ÌâÄ¿ÄÚÈÝ

ÉúÃüÀë²»¿ªË®£¬±£»¤Ë®×ÊÔ´ÊÇÿλ¹«ÃñÒå²»ÈݴǵÄÔðÈΣ¡
£¨1£©´Ó×é³ÉÉÏ¿´£ºË®ÊÇÓÉ
ÇâÔªËØºÍÑõÔªËØ
ÇâÔªËØºÍÑõÔªËØ
×é³ÉµÄ£®
£¨2£©´Ó±ä»¯ÉÏ¿´£ºË®Í¨Ö±Á÷µç·Ö½â£¬¿ÉÒÔÔÚ
¸º
¸º
¼«Éú³ÉδÀ´×îÀíÏëµÄÄÜÔ´--ÇâÆø£»µç½âË®µÃµ½ÇâÆøºÍÑõÆøµÄÌå»ý±ÈΪ
2£º1
2£º1
£®
£¨3£©´ÓÎÛȾÉÏ¿´£ºÏÂÁÐ×ö·¨ÄÜÔì³ÉË®ÌåÎÛȾµÄÓÐ
AD
AD
£®
A£®¹¤Òµ·Ïˮֱ½ÓÅÅ·Å     B£®¹¤Òµ·ÏÆø´¦Àí´ï±êºóÅÅ·Å
C£®½ûֹʹÓú¬Á×Ï´Ò·۠  D£®´óÁ¿Ê¹ÓÃũҩ¡¢»¯·ÊÌá¸ßÁ¸Ê³²úÁ¿
£¨4£©´Ó¾»»¯ÉÏ¿´£º×ÔÀ´Ë®Éú²ú¹ý³ÌÖг£Ê¹ÓÃ
»îÐÔÌ¿
»îÐÔÌ¿
À´³ýȥˮÖÐÒìζºÍÉ«ËØ£®
£¨5£©Éú»îÖУº¿ÉÒÔ
·ÊÔíË®
·ÊÔíË®
ÓüòÒ×Çø·ÖӲˮºÍÈíË®£»ÒªÏëʹӲˮת»¯ÎªÈíË®³£Óõķ½·¨ÊÇ
Öó·Ð
Öó·Ð
£®
·ÖÎö£º£¨1£©¸ù¾ÝË®µÄ×é³ÉÔªËØ·ÖÎö»Ø´ð£»
£¨2£©¸ù¾Ýµç½âË®µÄʵÑéÏÖÏóºÍ½áÂÛ·ÖÎö»Ø´ð£»
£¨3£©¸ù¾ÝË®µÄÎÛȾԴ·ÖÎö£»
£¨4£©¸ù¾Ý»îÐÔÌ¿µÄÎü¸½ÐÔ·ÖÎö£»
£¨5£©¸ù¾ÝӲˮºÍÈíË®Óë·ÊÔíË®·´Ó¦µÄÏÖÏó²»Í¬¼ø±ð£¬Éú»îÖг£ÓÃÖó·ÐµÄ·½·¨½«Ó²Ë®Èí»¯£®
½â´ð£º½â£º£¨1£©ÎïÖʵÄ×é³ÉÓÃÔªËØÀ´ÃèÊö£¬´Ó×é³ÉÉÏ¿´£ºË®ÊÇÓÉÇâÔªËØºÍÑõÔªËØ×é³ÉµÄ£»
£¨2£©Ë®Í¨Ö±Á÷µç·Ö½â£¬ÔÚ¸º¼«Éú³ÉδÀ´×îÀíÏëµÄÄÜÔ´--ÇâÆø£¬ÔÚÕý¼«ÉÏÉú³ÉÁËÑõÆø£¬ÇâÆøºÍÑõÆøµÄÌå»ý±ÈΪ2£º1£»
£¨3£©A£®¹¤Òµ·Ïˮֱ½ÓÅÅ·Å£¬»áÔì³ÉË®µÄÎÛȾ£»
B£®¹¤Òµ·ÏÆø´¦Àí´ï±êºóÅÅ·Å£¬²»»áÔì³ÉË®µÄÎÛȾ£»
C£®½ûֹʹÓú¬Á×Ï´Ò·ۣ¬²»»áÔì³ÉË®µÄÎÛȾ£»
D£®´óÁ¿Ê¹ÓÃũҩ¡¢»¯·ÊÌá¸ßÁ¸Ê³²úÁ¿£¬»áÔì³ÉË®µÄÎÛȾ£»
£¨4£©»îÐÔÌ¿ÓÐÎü¸½ÐÔ£¬ÔÚ¾»»¯Ë®Ê±£¬³£Ê¹ÓûîÐÔÌ¿À´³ýȥˮÖÐÒìζºÍÉ«ËØ£»
£¨5£©Éú»îÖУº¿ÉÒÔ·ÊÔíË®ÓüòÒ×Çø·ÖӲˮºÍÈíË®£®ÏòË®ÖмÓÈë·ÊÔíË®£¬ÅÝÄ­¶àµÄÊÇÈíË®£¬ÅÝÄ­ÉÙµÄÊÇӲˮ£¬Éú»îÖг£ÓÃÖó·ÐµÄ·½·¨½«Ó²Ë®Èí»¯£®
¹Ê´ðΪ£º£¨1£©ÇâÔªËØºÍÑõÔªËØ£»£¨2£©¸º£¬2£º1£»£¨3£©AD£»£¨4£©»îÐÔÌ¿£»£¨5£©·ÊÔíË®£¬Öó·Ð£®
µãÆÀ£ºË®ÊÇ´ó×ÔÈ»´ÍÓèÈËÀà×îÖØÒªµÄ±¦¹ó×ÊÔ´Ö®Ò»£¬ÎÒÃÇÒ»¶¨ÒªºÃºÃÕäϧ£¬±£»¤Ë®×ÊÔ´£¬½ÚÔ¼ÓÃË®£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
29¡¢Ë®ÊÇÉúÃüÖ®Ô´£¬ÈËÀàµÄÈÕ³£Éú»îÓ빤ũҵÉú²ú¶¼Àë²»¿ªË®£®
£¨1£©Ð¡Ã÷ÔÚ̽¾¿Ë®µÄ×é³Éʱ£¨×°ÖÃÈçͼ¢ÙËùʾ£©£®Í¨µçÒ»¶Îʱ¼äºó£¬ÊÔ¹Ü1ÖÐËùÊÕ¼¯µÄÆøÌåΪ
ÇâÆø
£¬¸ÃʵÑé˵Ã÷Ë®ÊÇÓÉ
ÇâÔªËØºÍÑõÔªËØ
×é³ÉµÄ£®

£¨2£©Ð¡Ã÷Òª¾»»¯ÊÕ¼¯µÄÓêË®£¬×ÔÖÆÁËÒ»¸ö¼òÒ×¾»Ë®Æ÷£¨Èçͼ¢ÚËùʾ£©£¬ÆäÖÐСÂÑʯ¡¢Ê¯Ó¢É³ºÍÅòËÉÃÞµÄ×÷ÓÃÊÇ
¹ýÂ˳ýȥˮÖеIJ»ÈÜÐÔÔÓÖÊ
£®
£¨3£©¿óȪˮ¡¢ÕôÁóË®¡¢×ÔÀ´Ë®ºÍ¾»»¯ºóµÄÓêË®¶¼ÊÇÉú»îÖг£¼ûµÄË®£¬ÄãÈçºÎ¼ø±ðͼ¢ÛÖеÄÁ½Æ¿Ë®
·Ö±ðÈ¡ÉÙÁ¿£¬Õô·¢ºóÎÞ²ÐÁôÎïµÄÊÇÕôÁóË®£¬Óа×ɫӡºÛµÄÊÇ¿óȪˮ£¬£¨ÆäËûºÏÀí´ð°¸Ò²¿É£©
£®
£¨4£©±±¾©ÊÐΪÑÏÖØÈ±Ë®³ÇÊУ¬ÎÒÃÇÒª±£»¤ºÃË®×ÊÔ´£¬ÏÂÁÐ×ö·¨Öв»»áÔì³ÉË®ÎÛȾµÄÊÇ
ABC
£®
A£®Éú»îÎÛˮͨ¹ý¼¯Öд¦ÀíºóÅÅ·Å   B£®½ûÖ¹Óú¬Á×Ï´µÓ¼ÁÏ´µÓ
C£®ÊµÊ©¶ÔũҩºÍ»¯·ÊʹÓÃ¼à¿Ø     D£®ÔÚË®¿âÖܱßÐ˽¨ÔìÖ½³§
£¨5£©Ë®ºøÄÚ±ÚÉϳ£ÓÐË®¹¸£¨Ö÷Òª³É·ÖÊÇ̼Ëá¸ÆºÍÇâÑõ»¯Ã¾£©³Á»ý£¬¿ÉÓÃʳ´×³ýµô£®ÕâÊÇÒòΪʳ´×Öк¬ÓеÄÒÒËᣨCH3COOH£©¾ßÓÐËáÐÔ£¬¿ÉÓë̼Ëá¸ÆºÍÇâÑõ»¯Ã¾·´Ó¦£®ÒÑÖªÒÒËáÓëÇâÑõ»¯Ã¾·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2CH3COOH+Mg£¨OH£©2=£¨CH3COO£©2Mg+2H2O£¬ÔòÒÒËáÓë̼Ëá¸Æ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
2CH3COOH+CaCO3=£¨CH3COO£©2Ca+H2O+CO2¡ü
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø