¼ÊÖÊÁ¿±ÈÁгö±ÈÀýʽ£¬¼´¿É¼ÆËã³ö·þÓÃÒ©ÎïÖеÄÌúÔªËØÏ൱ÓÚÐèÒªÁòËáÑÇÌú¾§ÌåµÄÖÊÁ¿£»
£¨3£©¸ù¾Ý»¯Ñ§·½³ÌʽºÍÌúµÄÖÊÁ¿£¬¼´¿É¼ÆËã³ö²úÉúÇâÆøµÄÖÊÁ¿£¬È»ºóÔÙ¸ù¾ÝÌå»ý=ÖÊÁ¿¡ÂÃܶȼÆËã¼´¿É£®
½â´ð£º½â£º£¨1£©Éè16mL¸Ã½´ÓÍÖк¬ÌúÔªËØÖÊÁ¿Îªx£®
ÓÉÌâÒâµÃ£º
100mL
200mg¡Á8%
=
16mL
x

½âÖ®µÃ£ºx=2.56mg£¬
¡à´ËÈËÒ»Ìì´Ó½´ÓÍÖÐÎüÊÕµÄÌúÔªËØÖÊÁ¿Îª2.56mg¡Á10%=0.256mg£»
£¨2£©ÉèÐèÒªÁòËáÑÇÌú¾§Ì壨FeSO4?7H2O£©¾§ÌåÖÊÁ¿Îªy£¬
Fe¡«FeSO4?7H2O
56    278
1.68g  y
¡à
56
1.68g
=
278
y

½âÖ®µÃ£ºy=8.34g£»
£¨3£©Éè²úÉúÇâÆøµÄÖÊÁ¿Îªz£¬
Fe+H2SO4=FeSO4+H2¡ü
56            2
1.68g         Z
¡à
56
1.68g
=
2
z

½âÖ®µÃ£ºZ=0.06g£»
±ê¿öÏÂÇâÆøµÄÌå»ý=
0.06g
0.09g/L
=0.67L
£®
´ð£º£¨1£©ËûÒ»Ìì´Ó½´ÓÍÖÐÎüÊÕµÄÌúÔªËØΪ0.256mg£»
£¨2£©·þÓÃÒ©ÎïÖеÄÌúÔªËØÏ൱ÓÚÐèÒªÁòËáÑÇÌú¾§Ì壨FeSO4?7H2O£©8.34g£»
£¨3£©Í¬Ê±²úÉú0.67ÉýÇâÆø£®
µãÆÀ£º±¾ÌâÖ÷Òª¿¼²éѧÉúÔËÓû¯Ñ§·½³Ìʽ½øÐмÆËãµÄÄÜÁ¦£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø