ÌâÄ¿ÄÚÈÝ

£¨2011ÄêÕã½­º¼ÖÝ£¬ 30Ì⣩ΪÁ˼õÇáËáÓêµÄΣº¦£¬ÎÒ¹úÑз¢ÁË¡°º£Ë®·¨ÑÌÆøÍÑÁò¹¤ÒÕ¡±¡£Æ乤ÒÕÁ÷³Ì´óÖÂÊÇ£º

I¡¢´Ó¸ß´¦ÅçÁÜϵĺ£Ë®(pH=8.1-8.3)Ï´ÍÑ´Ó϶øÉÏȼúÑÌÆøÖеÄSO2, (SO2+H2O=H2SOH2SO3ÊÇÈõËᣩ£¬º£Ë®±äΪÈõËáÐÔ£»

¢ò¡¢.½«Ï´¹ýÑÌÆøºóµÄº£Ë®ÓëÑõÆø³ä·Ö½Ó´¥£¬·¢ÉúÏÂÁз´Ó¦£º

4NaC1£«O2Ê®2H2SO3 ==2Na2SO4£«4HC1

III.ÔÙ½«ÓëÑõÆø³ä·Ö½Ó´¥µÄº£Ë®¸ú´óÁ¿ÌìÈ»º£Ë®»ìºÏµÈ´ëÊ©£¬Ê¹¸÷ÏîÖ¸±ê½Ó½üÌìÈ»º£Ë®ºóÔÙÅÅ·Å¡£

(1)¡¢ÔÚ×ø±êͼÖл­³ö¡°º£Ë®·¨ÑÌÆøÍÑÁò¹¤ÒÕ¡±È«¹ý³ÌÖк£Ë®µÄpHÒÀ´Î±ä»¯´óÖÂÇ÷ÊÆ¡£

(2)¡¢¹¤ÒÕÁ÷³ÌÖÐÌìÈ»º£Ë®½Ó´¥ÑÌÆøºó±äΪÈõËáÐÔ£¬Õâ˵Ã÷Ôڴ˹ý³ÌÖк£Ë®ÖÐµÄ       Àë×ÓºÍH2SO3µçÀë³öµÄÇâÀë×Ó·¢ÉúÁË·´Ó¦¡£

(3)¡¢ÈôÒª²â¶¨º£Ë®ÖÐNa2SO4º¬Á¿£¬ÊµÑé²Ù×÷²½ÖèÊÇ£º

È¡ÉÙÁ¿±»²âº£Ë®£¬²â¶¨            ¡¢¼ÓÈë×ãÁ¿µÄ           ÈÜÒº£¨Ð´»¯Ñ§Ê½£©¡¢ÔÙ¼ÓÈëÏ¡ÏõËá¡¢¹ýÂË¡¢Ï´µÓ¡¢ºæ¸É¡¢³ÆÁ¿³ÁµíÖÊÁ¿¡£

 

(1)Èçͼ

 

 

(2)ÇâÑõ¸ù£¨»òOH-£©

(1) (3) ±»²âº£Ë®ÖÊÁ¿£¨Ìå»ý£©    BaCl2»òBa(N03)3»òBa(OH)2

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨2011ÄêÕã½­º¼ÖÝ£¬38Ì⣩ijѧУ¿ÆѧÐËȤС×éÏëÉè¼ÆÒ»¸öʵÑ飬À´Ä£ÄâÑо¿CO2Ũ¶ÈÔö¼ÓÊÇ·ñÔö´óµØÇò¡°ÎÂÊÒЧӦ¡±¡£ËûÃDzéÔÄÁËÓйØÊý¾Ý£º²¢Éè¼ÆÁËÏÂÃæµÄʵÑéºÍ²Ù×÷²½Ö裺
¢ñ¡¢ÔÚÁ½Ö»Í¬ÑùµÄ²£Á§Æ¿Àï·Ö±ð³äÂúCO2ºÍ¿ÕÆø£¬²¢±àºÅΪ¼×¡¢ÒÒ£¬Èû½ô´øÓÐͬÑùζȼƵÄÏðƤÈû¡£ÔÙ°ÑÁ½Ö»²£Á§Æ¿·ÅÔÚÑô¹âÏÂÕÕÉ䣨ÈçÏÂͼ£©£¬¹Û²ì¼×¡¢ÒÒÆ¿ÖеÄζȱ仯¡£

¢ò¡¢¡¢Ñô¹â³ÖÐøÕÕÉ䣬¼ä¸ôÒ»¶¨Ê±¼ä²âÁ¿Á½²£Á§Æ¿Î¶ÈÖµ£¬²¢¼Ç¼£¨¼ûÏÂ±í£©

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)¡¢Ð´³öʵÑéÊÒÖÆÈ¡CO2µÄ»¯Ñ§·½³Ìʽ                   ¡£
(2)¡¢ÍùÆ¿ÖгäCO2ʱ£¬Ñé֤ƿÖÐÒѳäÂúÁËCO2µÄ·½·¨ÊÇ                               ¡£
(3)¡¢¸ÃʵÑéÖУ¬ÕÕÉäͬÑùʱ¼ä£¬¸ù¾ÝÉϱíµÄÊý¾Ý£¬±È½Ï¼×¡¢ÒÒƿζȱ仯µÄ¹æÂÉÊÇ           
                                                           ¡£
(4)¡¢¸ÃʵÑéÖУ¬ÔÚÑô¹âÕÕÉäÏ£¬Ó°Ïì¼×¡¢ÒÒƿζȲ»Í¬µÄÔ­Òò£¬³ýÁËCO2µÄÎÂÊÒЧӦÒÔÍ⣬»¹ÓеĿÉÄÜÔ­ÒòÊÇ£¨Ð´³öÒ»µã¼´¿É£©                                                  
ͬѧÈÏΪ¸ù¾Ý¸ÃÄ£ÄâʵÑéµÄÄ¿µÄ£¬ÊµÑéÉè¼Æ´æÔÚÎÊÌ⣬ÄãÈÏΪÊÇ£¨Ð´³öÒ»µã¼´¿É£©        
                                                ¡£

£¨2011ÄêÕã½­º¼ÖÝ£¬38Ì⣩ijѧУ¿ÆѧÐËȤС×éÏëÉè¼ÆÒ»¸öʵÑ飬À´Ä£ÄâÑо¿CO2£ºÅ¨¶ÈÔö¼ÓÊÇ·ñÔö´óµØÇò¡°ÎÂÊÒЧӦ¡±¡£ËûÃDzéÔÄÁËÓйØÊý¾Ý£º

²¢Éè¼ÆÁËÏÂÃæµÄʵÑéºÍ²Ù×÷²½Ö裺
¢ñ¡¢ÔÚÁ½Ö»Í¬ÑùµÄ²£Á§Æ¿Àï·Ö±ð³äÂúCO2ºÍ¿ÕÆø£¬²¢±àºÅΪ¼×¡¢ÒÒ£¬Èû½ô´øÓÐͬÑùζȼƵÄÏðƤÈû¡£ÔÙ°ÑÁ½Ö»²£Á§Æ¿·ÅÔÚÑô¹âÏÂÕÕÉ䣨ÈçÓÒͼ£©£¬¹Û²ì¼×¡¢ÒÒÆ¿ÖеÄζȱ仯¡£

¢ò¡¢.Ñô¹â³ÖÐøÕÕÉ䣬¼ä¸ôÒ»¶¨Ê±¼ä²âÁ¿Á½²£Á§Æ¿Î¶ÈÖµ£¬²¢¼Ç¼£¨¼ûÏÂ±í£©

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)¡¢Ð´³öʵÑéÊÒÖÆÈ¡CO2µÄ»¯Ñ§·½³Ìʽ                   ¡£
(2)¡¢ÍùÆ¿ÖгäCO2ʱ£¬Ñé֤ƿÖÐÒѳäÂúÁËCO2µÄ·½·¨ÊÇ                               ¡£
(3)¡¢¸ÃʵÑéÖУ¬ÕÕÉäͬÑùʱ¼ä£¬¸ù¾ÝÉϱíµÄÊý¾Ý£¬±È½Ï¼×¡¢ÒÒƿζȱ仯µÄ¹æÂÉÊÇ           
                                                           ¡£
(4)¡¢¸ÃʵÑéÖУ¬ÔÚÑô¹âÕÕÉäÏ£¬Ó°Ïì¼×¡¢ÒÒƿζȲ»Í¬µÄÔ­Òò£¬³ýÁËCO2µÄÎÂÊÒЧӦÒÔÍ⣬»¹ÓеĿÉÄÜÔ­ÒòÊÇ£¨Ð´³öÒ»µã¼´¿É£©                                                  
                                                  
ÓÐͬѧÈÏΪ¸ù¾Ý¸ÃÄ£ÄâʵÑéµÄÄ¿µÄ£¬ÊµÑéÉè¼Æ´æÔÚÎÊÌ⣬ÄãÈÏΪÊÇ£¨Ð´³öÒ»µã¼´¿É£©        
                                                ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø